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Description: fen否则需依次排队等候。一旦有顾客理完发离去时，排在队头的顾客便可开始理发。若理发店每天
连续营业T小时，
求一天内顾客在理发馆内平均的逗留时间、顾客排队等候理发的队列的平均长度、营业时间到点后仍需
要完成的收尾工作时间
测试数据：理发椅数N及关门时间由用户读入，第一个顾客进门的时刻为0，之后每个顾客进门的时刻由
前一个顾客进门时间确定。即在进门事件发生时即产生两个随机数（durtime,intertime）,durtime为进
门顾客理发所需要的服务时间，intertime为下一个顾客将到达的时间间隔。R为-fen otherwise be followed queue. Once customers Jimmy End made to leave, the first in the queue of customers will start barber. If the barber shop daily turnover of T consecutive hours a day for customers in the barbershop where the average length of stay, customers are queuing up at the barbershop the average queue length, hours after the close of the need to complete the relevant work time test data : N barber chairs and closed by the user time to read, a customers went 0 for the moment, the door after each customer from the time a customer comes first time to determine. At the time of the incident comes as a result of two random number (durtime, intertime), the door for customers durtime hairdressing services needed by the time intertime customers for the next one will arrive in the tim
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Size: 489320 |
Author: 王寒夜 |
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Description: 题目内容：使用队列模拟理发馆的排队现象，通过仿真手法评估其营业状况。
基本要求：
假设理发馆内设有N把理发椅，可同时为N位顾客进行理发。对于在营业时间(假设为T小时)内进门的顾客：
*当顾客进门时，若有空椅，则可以立即坐下理发，否则需要依次排队等候。
*一旦有顾客理完发离去时，排在队头的顾客便可开始理发。
*若理发馆每天连续营业T小时，求一天内顾客在理发馆内的平均逗留时间
*顾客排队等候的队列平均长度。
*营业时间到点后仍需完成服务的收尾工作时间。-topics as : the use of cohort simulation barber's shop, the queues, through simulation methods to assess its financial situation. Basic requirement : Suppose N Barber Library has put barber chairs, as well as for customers, N barber. For hours (assuming T-hour) entering customers : * When customers come through the door, if empty chairs, they can sit down barber immediately, otherwise needs were queuing up. * Once customers Jimmy End made to leave, the first in the queue of customers will start barber. * If the Barber Museum consecutive business day T-hour day for customers in the barbershop where the average length of stay * Customers waiting in line for the average queue length. * Hours after the close of the service needs to be done finishing time.
Platform: |
Size: 7560 |
Author: lucky100 |
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Description: fen否则需依次排队等候。一旦有顾客理完发离去时，排在队头的顾客便可开始理发。若理发店每天
连续营业T小时，
求一天内顾客在理发馆内平均的逗留时间、顾客排队等候理发的队列的平均长度、营业时间到点后仍需
要完成的收尾工作时间
测试数据：理发椅数N及关门时间由用户读入，第一个顾客进门的时刻为0，之后每个顾客进门的时刻由
前一个顾客进门时间确定。即在进门事件发生时即产生两个随机数（durtime,intertime）,durtime为进
门顾客理发所需要的服务时间，intertime为下一个顾客将到达的时间间隔。R为-fen otherwise be followed queue. Once customers Jimmy End made to leave, the first in the queue of customers will start barber. If the barber shop daily turnover of T consecutive hours a day for customers in the barbershop where the average length of stay, customers are queuing up at the barbershop the average queue length, hours after the close of the need to complete the relevant work time test data : N barber chairs and closed by the user time to read, a customers went 0 for the moment, the door after each customer from the time a customer comes first time to determine. At the time of the incident comes as a result of two random number (durtime, intertime), the door for customers durtime hairdressing services needed by the time intertime customers for the next one will arrive in the tim
Platform: |
Size: 489472 |
Author: 王寒夜 |
Hits:
Description: 题目内容：使用队列模拟理发馆的排队现象，通过仿真手法评估其营业状况。
基本要求：
假设理发馆内设有N把理发椅，可同时为N位顾客进行理发。对于在营业时间(假设为T小时)内进门的顾客：
*当顾客进门时，若有空椅，则可以立即坐下理发，否则需要依次排队等候。
*一旦有顾客理完发离去时，排在队头的顾客便可开始理发。
*若理发馆每天连续营业T小时，求一天内顾客在理发馆内的平均逗留时间
*顾客排队等候的队列平均长度。
*营业时间到点后仍需完成服务的收尾工作时间。-topics as : the use of cohort simulation barber's shop, the queues, through simulation methods to assess its financial situation. Basic requirement : Suppose N Barber Library has put barber chairs, as well as for customers, N barber. For hours (assuming T-hour) entering customers :* When customers come through the door, if empty chairs, they can sit down barber immediately, otherwise needs were queuing up.* Once customers Jimmy End made to leave, the first in the queue of customers will start barber.* If the Barber Museum consecutive business day T-hour day for customers in the barbershop where the average length of stay* Customers waiting in line for the average queue length.* Hours after the close of the service needs to be done finishing time.
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Size: 62464 |
Author: lucky100 |
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Description: 理发店网上发型设计预约系统，是一个典型的JSP数据库开发应用程序，由前台发型设计和理发师预约、后台管理2部分组成。本系统设计中使用了Struts框架建立电子商务网站。在Struts框架中，JSP用于前端展现，Action用于处理前端页面的JSP发来的请求，请求参数通过Struts拦截器机制进行传递，Action在获得请求之后连接数据库做处理，最后将处理结果转发到相应的JSP进行展现。系统中还运用了一定的图像处理技术，将图片以二进制文件存储到数据库中，再进行读取、修改等操作，替换覆盖图片实现“换装”效果。-err
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Size: 5269504 |
Author: Jane |
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Description: Barber Shop algorithm Synchronization Simulator-Barber Shop algorithm Synchronization Simulator
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Size: 20480 |
Author: Nasir |
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Description: 用C语言写的一个理发店排队系统问题，包括输入和输出文件。希望大家可以用的上。-a program by C
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Size: 225280 |
Author: 罗扇 |
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Description: 设有一个理发师，5把椅子（另外还有一把理发椅），几把椅子可用连续存储单元。
要求：
1）为每个理发师／顾客产生一个线程，设计正确的同步算法
2）每个顾客进入理发室后，即时显示“Entered” 及其线程自定义标识，还同时显示理发室共有几名顾客及其所坐的位置。
3）至少有10个顾客，每人理发至少3秒钟。
4）多个顾客须共享操作函数代码。 -There is a barber, five chairs (in addition to a barber chair), a few chairs available contiguous memory cell. Requirements: 1) for each of the barber/customer to generate a thread, designed to correct synchronization algorithm 2) Every customer entered a barbershop, immediately after the show " Entered" and the thread is a custom logo, also showed there were a few barbershop Customers and the sitting position. 3) At least 10 customers, each hair for at least 3 seconds. 4) A number of customers to share the operation of the function code.
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Size: 7168 |
Author: mingqing |
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Description: 一个Struts实现的在线发型设计系统，包括在线发型试戴，预约理发师，生成理发订单等功能-Struts implementation of a hair-line design system, including trying on-line hair, hairdresser appointments, orders and other features generated Barber
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Size: 5003264 |
Author: 桃子 |
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Description: 利用二叉树模拟理发店顾客的等待时间情况，其中以随机数生成的顾客流-using binary Tree Simulation to simulate customer waiting time in barber shops, of which a random number generator of customer flow
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Size: 2048 |
Author: quiq |
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Description: 理发店系统的模拟，背包问题求解得穷举法得到最优解的程序等的MATLAB程序源代码-Barbershop system simulation, Knapsack Problem was exhaustive method to obtain the optimal solution procedures for the MATLAB source code
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Size: 9216 |
Author: liuliu |
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Description: GUI barbershop with java
5 customer with barber sleep and cutting hair
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Size: 433152 |
Author: nina |
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Description: 理发店C++模拟，数据结构课程设计~功能比较简单，有点小BUG~-Barber shop C++ simulation, data structures curriculum design ~ function is relatively simple, a bit small BUG ~
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Size: 1091584 |
Author: superpig119 |
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Description: 操作系统一作业，是理发师理发的模拟实现。-Operating system for a job, is a barber haircut Simulation.
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Size: 32081920 |
Author: 刘新 |
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Description: Sleeping Barber java
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Size: 20480 |
Author: vincenzo |
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Description: Barbershop parallel programming source code.
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Size: 12288 |
Author: Bocato |
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Description: 用C#编写的超小型理发店收银系统，管理收入-Small barber shop cash register system
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Size: 1868800 |
Author: hekun |
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Description: 理发店里有一位理发师，一把理发椅和 N 把供等候理发的顾客坐的椅子 如果没有顾客,则理发师便在理发椅上睡觉。当一个顾客到来时，他必须先唤醒理发师。如果顾客到来时理发师正在理发，则如果有空椅子，可坐下来等；否 则离开。操作系统信号量控制进程同步。-Barbershop, a hairdresser, a barber chair and N customer sat waiting Barber chair if no customers, the barber would sleep in the barber chair. When a customer comes, he must wake up to the barber. If the customer comes barber is Barber, if the empty chair, sit down and so on otherwise leave. The semaphore control of the operating system process synchronization.
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Size: 171008 |
Author: Miami |
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Description: 理发店营业仿真：
理发店有2名理发师,为每名顾客服务时间MU=20min+-SIGMA=3min服从正态分布,顾客相继到达,时间间隔服从1/LAMBDA=10min的指数分布.顾客到达后如发现店内有6人以上排队等待,30 顾客会选择离开,其余人继续等待.
要求:建模,仿真
一天10小时营业,统计N天内:
1.理发师实际服务人数
2.平均队长及因排队人数过多而离去的人数
3.ALPHA=0.05计算置信区间.
-Barber shop business simulation: two barber barbershop, service time per customer MU = 20min+-SIGMA-= 3min follow a normal distribution, the customers were arriving interval The obedience 1/LAMBDA = 10min exponential distribution. Customers arrive found store queued for more than 6 people, 30 of customers will choose to leave, the rest continue to wait. requirements: modeling, simulation day 10 hours a day, statistics N days: 1. barber actual service number 2. average captain and due the number of people queuing overrepresented departed 3.ALPHA = 0.05 confidence interval.
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Size: 2048 |
Author: 连云 |
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Description: 操作系统概念第六版信号量课后习题，Barbershop的多线程编码-Operating System Concepts sixth edition Semaphore of the book exercise, babershop problem, java multithreading semaphore issues
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Size: 2048 |
Author: 李长松 |
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