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Description: 多维数组（二维以下和数组）在内存中也是按顺序存放的，因此也可以用这种方式传递。但是，如果要确切知道每个元素在数组中的位置，就应给出各维的最大索引值-multi-dimensional arrays (two-dimensional array and below) in memory is stored sequentially, so you can pass this way. However, if we know exactly each element in the array position, it should be given the largest peacekeeping index
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Size: 7196 |
Author: 王 艳 |
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Description: 简单的事例程序，二分法寻找数组中最大最小元素。-simple example procedures dichotomy for the largest array smallest elements.
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Size: 1172 |
Author: 马宏泉 |
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Description: 输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 程序分析：谭浩强的书中答案有问题。-input array, the largest and one of the elements in the first exchange, and the smallest elements of a final exchange, the output array. Program Analysis : Tan-book answer to a problem.
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Size: 2825 |
Author: 陈明 |
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Description: 多维数组（二维以下和数组）在内存中也是按顺序存放的，因此也可以用这种方式传递。但是，如果要确切知道每个元素在数组中的位置，就应给出各维的最大索引值-multi-dimensional arrays (two-dimensional array and below) in memory is stored sequentially, so you can pass this way. However, if we know exactly each element in the array position, it should be given the largest peacekeeping index
Platform: |
Size: 50176 |
Author: 王 艳 |
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Description: 输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 程序分析：谭浩强的书中答案有问题。-input array, the largest and one of the elements in the first exchange, and the smallest elements of a final exchange, the output array. Program Analysis : Tan-book answer to a problem.
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Size: 2048 |
Author: 陈明 |
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Description: 简单的事例程序，二分法寻找数组中最大最小元素。-simple example procedures dichotomy for the largest array smallest elements.
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Size: 1024 |
Author: 马宏泉 |
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Description: 求数组中最大、次大值
本程序运用了算法思想，如果数据很大的时候，就可以看出本程序的效率了-Array for the largest and second largest value of this procedure to use the algorithm of thought, a lot of time if the data, we can see that the efficiency of this procedure
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Size: 1024 |
Author: lfk |
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Description: 2叉树的方法递归求得求得一组数中最大的数-find the biggest number of a sreious number
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Size: 164864 |
Author: bazi |
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Description: 求数组中最大的一个元素，给出了最简单的一个实例，应运时之需要改变数字即可-calculator the max one
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Size: 1024 |
Author: 杨晓彬 |
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Description: 编写返回数组中最大元素数值的模板函数：
template <class T>
int Max(T Arr[],int n)
-Prepared to return the largest element of the array value template function: template <class T> int Max (T Arr [], int n)
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Size: 4096 |
Author: weiht |
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Description: 题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。
1.程序分析：谭浩强的书中答案有问题。
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Size: 8192 |
Author: xl |
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Description: 找出一个整型数组中的元素的最大值。
这个问题可以不用类的方法来解决，现在用类来处理-Identify the elements of an integer array maximum. This problem can be class methods to solve, and now to deal with class
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Size: 1024 |
Author: 最初的梦想 |
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Description: 找出2*M整形二维数组中最大元素的值，并将此值返回调用函数-To find 2* M plastic two-dimensional array of elements in the largest value and this value is returned to the calling function
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Size: 1024 |
Author: 户佳 |
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Description: 题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。
1.程序分析：谭浩强的书中答案有问题。
2.程序源代码：-Topic: input arrays, and the biggest and the first element exchange, the smallest and the last element exchange, output array.
1. The program analysis: TanHaoJiang book the answer.
2. The source code:
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Size: 2048 |
Author: 崔嬴 |
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Description: 求解数组中最大的数，用C++编程语言编写的，比较简单-Solving the maximum number of array, using C++ programming language, relatively simple
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Size: 1024 |
Author: 孙伟 |
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Description: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.
分析：首先要注意的是，输入数组中可能有重复的点。由于两点确定一条直线，一个很直观的解法是计算每两个点形成的直线，然后把相同的直线合并，最后包含点最多的直线上点的个数就是本题的解。我们知道表示一条直线可以用斜率和y截距两个浮点数（垂直于x轴的直线斜率为无穷大，截距用x截距），同时还需要保存每条直线上的点（避免重复）。听起来就很麻烦，但是基于这个思想有一种简单的实现方式：
以某点O为中心，计算它和其他点的斜率，如果有两个点A、B和O点形成的斜率相等，那么ABO三点是共线的，如果有多个点和O的斜率相等，那么这多个点和O也是共线的，因此我们可以求出包含O的所有直线中点数最多的直线，会得到一个最大共线点数k(O)，如果和O点重复的点有n个（除了O本身），那么K(O) = K(O) + n。这一步的计算中，为了提高效率，我们可以用哈希表来保存某个斜率对应的点的数目。
对数组中的每一个点i，按照第一步计算得到每个点最大点数K(i)
从k(i)中选取最大的就是本题的解
注意：为了避免重复计算，以数组中第i个点为中心时，只计算数组中它右边的所有点-Given n points on a 2D plane, find the maximum number of points that lie on the same straight line analysis: first thing to note is that the input array may have duplicate points. Because two points determine a line, a very intuitive solution is to calculate every two points form a straight line, and then merge the same straight line, the final solution of this problem is to include the number of points on a straight line up to the point. We know that a straight line can be expressed by the slope and y-intercept of the two floating-point (x-axis perpendicular to the slope of the line is infinite, the intercept with the x-intercept), but also need to save the points on each line (to avoid duplication). It sounds very troublesome, but there is a simple way to achieve based on this idea: to a point O as the center, and the slope of the other points to calculate it, and if there are two points A, B and O points form the slope equal, then the ABO three points are collinear, if there are a p
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Size: 1024 |
Author: lb |
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Description: 面试题，找出一个整形数组中第二大的数，标准程序，简洁明了，最受面试官青睐。-the standard process to find out the second biggist number in a matrix when inteviewing.
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Size: 1024 |
Author: 王一二 |
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Description: 数组中的查找和删除数据，最大上限为100，用c语言编写，可直接运行(Array of search and delete data, the maximum limit of 100, written in C language, can be run directly)
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Size: 5120 |
Author: 闻怡
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Description: IDE: VS2015。利用C++动态创建二维数组，并可以求该二维数组中的最大值(Dynamically creating a two-dimensional array)
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Size: 828416 |
Author: 丰宇
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