Fibonacci Series 3 is whether the multiplier issue that if the calculated using recursive F (n), The judgment will then overtime. Notes F (n) = F (n-1) F (n-2) and the modulus and the same model. That is, F (n) = 3% (F (n-1)% F 3 (n-2)% 3)% 3 F (0%) 3 = 1, F (1)% 2 3 = calculated F (n)% 3 : 1,2,0,2,2,1,0,1,1,2,0. 2,2,1 ... ... ... can be seen F (n) 3% to 1,2,0,2,2,1,0,1, repeated F (n) = 0% 3 F (n) 3 is a multiple of n time to 8k or 8k 6 2

Packet : 536078902060.zip filelist
2060.cpp
2060.dsp
2060.dsw
2060.ncb
2060.opt
2060.plg
Debug/
Debug/1733.exe
Debug/1733.ilk
Debug/1733.obj
Debug/1733.pch
Debug/1733.pdb
Debug/2060.exe
Debug/2060.ilk
Debug/2060.obj
Debug/2060.pch
Debug/2060.pdb
Debug/vc60.idb
Debug/vc60.pdb

• We are an exchange download platform that only provides communication channels. The downloaded content comes from the internet. Except for download issues, please Google on your own.
• The downloaded content is provided for members to upload. If it unintentionally infringes on your copyright, please contact us.
• Please use Winrar for decompression tools
• If download fail, Try it againg or Feedback to us.
• If downloaded content did not match the introduction, Feedback to us，Confirm and will be refund.
• Before downloading, you can inquire through the uploaded person information

Nothing．