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Description: ASP高级网 t=0:0.0000002:0.0006 ％ ts=0.2ms 每周期1000点
x1=sin(5000*2*pi.*t) ％ 生成5KHz的正弦波
b=fir1(9,0.01,hanning(10)) ％ 采样频率是100KHz，截止频率为500Hz的9阶汉宁窗生成b系数。
freqz(b,1,512,100000)
y=filter(b,1,x1) ％ 对5KHz正弦波用9阶汉宁窗进行滤波
plot(t,x1,t,y)
仿真结果未见到y被衰减的滤波效果。请高手指点。 络变成编程-ASP t = 0:0.0000002 : ts = 0.0006% per period 1000 EMFs point x1 = sin (5000 * 2 * pi. * t)% 5KHz generation of sine wave b = fir1 (9,0.01. HANNING (10))% is 100KHz sampling frequency, As the frequency of 500Hz nine bands Hanning window Generation b coefficient. Freqz (b, 1,512,100000) y = filter (b, a, x1)% to 5KHz sine wave with nine bands Hanning window filtering plot (t, x, t, y) Simulation results were not seen y attenuation of the filter effect. 19:56 guidance. Tongxinluo into programming
Platform: |
Size: 71520 |
Author: 罗飞腾 |
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Description: Java数据库编程中查询结果的表格式输出
Platform: |
Size: 7154 |
Author: 高兴宁 |
Hits:
Description: 利用循环队列模拟舞伴配对问题：在舞会上，男、女各自排成一队。舞会开始时。依次从男队和女队的队头各出一人配成舞伴。如果两队初始人数不等，则较长的那一队中未配对者等待下一轮舞曲。
Platform: |
Size: 1401 |
Author: 石狼 |
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Description: ASP高级网 t=0:0.0000002:0.0006 ％ ts=0.2ms 每周期1000点
x1=sin(5000*2*pi.*t) ％ 生成5KHz的正弦波
b=fir1(9,0.01,hanning(10)) ％ 采样频率是100KHz，截止频率为500Hz的9阶汉宁窗生成b系数。
freqz(b,1,512,100000)
y=filter(b,1,x1) ％ 对5KHz正弦波用9阶汉宁窗进行滤波
plot(t,x1,t,y)
仿真结果未见到y被衰减的滤波效果。请高手指点。 络变成编程-ASP t = 0:0.0000002 : ts = 0.0006% per period 1000 EMFs point x1 = sin (5000* 2* pi.* t)% 5KHz generation of sine wave b = fir1 (9,0.01. HANNING (10))% is 100KHz sampling frequency, As the frequency of 500Hz nine bands Hanning window Generation b coefficient. Freqz (b, 1,512,100000) y = filter (b, a, x1)% to 5KHz sine wave with nine bands Hanning window filtering plot (t, x, t, y) Simulation results were not seen y attenuation of the filter effect. 19:56 guidance. Tongxinluo into programming
Platform: |
Size: 71680 |
Author: 罗飞腾 |
Hits:
Description: Java数据库编程中查询结果的表格式输出-Java Database Programming query results in table format output
Platform: |
Size: 7168 |
Author: |
Hits:
Description: 利用循环队列模拟舞伴配对问题：在舞会上，男、女各自排成一队。舞会开始时。依次从男队和女队的队头各出一人配成舞伴。如果两队初始人数不等，则较长的那一队中未配对者等待下一轮舞曲。
-Circular Queue using simulated partner matching problem: at the ball, men
Platform: |
Size: 1024 |
Author: 石狼 |
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Description: ASP高级网 t 0 0 0000002 0 0006 ％ ts 0 2ms 每周期1000点 x1 sin(5000 2 pi t)()
Platform: |
Size: 71680 |
Author: fvlxdkcc
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