Search - Infix grammar

Search - Infix grammar - List

[Data structs] tree DL : 1: 表达式类型的实现: 1、一个表达式和一颗二叉树之间，存在着自然的对应关系。 2、假设算术表达式Expression内可以含有变量（a～z）、常量（0～9）和二元运算符（＋，－，*，/，^）。实现一下操作。（1） ReadExpr(E)——以字符序列的形式输入语法正确的前缀表示式并构造表达式E。（2） WritrExpr(E)——用带括弧的中缀表示式输出表达式E。（3） Assign(V,c)——实现对变量V的赋值(V=c),变量的初值为0。（4） Value(E)——对算术表达式E求值。（5） CompoundExpr(P,E1,E2)——构造一个新的复合表达式（E1）P (E2)。 -Realize the type of expression: one, an expression, and between a binary tree, there is a natural correspondence between. 2, assuming that the arithmetic expression Expression can contain variables (a ~ z), constant (0 ~ 9) and binary operators ( ,-,*,/,^)。 You realize the operation. (1) ReadExpr (E)- sequence of characters in the form of input grammar correct prefix expressions and tectonic expression of E. (2) WritrExpr (E)- used within parentheses express output infix expression E. (3) Assign (V, c)- realize the value V of the variables (V = c), variable initial value is 0. (4) Value (E)- on the arithmetic expression E is evaluated. (5) CompoundExpr (P, E1, E2)- Construction of a new composite expression (E1) P (E2).
Date : 2025-07-02 Size : 57kb User :
[Other] Caluate DL : 0: 将中缀表达式转换为后缀表达式，并计算任意四则运算表达式的结果，采用链表和队列实现，非文法和状态机-Infix expression would be converted to suffix expressions, and calculate the arithmetic expression of arbitrary results, the use of linked lists and queues to achieve, non-grammar and the state machine
Date : 2025-07-02 Size : 7kb User : wuwenxi
[Data structs] ICCaluaten DL : 0: 将中缀表达式转换为后缀表达式，并计算任意四则运算表达式的结果果，采用链表和队列实现，非文法和状态机，已通过测试。 -Infix convert an expression for the postfix expression, and calculate any four of expression is the result fruit, using linked lists and queues, non-grammar and state machines, has been tested.
Date : 2025-07-02 Size : 7kb User : 认可
[ELanguage] postfix-notation DL : 0: 1、给出文法如下： G[E] E->T|E+T T->F|T*F F->i(E) 对应的转化为逆波兰式的语义动作如下： E-> E(1)op E(2) {E.CODE:= E(1).CODE||E(2).CODE||op} E->(E(1)) { E.CODE := E(1).CODE} E->id { E.CODE := id} 2、利用实验5中的算符优先分析算法，结合上面给出的语义动作实现逆波兰式的构造； 3、利用栈，计算生成的逆波兰式，步骤如下： 1）中缀表达式，从文本文件读入，每一行存放一个表达式，为了降低难度，表达式采用常数表达式； 2）利用结合语法制导翻译的算符优先分析，构造逆波兰式； 3）利用栈计算出后缀式的结果，并输出；-1 gives grammar as follows: E [E] E-> T | E+ T T-> F | T* F F-> i (E) the corresponding inverse Polish into semantic action as follows: E-> E (1) op E (2) {E.CODE: = E (1) .CODE || E (2) .CODE || op} E-> (E (1)) {E.CODE: = E (1) .CODE} E-> id {E.CODE: = id} 2, the use of experimental 5 operator priority analysis algorithms, combined with semantic actions given above structure to achieve reverse Polish notation 3, the use of the stack, calculates the resulting Reverse Polish Notation, as follows: 1) infix expression, read a text file, each line deposited an expression, in order to reduce the difficulty of using a constant expression expression 2) the use of binding syntax directed translation of operator priority analysis, structural inverse Polish 3) Using the calculated postfix stack of results and outputs
Date : 2025-07-02 Size : 1kb User : 忆昔