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[Driver Develop24c01-24c16驱动程序

Description: //24c01-24c16读写驱动程序, sbit a0=ACC^0 //定义ACC的位,利用ACC操作速度最快 sbit a1=ACC^1 sbit a2=ACC^2 sbit a3=ACC^3 sbit a4=ACC^4 sbit a5=ACC^5 sbit a6=ACC^6 sbit a7=ACC^7 -/ / 24c01 - 24c16 literacy drivers, ACC sbit a0 = ^ 0 / / ACC definition of the position, using the speed of the fastest ACC sbit ACC a1 = ^ 1 = a2 sbit ACC sbit a3 ^ 2 ^ 3 = ACC sbit a4 = ^ ACC a5 = 4 sbit ACC sbit a6 ^ 5 ^ 6 = ACC sbit a7 ACC = ^ 7
Platform: | Size: 958 | Author: 哟 乁 | Hits:

[Driver Develop01-24c16驱动程序

Description: //24c01-24c16读写驱动程序, sbit a0=ACC^0 //定义ACC的位,利用ACC操作速度最快 sbit a1=ACC^1 sbit a2=ACC^2 sbit a3=ACC^3 sbit a4=ACC^4 sbit a5=ACC^5 sbit a6=ACC^6 sbit a7=ACC^7 -/ / 24c01 - 24c16 literacy drivers, ACC sbit a0 = ^ 0 / / ACC definition of the position, using the speed of the fastest ACC sbit ACC a1 = ^ 1 = a2 sbit ACC sbit a3 ^ 2 ^ 3 = ACC sbit a4 = ^ ACC a5 = 4 sbit ACC sbit a6 ^ 5 ^ 6 = ACC sbit a7 ACC = ^ 7
Platform: | Size: 958 | Author: kkysun | Hits:

[Other resourcepara

Description: 抛物线法求解 方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*. 设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程 例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式. 方程中的系数a0由你得到的根p*来确定. -parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p *. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p * to determine.
Platform: | Size: 883 | Author: 董方 | Hits:

[Other resourceadvancenewton

Description: 改进的牛顿法求解: 方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*. 设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程 例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式. 方程中的系数a0由你得到的根p*来确定. -improve Newton's method : Construction of the equation : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p *. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : Your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p * to determine.
Platform: | Size: 801 | Author: 董方 | Hits:

[Other resourcehypot

Description: 抛物线法求解 方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*. 设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程 例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式. 方程中的系数a0由你得到的根p*来确定. -parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p *. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p * to determine.
Platform: | Size: 790 | Author: 董方 | Hits:

[Driver DevelopIic2

Description: 这是EEPROM芯片AT24C32的驱动程序,其中该芯片的A0,A1,A2脚均接地。-This EEPROM chip AT24C32 is the driving procedures, which the chip A0, A1, A2 feet are grounded.
Platform: | Size: 2071 | Author: 王累 | Hits:

[Com Portfet120_adc10_01

Description: ADC10, Sample A0, AVcc Ref, Set P1.0 if A0 > 0.5*AV-ADC10, Sample A0, AVcc Ref, Set P1.0 if A0
Platform: | Size: 1315 | Author: 刘J.C. | Hits:

[Parallel Portfet120_adc10_02

Description: ADC10, Sample A0, 1.5V Ref, Set P1.0 if A0 > 0.2V-ADC10, Sample A0, 1.5V Ref, Set P1.0 if A0
Platform: | Size: 1528 | Author: 刘J.C. | Hits:

[Other resource8254-373

Description: 应用373进行地址锁存的操作8254的源代码,详细情况可向作者联系 连线: A0---Q0 A1---Q1 A2---CS -373 applications for the operation address latch 8254 source code, the details of which can be linked to the authors link : A0 A1 Q0 --- --- --- CS Q1 A2
Platform: | Size: 1222 | Author: 王宇波 | Hits:

[Windows DevelopSpeechClock11654

Description: 结合\"61板\"的三个按键完成带有语音播报功能的电子钟: // 1、KEY1--按一下播放年、月、日,再按一下播放时、分 (I/O口A0) // 连续按3s,则进入调整状态 调整状态下调整内容的切换 // 2、KEY2--年、月、日、时、分的增加(I/O口A1) // 3、KEY3--年、月、日、时、分的减少(I/O口A2)-combination "61 boards" to complete th ree key functions with voice broadcast electronic bell : / / 1, KEY1 -- by about players, month, day and broadcast press once, - (I / O A0) / / by consecutive 3s, then a state of adjustment adjustment adjustment under the content switching / / 2. KEY2 -- the year, month, day and hour of the increase in hours (I / O A1) / / 3, KEY3 --, on that day, when the reduced hours (I / O A2)
Platform: | Size: 138155 | Author: jone Pote | Hits:

[Other resourceobject-design

Description: 统一用例方法+-+A0+-+IT之源+-+张恂 UML基础案例与应用 项目经理案头手册 飞利浦高级经理内部培训资料 界观+-+对对象模型的通俗理解-+邱嘉文+2002[1].03.05 JAVA设计模式1-reunification with cases method-A0-source IT-UML Zhang Xun case basis and application of project managers desk manuals to fly Lipp, Senior Manager internal training materials outlook-object model of the popular understanding - Qiujiawen 2002 [1] .03. JAVA 05 design a model
Platform: | Size: 14832042 | Author: 真实姓名 | Hits:

[Other resourcec-basic

Description: 用C-BASEIC语言编写的805X单片机计算子程序P=A0+A1*X+A2*X*X+A3-with C-language BASEIC the 805X MCU calculation subroutine P = A0 A1 A2 * X * A3 * X * X * X * X * X
Platform: | Size: 29158 | Author: spr | Hits:

[Other resourceCorrelation1

Description: //=== === === === === === ===== //函数说明 //函数名称:Correlation //函数功能:计算最小二乘法拟合的多项式的相关系数 //使用方法:int M------ 拟合多项式的阶数(已知条件) // double *b--- 拟合曲线的系数,排列顺序为由高阶到低阶(已知条件) // double *x--- 结点x轴数据(已知条件) // double *y--- 结点y轴数据(已知条件) // double *Yg-- 结点估计值,个数为m(过程变量) // int m------ 结点个数(已知条件) //注意事项:多项式阶数最高为10,多项式的形式为 y = a0 + a1x +a2x2 -//=== === === === === ==== === === === === === === = / / letter Description / / function name : Correlation / / Function functions : Calculation least squares polynomial fitting of the correlation coefficient / / Use : int M ------ polynomial fitting stage (known condition) / / * b --- double fitting song The coefficient, Higher-order the order on grounds of low order (known condition) / / * double-node x x axis data (known to be pieces) / / double * y --- node y-axis data (known condition) / / * double FSL -- Nodes estimates, Number m (process variables) / / int m ------ node number (known condition) / / Note : polynomial order of a maximum of 10. polynomials in the form of y = a0 a1x a2x2 //==================== ========================================
Platform: | Size: 1073 | Author: 石林 | Hits:

[mpeg mp3DVB_MHPbox_SRC

Description: MHPbox-0.0-A0.zipMHPbox project is an open source implementation of MHP (Multimedia Home Platform). MHP is the open middleware designed by the DVB 欧洲标准 DVB 数字电视的中间件MHP 源代码 Project that is being used in digital TVs. MHPbox will turn your PC in a digital TV and provide a framework for developers-MHPbox - 0.0 - A0.zipMHPbox project is an op en source implementation of MHP (Multimedia Ho Platform me). MHP is the open middleware design ed by the European DVB digital television standard DVB MHP middleware source code Project th at is being used in digital TVs. MHPbox will turn your PC in a digital TV and provide a framework az r developers
Platform: | Size: 5453514 | Author: 12 | Hits:

[Other resourceLCD501Graphic

Description: 显示凌阳标志动画 涉及的库: CMacro1016.lib // 组成文件: main.c/SPLC501User.c/Sunplus_Table.c // SPLC501Driver_IO.asm/DataOSforLCD.asm // SPLC501User.h/Sunplus_Table.h // SPLC501Driver_IO.inc // // 硬件连接: LCD DB0~DB7接IOA0~IOA7 // LCD EP 接IOB5 // LCD RW 接IOB4 // LCD A0 接IOB3 // LCD /CS 接IOB2 或接地也可 // // 维护记录: 2005-09-20 v1.0 // 注意事项: 1.SPLC501的 // 2.IO高电平:3.3V-showed signs of the animation : CMacro1016.lib / / constituent documents : main.c/SPLC501User.c/Sunplus_Table.c / / SP LC501Driver_IO.asm/DataOSforLCD.asm / / SPL C501User.h/Sunplus_Table.h / / SPLC501Drive r_IO.inc / / / / hardware connection : LCD DB0 DB7 access IOA0 ~ ~ IOA7 / / LCD EP then IOB5 / / LCD RW access IOB4 / / LCD A0 access IOB3 / / LCD / CS or grounding then IOB2 can / / / / Maintenance record : 2005-09-20 v1.0 / / Note : 1.SPLC501 / / 2.IO margin : 3.3V
Platform: | Size: 53166 | Author: leon | Hits:

[Other resourceLCD501Ellipse

Description: 显示\"凌阳 科技 落实 生活\"八个汉字,分四个词在四行 // 上错开显示。 // 涉及的库: CMacro1016.lib // 组成文件: main.c/SPLC501User.c/Chinese_Table.c // SPLC501Driver_IO.asm/DataOSforLCD.asm // SPLC501User.h/Chinese_Table.h // SPLC501Driver_IO.inc // // 硬件连接: LCD DB0~DB7接IOA0~IOA7 // LCD EP 接IOB5 // LCD RW 接IOB4 // LCD A0 接IOB3 // LCD /CS 接IOB2 或接地也可-showed that the "implementation of Sunplus Technology Life" eight Chinese characters, the four words Sixingshang / / stagger on the show. / / The library : CMacro1016.lib / / constituent documents : main.c/SPLC501User.c/Chinese_Table.c / / SP LC501Driver_IO.asm/DataOSforLCD.asm / / SPL C501User.h/Chinese_Table.h / / SPLC501Drive r_IO.inc / / / / hardware connection : LCD DB0 DB7 access IOA0 ~ ~ IOA7 / / LCD EP then IOB5 / / LCD RW access IOB4 / / LCD A0 access IOB3 / / LCD / CS received IOB2 or grounding may also
Platform: | Size: 35325 | Author: leon | Hits:

[Special EffectsColorTransformRGB-LAB

Description: 自己写的很实用的色彩空间转换程序: 在色彩空间的正向转换中(RGB----->Lab),用的是九级均匀分割建模 在色彩空间的反向转换中(Lab----->RGB),用的是多项式(20项)回归的方法! 二十项多项式: p(x,y,z)=a0+a1*x+a2*y+a3*z+a4*x*y+a5*y*z+a6*x*z+a7*x^2+a8*y^2+a9*z^2+a10*x*y*z+a11*x^3+a12*y^3-himself wrote a very practical color space conversion : the color space conversion positive (RGB
Platform: | Size: 124827 | Author: 思根 | Hits:

[Other resourceLeastSquarFit

Description: 用最小二乘法拟合曲线y=a0+a1*x+a2*x^2+a3*x^3+...+an*x^n 的vc源码-using the method of least squares fitting curve y = a0 a1 a2 * x * x * a3 ^ 2 x ^ 3 ... an * x ^ n vc FO
Platform: | Size: 1835 | Author: wawyace | Hits:

[CA autha0

Description: 自动无限激活卡巴斯基的程序我不就是要下个程序源码么还不知道能不能用了你们怎么就这么麻烦那啊~。-Unlimited automatic procedure to activate Kaspersky is I do not want to process the next source code you can not know how you spent it on such a trouble ah ~.
Platform: | Size: 8192 | Author: 完全饿 | Hits:

[SCM4830wrht24xx

Description: HT24 系列的EEPROM 总共8 个管脚,三个为芯片地址脚A0、A1、A2,在单片机对它进行操作时,从SDA 输入A0、A1、A2 数据和芯片外部A0、A1、A2 所接地址需一一对应。一个为芯片写保护脚WP,WP 脚接低电平时,芯片可进行读写操作;WP 脚接高时,芯片只可进行读,不可进行写。 另外两个管脚为电源脚VCC,VSS。 用单片机对HT24 系列的EEPROM 进行控制时,HT24 系列的EEPROM 的外部管脚VCC、VSS、WP、A0、A1、A2 根据需要,对应接上,SDA、SCL 接到单片机控制脚上。-HT24 Series EEPROM total of 8 pins, three pins for the chip address A0, A1, A2, in the microcontroller to operate it, from SDA input A0, A1, A2, and chip external data A0, A1, A2 of the Then one correspondence address must be in. One for the chip, write-protect pin WP, WP feet then low, the chip can be read and write operations WP pin is high then, the chip can only be read, not write. The other two pins for the power pin VCC, VSS. With the microcontroller on the HT24 Series EEPROM control when, HT24 Series EEPROM external pin VCC, VSS, WP, A0, A1, A2 according to the needs of the corresponding connected, SDA, SCL receives SCM control feet .
Platform: | Size: 1024 | Author: 张钧 | Hits:
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