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Description: 试用时域最小平方误差准则（最小平方逆设计）设计一个具有四项系数的IIR DF的系统函数，使其在y(n)=[3,2,1]输入激励下，输出v(n)逼近d(n)=[2,0.2,0.05]。令v(-1)=v(-2)=0。求出v(n)的前8个样值与d(n)进行比较。用matlab实现了此要求。-trial at the least square error domain guidelines (minimum inverse square design) design with a four DF IIR coefficient of the system function, so in y (n) = [3,2,1] incentive to import, export v (n) approximation d (n) = [2,0.2,0.05]. So v (1) = v (2) = 0. Get v (n) of eight samples value d (n) comparisons. Using Matlab realization of this request.
Platform: |
Size: 822 |
Author: lsd |
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Description: 最小平方反褶积代码。地球物理科学中广泛使用的反褶积方法，使用Matlab语言编写。-least squares deconvolution code. Geophysical Sciences extensive use of deconvolution method, the use of Matlab.
Platform: |
Size: 1070 |
Author: 小刘 |
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Description: 将1、2、3、4、5、6、7、8、9九个数字分成三组，每个数
字只能用一次，即每组三个数不允许有重复数字，也不许同其它
组的三个数字重复，要求每组中的三位数都组成一个平方数。-1,2,3,4,5,6,7,8,9 nine figures will be split into three groups, each number can only be used once, the number three in each group is allowed to repeat the figures and not allowed with other groups to repeat the three figures, each of the requests are triple-digit the formation of a square.
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Size: 1668 |
Author: 姚紫欣 |
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Description: 平方的一个有趣性质
编程验证“大于1000的奇数其平方与1的差是8的倍数”。
*问题分析与算法设计
本题是一个很容易证明的数学定理，我们可以编写程序验证
它。
题目中给出的处理过程很清楚，算法不需要特殊设计。可以
按照题目的叙述直接进行验证(程序中仅验证到3000)。-square interesting nature of a certification program "more than 1,000 of its odd square one with the poor in multiples of eight." * Analysis and design of the algorithm that is a very easy to prove mathematical theorems, we can prepare to verify it. The title of the process is very clear, do not need special algorithm design. According to the topics described in direct certification (validation procedures only to 3000).
Platform: |
Size: 849 |
Author: 姚紫欣 |
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Description: 过JAVA编程产生一系列伪随机数，掌握平方取中法、乘同余法、混合同余法产生均匀随机数的方法。-off Java programming produce a series of pseudo-random numbers, master Mid-square method, I took with the law, mixed with the law I have Random Number method.
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Size: 93074 |
Author: zhangyu |
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Description: VB自制一个支持正弦、余弦、平方、阶乘的数学计算器，还可进行开平方、指数、对数、倒数的运算，虽然功能还不是很强大，但作为自己学习VB的技巧总结，希望能帮助像我水平相当的朋友，也希望高手莫笑话哦。
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Size: 3079 |
Author: 286998253@QQ.COM |
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Description: 代码中给出了图像恢复的最小平方滤波和winner滤波法，并显示其结果图可进行分析比较
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Size: 1249 |
Author: mingmingpudm |
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Description: avr单片机开平方的程序-avr SCM open square procedures! !
Platform: |
Size: 1024 |
Author: 谭玉波 |
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Description: 自己做的程序,可能对你有用-own procedures that may be useful to you
Platform: |
Size: 1024 |
Author: 柏 |
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Description: 过JAVA编程产生一系列伪随机数，掌握平方取中法、乘同余法、混合同余法产生均匀随机数的方法。-off Java programming produce a series of pseudo-random numbers, master Mid-square method, I took with the law, mixed with the law I have Random Number method.
Platform: |
Size: 93184 |
Author: zhangyu |
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Description: 试用时域最小平方误差准则（最小平方逆设计）设计一个具有四项系数的IIR DF的系统函数，使其在y(n)=[3,2,1]输入激励下，输出v(n)逼近d(n)=[2,0.2,0.05]。令v(-1)=v(-2)=0。求出v(n)的前8个样值与d(n)进行比较。用matlab实现了此要求。-trial at the least square error domain guidelines (minimum inverse square design) design with a four DF IIR coefficient of the system function, so in y (n) = [3,2,1] incentive to import, export v (n) approximation d (n) = [2,0.2,0.05]. So v (1) = v (2) = 0. Get v (n) of eight samples value d (n) comparisons. Using Matlab realization of this request.
Platform: |
Size: 1024 |
Author: lsd |
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Description: 用于单片机32bit内的快速开方（C51）-32bit MCU for the rapid evolution (C51)
Platform: |
Size: 2048 |
Author: 孙屠介 |
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Description: 最小平方反褶积代码。地球物理科学中广泛使用的反褶积方法，使用Matlab语言编写。-least squares deconvolution code. Geophysical Sciences extensive use of deconvolution method, the use of Matlab.
Platform: |
Size: 1024 |
Author: 小刘 |
Hits:
Description: 将1、2、3、4、5、6、7、8、9九个数字分成三组，每个数
字只能用一次，即每组三个数不允许有重复数字，也不许同其它
组的三个数字重复，要求每组中的三位数都组成一个平方数。-1,2,3,4,5,6,7,8,9 nine figures will be split into three groups, each number can only be used once, the number three in each group is allowed to repeat the figures and not allowed with other groups to repeat the three figures, each of the requests are triple-digit the formation of a square.
Platform: |
Size: 1024 |
Author: 姚紫欣 |
Hits:
Description: 平方的一个有趣性质
编程验证“大于1000的奇数其平方与1的差是8的倍数”。
*问题分析与算法设计
本题是一个很容易证明的数学定理，我们可以编写程序验证
它。
题目中给出的处理过程很清楚，算法不需要特殊设计。可以
按照题目的叙述直接进行验证(程序中仅验证到3000)。-square interesting nature of a certification program "more than 1,000 of its odd square one with the poor in multiples of eight."* Analysis and design of the algorithm that is a very easy to prove mathematical theorems, we can prepare to verify it. The title of the process is very clear, do not need special algorithm design. According to the topics described in direct certification (validation procedures only to 3000).
Platform: |
Size: 1024 |
Author: 姚紫欣 |
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Description: 本程序用8031汇编语言实现双字节二进制无符号数平方-procedures with the 8031 assembly language to achieve double-byte binary unsigned few square
Platform: |
Size: 3072 |
Author: guorui |
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Description: 实现平方乘算法，简单实用！！！！！！！！(shixiannpingfangchengsuanfa)
Platform: |
Size: 1024 |
Author: 搞错了
|
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Description: 平方解调分析，针对旋转机械故障信号的分析处理(Analysis and analysis of square demodulation for the analysis and processing of fault signals of rotating machinery)
Platform: |
Size: 6311936 |
Author: g-nice |
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Description: 使用matlab编写了最佳平方逼进法的函数，里面有题目，可直接运行计算得到结果。(Matlab prepared using the best square approximation function, which is the problem, can be directly run the calculated results.)
Platform: |
Size: 76800 |
Author: jeff1130 |
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Description: 对DSSS/BPSK信号进行平方倍频法，可以对其载频进行估计(The frequency doubling method of DSSS/BPSK signal can be used to estimate its carrier frequency.)
Platform: |
Size: 7168 |
Author: 飞翔的蜘蛛 |
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