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armok01126758

  • Category : Delphi VCL
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  • Update : 2012-11-26
  • Size : 3kb
  • Downloaded :0次
  • Author :m****
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接收到的信号为发送信号的反码因为每检测到按键有效一次PT2262 都发送四次编码我们可以 利用这一特点来解码先检测有没有接收到信息当有的时候我们就去掉第一次编码的信号检测5ms 的 高电平来检测编码的开始信号接收到5ms 的高电平后才开始解码我们可以发现每个码的长度都是1.2ms 左右每一个编码都是由低电平开始然后到高电平又到低电平又回到高电平我们从第一个高电平 的宽度可以把1 码区分出来剩下的悬空码和0 码可以从第二个高电平的宽度区分出来 具体的单片机译码方法如下 由高电平开始检测到下降沿时就延时300us 读取接收的状态记为A0 然后再检测下一个下降沿 降沿后又延时300us 读取接收的状态记为A1 这样就把一个编码给译出来了
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