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[SymbianJewel

Description: symbian下的泡泡龙游戏源码,手机游戏开放新手学习的好资料-symbian the source Paopaolong games, cell phone games open novice learning good information
Platform: | Size: 139402 | Author: 胡家宝 | Hits:

[SymbianJewel

Description: symbian下的泡泡龙游戏源码,手机游戏开放新手学习的好资料-symbian the source Paopaolong games, cell phone games open novice learning good information
Platform: | Size: 139264 | Author: 胡家宝 | Hits:

[Game ProgramCH09

Description: 运行在JDK1.5下的宝石连连看游戏."打包发布"文件夹中的Kyodai.bat直接运行."源文件"文件夹为程序源码-Running on JDK1.5 under the Jewel Jam game.
Platform: | Size: 925696 | Author: hphpever | Hits:

[JSP/Javalianliankan

Description: 使用JAVA语言编写的宝石连连看游戏的源代码。-The use of JAVA language Jewel Jam game s source code.
Platform: | Size: 385024 | Author: 黄戈 | Hits:

[Other GamesKyodai

Description: 该宝石连连看游戏有刷新,提示,炸弹,演示,设置以及计算时间和分数等功能-The Jewel Jam game has set, suggesting that, bombs, demonstrations, set up and to calculate the fraction of time and other functions
Platform: | Size: 926720 | Author: yee | Hits:

[source in ebookzuheshuxue

Description: 组合数学是数学中的宝石,是人类数学智慧的体现-Combinatorial mathematics is the jewel in mathematics, mathematics is a human embodiment of wisdom
Platform: | Size: 39936 | Author: 肖阳 | Hits:

[JSP/JavaASimpleJewelJam

Description: 一个宝石连连看游戏的源代码,运行非常简单,而且画面特别好,程序也容易,是Java初学者的至爱。-A Jewel Jam game s source code, run a very simple, and images are particularly good, easy to process, is the favorite Java beginners.
Platform: | Size: 385024 | Author: 罗维 | Hits:

[JSP/JavaKyodai

Description: 用JAVA编写的宝石连连看游戏,非常动感的音效和漂亮的界面,提供给大家!-Written using JAVA Jewel Jam game, a very dynamic sound and beautiful interface, available to everyone!
Platform: | Size: 923648 | Author: lu | Hits:

[Other Riddle gamesjewel

Description: Java实现经典小游戏,宝石连连看!绝对好玩!-A funny game which carry out by JAVA language.
Platform: | Size: 928768 | Author: huang | Hits:

[VC/MFCEx_CommCtrl

Description: c++\Visual C++程序开发范例宝典-Visual c++ program development paradigm jewel
Platform: | Size: 4675584 | Author: 桓文 | Hits:

[Windows DevelopJEWEL-Test-Source

Description: JEWEL测试代码,JEWEL动态链接库接口程序的测试。VC++6.0开发。-JEWEL test code, JEWEL dynamic link library interface routine testing. VC++6.0 development.
Platform: | Size: 5539840 | Author: cdq | Hits:

[Software EngineeringEloquent_ruby

Description: In fluent Ruby, Russ Olsen help you write Ruby like Rubyists really doing? So you can take advantage of his big, surprising power. Olsen draws on years of teaching experience and cultural internalization Ruby Ruby to other programmers. moments when suddenly becomes clear why the Ruby work that way, and how you can take advantage of this language? s, and expressive elegance. Ruby fluent start small, tactical questions focused on a single statement, methods, testing, or a bug. ? You will learn how to write code that actually looked like Ruby (not Java or C #), why Ruby has so much control structure, how to use strings, expressions, and symbols, and what is good for dynamic typing. Furthermore, the book addresses big questions relating to the construction methods and classes. He concluded with a strong project-level features and techniques ranging from jewel Domain Specific Language. A part of the Addison-Wesley Professional Ruby Series famous, eloquent Ruby will help you? Ruby-colored glasses you wear?
Platform: | Size: 2351104 | Author: resx | Hits:

[Other GamesJeweled-calculators

Description: 宝石计算器,用于计算暗黑3拍卖场的宝石价格。可得出自己的利润-Gem calculator used to calculate the price of Diablo 3 the jewel of the auction. Can be drawn from their own profits
Platform: | Size: 9873408 | Author: 高静 | Hits:

[Linux-UnixphHciNfc_Jewel

Description: brief HCI Jewel/Topaz Management Routines.
Platform: | Size: 6144 | Author: fuehairou | Hits:

[SCMstc12MCU-PN532-code

Description: pn532开发的单片机源代码,作为开发NFC的试验用,可读写ISO14443-A/B协议的射频卡和felica以及宝石卡-pn532 developed microcontroller source code, as the development of NFC test, can read and write ISO14443-A/B protocol and RF cards and jewel card felica
Platform: | Size: 3072 | Author: yangfan | Hits:

[OtherProgrammer-interview-jewel

Description: 程序员面试宝典,包括了java和c及c++,内容包罗万象,对刚找出校门立志做程序员的毕业生很有帮助-Programmer interview bible, including the Java and c and c, everything, do to just find the school aspires to the programmer s graduates is very helpful
Platform: | Size: 6286336 | Author: liu | Hits:

[Software EngineeringProgrammer-interview-jewel

Description: 一本很好的程序员面试书籍,电子版的,供大家学习使用-A good programmer interview books, the electronic version for everyone to learn to use
Platform: | Size: 6286336 | Author: 杨国环 | Hits:

[SCMe-jewel

Description: embedded c used in switching camera attached to micro controller and change accordgly
Platform: | Size: 21504 | Author: meghna | Hits:

[Other1106

Description: ACM1106题:“自然科学的皇后是数学。数学的皇冠是数论。哥德巴赫猜想,则是皇冠上的明珠。”哥德巴赫猜想表述为:任一大于2的偶数都可写成两个质数之和。当然我们今天不是来证明哥德巴赫猜想的,而是验证对于比较小的偶数其猜想是否成立。 Input数据的第一行是一个正整数T(0<T<=100),表示有T组测试数据。 每组测试数据只有一行,为一个偶数M(2<M<=100000),表示要验证的偶数。Output对于每组测试数据,在一行上输出两个质数A,B(A<=B),表示M=A+B,如果有多种可能,则输出B-A的值最小的那组。 Sample Input3 6 10 12Sample Output3 3 5 5 5 7-ACM1106 title: " Queen of the natural sciences mathematics is mathematics crown Goldbach conjecture in number theory, it is the jewel in the crown ..." Goldbach conjecture expressed as: any even number greater than 2 can be written as two prime numbers and. Of course we have today is not to prove Goldbach conjecture, but even relatively small validation for their conjecture is established. Input data of the first line is a positive integer T (0 <T<=100),表示有T组测试数据。 每组测试数据只有一行,为一个偶数M(2<M<=100000),表示要验证的偶数。Output对于每组测试数据,在一行上输出两个质数A,B(A<=B),表示M=A+B,如果有多种可能,则输出B-A的值最小的那组。 Sample Input3 6 10 12Sample Output3 3 5 5 5 7
Platform: | Size: 1024 | Author: 范晓旭 | Hits:

[Otherlading

Description: 拉丁矩阵问题: 现有N种不同形状的宝石,每种宝石有足够多颗。欲将这些宝石排列成m行n列的一个矩阵,m<=n,使矩阵中每一行和每一列的宝石都没有相同形状。试设计一个算法,计算出对于给定的m和n,有多少种不同的宝石排列方案。 算法设计: 对于给定的m和n,计算出不同的宝石排列方案数。 -Latin matrix problem: Existing N different shapes of stones, each gem has enough teeth. The stones are arranged in a matrix wishing m rows and n columns, m < = n, the matrix so that each row and each column do not have the same shape as the jewel. Try to design an algorithm to calculate for a given m and n, there are many different kinds of gems arranged plan. Algorithm Design: For a given m and n, the program calculates the number of different permutations gems.
Platform: | Size: 1024 | Author: liuxu | Hits:
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