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Description: 目前能实现随意控制蚂蚁的轨迹长度（Path）、数量（Unit）、速度（V）、角度（R）、加速度（dv，dr）。
Kr和Kv是常数，打算将来改成数组，作为用来控制蚂蚁活跃程度的基因。-can now achieve arbitrary control ants length of the track (Path), volume (Unit), speed (V), angle (R), acceleration (dv, dr). Kr and Kv is constant, is planning to change the array, used to control ants active genes.
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Size: 1822 |
Author: 王子良 |
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Description: Individual files are available in the following links:
Bessjy -- Bessel functions Jn and Yn for real argument and integer or real order.
Bessik -- Modified Bessel function In and Kn for real argument and integer or real order.
CBessjy -- Bessel functions Jv and Yv for real or complex arguments and real order.
CBessik -- Modified Bessel functions Iv and Kv for complex arguments and real order.
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Size: 18491 |
Author: luo chao |
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Description: KVM (for Kernel-based Virtual Machine) is a full virtualization solution for Linux on x86 hardware. It consists of a loadable kernel module (kvm.ko) and a userspace component.
Using KVM, one can run multiple virtual machines running unmodified Linux or Windows images. Each virtual machine has private virtualized hardware: a network card, disk, graphics adapter, etc.
The kernel component of KVM is included in mainline Linux, and will appear in Linux 2.6.20.
KVM is open source software.
-KVM (for Kernel-based Virtual Machine) is a full virtualization solution for Linux on x86 hardware. It consists of a loadable kernel modu le (kvm.ko) and a userspace component. Using KV M, one can run multiple virtual machines running u nmodified Linux or Windows images. Each virtua l machine has private virtualized hardware : a network card, disk, graphics adapter. etc.. The kernel component of KVM is included in m ainline Linux, and will appear in Linux 2.6.20. KVM is open sour ce software.
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Size: 2046435 |
Author: 翟钦风 |
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Description: 已知单位负反馈系统被控对象的传函为:
• 设计滞后-超前校正装置,使校正后的系统满足:
• (1).在单位斜坡信号作用下,Kv=10s^(-1)
• (2).校正后相角裕度³ 45°
• (3).系统校正后剪切频率wc ³ 1.5s^(-1)
• (4).时域性能指标:s％£ 30％,Tp £ 2s,Ts £ 6s
-units known negative feedback system object to the transfer function :
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Size: 1555 |
Author: zyhd |
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Description: Hard-decision decoding scheme
Codeword length (n) : 31 symbols.
Message length (k) : 19 symbols.
Error correction capability (t) : 6 symbols
One symbol represents 5 bit.
Uses GF(2^5) with primitive polynomial p(x) = X^5 X^2 + 1
Generator polynomial, g(x) = a^15 a^21*X + a^6*X^2 + a^15*X^3 + a^25*X^4 + a^17*X^5 + a^18*X^6 + a^30*X^7 + a^20*X^8 + a^23*X^9 + a^27*X^10 + a^24*X^11 + X^12. Note: a = alpha, primitive element in GF(2^5) and a^i is root of g(x) for i = 19, 20, ..., 30.
Uses Verilog description with synthesizable RTL modelling.
Consists of 5 main blocks: SC (Syndrome Computation), KES (Key Equation Solver), CSEE (Chien Search and Error Evaluator), Controller and FIFO Register.
-Hard-decision decoding scheme Codeword l KV (n) : 31 symbols. Message length (k) : 19 symbols. Error correction capability (t) : 6 symbols One symbol represents five bit. Uses GF (2 ^ 5) with primitive polynomial p (x) = x ^ x ^ 5 2 1 Ge nerator polynomial. g (x) = a ^ a ^ 15 * 21 ^ 6 a X * X ^ a ^ 15 2 * X ^ a ^ 3 25 * X ^ a ^ 4 17 5 * X ^ a ^ 18 ^ 6 X * a * X 30 ^ 7 ^ a ^ 20 * X ^ a ^ 23 8 * X ^ a ^ 9 * 27 X 10 ^ a ^ 24 * 11 ^ X ^ X 12. Note : a = alpha, primitive element in GF (2 ^ 5) and a ^ i is the root of g (x) for i = 19, 20, ..., 30. Uses Verilog description with synthesizab le RTL modeling. Consists of five main blocks : SC (Syndrome Computation), KES (Key Equation Solver). CSEE (Chien Search and Error Evaluator) Controller and FIFO Register.
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Size: 14247 |
Author: 孟轲敏 |
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Description: American Gladiator,You are consulting for a game show in which n contestants are pitted against n gladiators in order to see which contestants are the best. The game show aims to rank the contestants in order of strength this is done via a series of 1-on-1 matches between contestants and gladiators. If the contestant is stronger than the gladiator, then the contestant wins the match otherwise, the gladiator wins the match. If the contestant and gladiator have equal strength, then they are “perfect equals” and a tie is declared. We assume that each contestant is the perfect equal of exactly one gladiator, and each gladiator is the perfect equal of exactly one contestant. However, as the gladiators sometimes change from one show to another, we do not know the ordering of strength among the gladiators. -American Gladiator. You are consulting for a game show in which n cont estants are pitted against n gladiators in orde r to see which contestants are the best. The game show aims to rank the contestants in order of str KV this is done via a series of 1-on-1 matches between contestants and gladiators. If the con testant is stronger than the gladiator. then the contestant wins the match otherwise, the gladiator wins the match. If the contestant and gladiator have equal strength. then they are "perfect equals" and a tie is decla red. We assume that each contestant is the perfe ct equal of exactly one gladiator. and each gladiator is the perfect exact equal of ly one contestant. However, as the gladiators sometimes change from one sho w to another, we do not know the ordering of stre
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Size: 1858 |
Author: zhoushusen |
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Description: 一1000 MW水电站（机组M1）通过一条500 kV, 700 km的输电线路与负载中心连接。负载中心模型是5000 MW的阻抗负载，由遥远的1000 MW电站和当地的5000 MW (机组 M2)电站供电。系统已经初始化，因此线路传送950 MW，接近它的潮流阻抗负载（SIL = 977 MW）。这两台机相当于一台水轮机和管理(HTG)，励磁系统和电力系统稳定器(PSS)。这三个模块位于“涡轮和调速”子系统中。通过此例，在500 kV系统中制造故障，观察PSS对系统稳定性的影响。-a 1,000 MW hydropower station (crew M1) through a 500 kV, 700 km of transmission line and load center. Load center model is 5,000 MW of load impedance. from the distant 1000 MW power station and the local 5,000 MW (Unit M2) power supply. Is initialized, it transmits 950 MW. closer to its trend of load impedance (SIL = 977 MW). This machine is equivalent to a two hydraulic turbines and Management (HTG), excitation system and the power system stabilizer (PSS). This module is located at 3 "and turbine speed" subsystem. Through this cases, the 500 kV system manufacturing fault, PSS observation of the system stability.
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Size: 13591 |
Author: 卢丹 |
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Description: 包括RS码的编码,硬(BM)/软(KV)译码,AWGN信道调制解调仿真. 具体采用何种编译码方案和调制解调方式可在Profile.txt文件中指定(内有详细说明). 且扩展性极好,容易向其中加入新的调制/解调函数和编/译码函数(具体说明今后会补上)
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Size: 35164 |
Author: ChenQiu |
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Description: 非常仔细的GS算法，用于RS解码过程。是KV算法的基础。包含很多例子。不可多得的关于RS码的资料
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Size: 319462 |
Author: 牛群山 |
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Description: 江民杀毒源代码
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Size: 37027 |
Author: 吴建 |
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Description: 300 km 传输线和功率补偿仿真
The circuit below represents an equivalent power system feeding a 300 km transmission line. The line is compensated by a shunt inductor at its receiving end. A circuit breaker allows energizing and de-energizing of the line. To simplify matters, only one of the three phases is represented. The parameters shown in the figure are typical of a 735 kV power system.
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Size: 6617 |
Author: 楚燕 |
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Description: 电力系统向量和连续暂态分析实例This circuit is a simplified model of a 60 Hz, 230 kV three-phase power system where only one phase is represented.
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Size: 20920 |
Author: 楚燕 |
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Description: This program is to calculate the Reciving End MVA Power for transmission overhead line 220KV
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Size: 4289 |
Author: rabah03 |
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Description: 包括RS码的编码,硬(BM)/软(KV)译码,AWGN信道调制解调仿真. 具体采用何种编译码方案和调制解调方式可在Profile.txt文件中指定(内有详细说明). 且扩展性极好,容易向其中加入新的调制/解调函数和编/译码函数(具体说明今后会补上)-err
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Size: 34816 |
Author: ChenQiu |
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Description: 非常仔细的GS算法，用于RS解码过程。是KV算法的基础。包含很多例子。不可多得的关于RS码的资料-Very carefully the GS algorithm, for the RS decoding process. KV algorithm is the foundation. Contains many examples. Invaluable information on the RS code
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Size: 319488 |
Author: 牛群山 |
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Description: baru ini yang bisa saya upload
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Size: 3756032 |
Author: ferdi |
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Description: ±800 kV特高压直流输电用6英寸大功率晶闸管换流阀-± 800 kV HVDC transmission with six inches high power thyristor valves
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Size: 458752 |
Author: 刘婕 |
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Description: KV-L21V通讯手册modbus RTU(KEYENCE KV-L21V,MODBUS RTU)
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Size: 13442048 |
Author: ding9
|
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Description: 针对kvaser-can卡的labview程序(LabVIEW program for kvaser-can card)
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Size: 689152 |
Author: wxsdd |
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