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Description: 北大ACM1003（Hangover）-North ACM1003 (Hangover)
Platform: |
Size: 28701 |
Author: ANGEL |
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Description: //{{NO_DEPENDENCIES}}
// Microsoft Developer Studio generated include file.
// Used by USBPort.rc
//
#define IDM_ABOUTBOX 0x0010
#define IDD_ABOUTBOX 100
#define IDS_ABOUTBOX 101
#define IDD_USBPORT_DIALOG 102
#define IDR_MAINFRAME 128
#define IDC_FIND 1001
#define IDC_EDIT_REPORT 1003
#define IDC_EDIT_ID 1004
#define IDC_ID_VENDOR 1005
#define IDC_ID_VERSION 1006
#define IDC_ID_PRODUCT 1007-//((NO_DEPENDENCIES))// Microsoft Deve loper Studio generated include file.// Used by USBPort.rc//# define IDM_ABOUTBOX 0x0008# de fine IDD_ABOUTBOX 100# define IDS_ABOUTBOX 10 1# define IDD_USBPORT_DIALOG 102# define IDR_ MAINFRAME 128# define IDC_FIND 1001# define ID C_EDIT_REPORT 1003# 1004# define IDC_EDIT_ID define IDC_ID_VENDOR 1005# define IDC_ID_VER SION 1006 1007# define IDC_ID_PRODUCT
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Size: 44032 |
Author: |
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Description: IEEE 1003.1-2003, Single Unix Specification v3
Platform: |
Size: 2900992 |
Author: Luca |
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Description: ACM 威士忌部分答案，可能有误，请谅解。-ACM whiskey part of the answer may be incorrect, please understanding.
Platform: |
Size: 1200128 |
Author: agxqsntt |
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Description: 北京大学ACM练习网站1003题代码，具体请参考http://acm.pku.edu.cn/JudgeOnline/problem?id=1003-Peking University ACM practice site title code 1003, please refer to the specific http://acm.pku.edu.cn/JudgeOnline/problem?id=1003
Platform: |
Size: 879616 |
Author: chenriji |
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Description: 这是在acm上所做的1003-1004，欢迎大家来下载，-This is done at acm on 1003-1004, welcomed everyone to download,lalala
Platform: |
Size: 339968 |
Author: zuoxue |
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Description: 第33届ACM亚洲区域赛（哈尔滨赛区预选）1003题目源码-The 33rd ACM Asia regional event (pre-division Harbin) 1003 Title Source
Platform: |
Size: 198656 |
Author: 齐达拉图 |
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Description: Turbo C2.0实用大全1 电子书籍-1 Guinness Turbo C2.0 practical e-books
Platform: |
Size: 4257792 |
Author: 牛猛猛 |
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Description: 已知一个三角形的三个点，求三角形的外接圆的周长-Known of the three points of a triangle, and circle the perimeter of a triangle
Platform: |
Size: 914432 |
Author: zhang |
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Description: 是ACM里面的1003题源代码认真书写并提交-ACM inside the 1003 title is the source code carefully written and submitted to the
Platform: |
Size: 7168 |
Author: 上传质量高 |
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Description: The POSIX standard volume 1.
Platform: |
Size: 1564672 |
Author: serj |
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Description: Goberl多层架构简单日记系统源码
说明：本源码为个人一个笔试题，虽然功能不多，但能够体现多层架构的思想，并有Ajax、富文本编辑器、对称加密、解密的使用，适合初学者。
介绍：
用户登录；
用户注册；
用户长期登录（使用对称加密Cookie）；
用户修改个人信息；
用户修改密码；
用户发布日志；
富文本fckeditor；
用户根据日期查看日记（仿CNZZ选择日期的方法）
使用Jquery无刷新保持会话状态（每3分钟刷新一次页面，保持Session，防止用户编写日记太久，点击提交时被踢下线）
测试用户名：1003
测试密码：51aspx
数据库在DB_51aspx文件夹下(sql2000)，附加即可-Goberl多层架构简单日记系统源码
说明：本源码为个人一个笔试题，虽然功能不多，但能够体现多层架构的思想，并有Ajax、富文本编辑器、对称加密、解密的使用，适合初学者。
介绍：
用户登录；
用户注册；
用户长期登录（使用对称加密Cookie）；
用户修改个人信息；
用户修改密码；
用户发布日志；
富文本fckeditor；
用户根据日期查看日记（仿CNZZ选择日期的方法）
使用Jquery无刷新保持会话状态（每3分钟刷新一次页面，保持Session，防止用户编写日记太久，点击提交时被踢下线）
测试用户名：1003
测试密码：51aspx
数据库在DB_51aspx文件夹下(sql2000)，附加即可
Platform: |
Size: 1482752 |
Author: wanghu |
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Description: c++算法源代码，主要是POJ上面的算法，根据标号可以找到。-c++ algorithm source code, POJ above algorithm, based on the label can be found.
Platform: |
Size: 136192 |
Author: 高飞 |
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Description: 家电制造企业网站(1003)具有适合家电制造企业网站的设计风格和页面布局，参考该行业典型网站，预设了适合家电制造企业网站的栏目和内容。模块化的网站软件构架，用户可以在现有成品网站的基础上加装其他功能模块；使用灵活的网页管理功能，可以自由添加和编辑网页；强大的鼠标拖曳排版功能，可以任意调整网站排版布局，灵活设置插件显示方式，网站管理维护更方便快捷。-Appliance manufacturers website (1003) with suitable appliance manufacturers website design style and page layout, typical of the industry reference sites, the default is suitable appliance manufacturer site columns and content. The modular software architecture, users can present the finished product based on the installation site other functional modules using flexible web management feature, you can add and edit pages powerful drag and layout features, you can adjust the site layout of any flexible set of plug display, website management and maintenance more convenient.
Platform: |
Size: 3058688 |
Author: yjn |
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Description: phpweb成品建站模板1003
使用起来还是不错的可以-phpweb Finished Build 1003 to use a template or a good try
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Size: 5563392 |
Author: niexuchao |
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Description: 虚拟主机或在自备服务器中开设好的主机空间，主机环境要求：
PHP4.3-5.x/非安全模式/允许WEB文件上传
MYSQL4.2-5.x
zend optimizer 3.2以上
上传后，安装直接进入网站安装：http://您的域名/
[安装方法]
1、下载安装包，将安装包下载解压后，将全部文件和目录上传到网站空间， 用FTP上传时必须采用二进制方式。
2、运行http://您的域名/（安装向导）,
第二步验证 免验证 ,第三步填写MYSQL数据库信息。
3、安装成功后请删除base/install/目录下所有文件
[初次登录]
安装成功后，点击安装最后一步的管理登录按钮，进入后台管理界面
使用在安装时设置的管理员帐户和密码登录后台管理系统
后台管理系统的访问地址为：http://网站域名/admin.php-Virtual host or open space owned a good host server, the host environment:
PHP4.3-5.x/non-secure mode/allow file uploads WEB
MYSQL4.2-5.x
zend optimizer 3.2 above
After uploading, the installation installed directly into the site: http:// your domain /
[Installation]
1, download and install the package, the package will be installed after the download, unzip the file and directory upload to all the web space, you must use binary mode with FTP upload.
2, run http:// your domain/(Setup Wizard),
The second step verification free verification, the third step to fill MYSQL database information.
3, remove the lower base/install/directory of all files after successful installation
[First login]
After successful installation, click the Install button on the last step of the administration login, enter admin interface
Use the settings when installing an administrator account and password to log back office management system
Access Address Management System is: http:// domai
Platform: |
Size: 3473408 |
Author: waldo |
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Description: 1、 闰年函数：计算闰年。
2、 学生成绩系统
已在程序中保存10条学生信息，方便直接检验查询功能而无需先录入，10条记录的学号分别是1001/1002/1003/1004/1005/1006/1007/1008/1009/1010
① 录入学生信息
② 录入学生分数
③ 查询信息及分数
④ 修改信息
⑤ 删除学生信息
（各功能均能循环进行，且实现如输入不存在的学号要求重新输入）(1 leap year function: calculate leap year.
2 student achievement system
In the program has saved 10 student information, convenient direct test query function, without the first entry, the 10 records of student number is 1001/1002/1003/1004/1005/1006/1007/1008/1009/1010
Enter student information
Enter students' scores
Query information and score
Modify information
Delete student information
(each function can be carried out circularly and implemented, such as the input does not exist, the number of students required to re enter))
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Size: 235520 |
Author: xqingmo
|
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Description: 北京大学ACM练习网站1003题代码,具体请参考http acm pku edu cn JudgeOnline problem id 10()
Platform: |
Size: 4096 |
Author: ifguqy |
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Description: 北大ACM题库中的部分已AC题目源码1001,1002,1003,1004,1005,1006,1007,1008()
Platform: |
Size: 3072 |
Author: LXGOfpfha&497 |
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Description: The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He realized that the bone was a trap, and he tried desperately to get out of this maze.
The maze was a rectangle with sizes N by M. There was a door in the maze. At the beginning, the door was closed and it would open at the T-th second for a short period of time (less than 1 second). Therefore the doggie had to arrive at the door on exactly the T-th second. In every second, he could move one block to one of the upper, lower, left and right neighboring blocks. Once he entered a block, the ground of this block would start to sink and disappear in the next second. He could not stay at one block for more than one second, nor could he move into a visited block. Can the poor doggie survive? Please help him.(The input consists of multiple test cases. The first line of each test case contains three integers N, M, and T (1 < N, M < 7; 0 < T < 50), which denote the sizes of the maze and the time at which the door will open, respectively. The next N lines give the maze layout, with each line containing M characters. A character is one of the following:
'X': a block of wall, which the doggie cannot enter;
'S': the start point of the doggie;
'D': the Door; or
'.': an empty block.)
Platform: |
Size: 1024 |
Author: zilewwy |
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