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用PEG方法生成的围长符合输入要求的规则ldpc码的源程序C语言版。-PEG Generation of Girth accordance with the importation requirements of the source code ldpc C language version.
Update : 2008-10-13 Size : 1.48kb Publisher : 尹浩

LDPC PEG生成校验矩阵。设计性能优良的LDPC码
Update : 2009-03-03 Size : 8.74kb Publisher : ilhxjfe@163.com

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利用PEG算法构造LDPC码的程序c++
Update : 2011-03-01 Size : 1.09mb Publisher : asd05txffh@126.com

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用PEG方法生成的围长符合输入要求的规则ldpc码的源程序C语言版。-PEG Generation of Girth accordance with the importation requirements of the source code ldpc C language version.
Update : 2025-02-17 Size : 1kb Publisher : 尹浩

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根据LDPC码中码子的构造方法中的PEG算法,来就算的最小码距。-LDPC codes under completely different construction method of PEG algorithm, even to the smallest distance code.
Update : 2025-02-17 Size : 96kb Publisher : 微微陈

ldpc码的peg构造,用c++写的,在xp上能够运行成功,是学习peg构造方法和c++编程的非常好的材料。-LDPC code peg construction, with c++ written in xp can be run successfully, is to learn from peg Construction methods and c++ programming very good material.
Update : 2025-02-17 Size : 408kb Publisher : 木木


Update : 2025-02-17 Size : 719kb Publisher : hans

LDPC的密度演化算法,C++写的,执行速度很快。-LDPC density evolution algorithm, C++ written in the implementation of the fast.
Update : 2025-02-17 Size : 10kb Publisher : 李剑

LDPC码H矩阵构造的三种尝试,包括比特填充法、PEG法和近似最短环路法(ACE)的实践-This document includes three methods to implement LDPC H matrix construction. Please enjoy them!
Update : 2025-02-17 Size : 12kb Publisher : david duan

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LDPC码的PEG构造算法,C语言编写。 希望对研究LDPC码的同仁们有所帮助-LDPC codes PEG construction algorithm, C language. Hope that the study of LDPC codes help colleagues
Update : 2025-02-17 Size : 390kb Publisher : xiaomin

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LDPC中消除四环的C源代码,供信道编码的研究者参考-Elimination of the C Ring LDPC source code for channel coding of the researchers refer to
Update : 2025-02-17 Size : 1kb Publisher : zhang li

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LDPC的peg编码算法程序,可以学习下-The peg LDPC coding procedures, can learn under
Update : 2025-02-17 Size : 10kb Publisher : ll

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基于PEG算法的准循环LDPC码构造方法研究-PEG algorithm based on quasi-cyclic LDPC code construction methods
Update : 2025-02-17 Size : 303kb Publisher : zj

Hu Xiaoyu的PEG算法,程序运行时实时显示当前校验矩阵的环长。-Hu Xiaoyu s PEG algorithm, this code can display the cycle girth when runing
Update : 2025-02-17 Size : 782kb Publisher : 李振

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用PEG构造法生成LDPC监督矩阵的程序-With PEG construction method to generate LDPC matrix program oversight
Update : 2025-02-17 Size : 692kb Publisher : 王昆

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ldpc performance testing.
Update : 2025-02-17 Size : 10kb Publisher : chhsi

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ldpc peg C++ code by xiaoyu HU-ldpc peg C++ code by xiaoyu HU
Update : 2025-02-17 Size : 10kb Publisher : asdasd

LDPC-PEG算法构造H矩阵 LDPC码最早在20世纪60年代由Gallager在他的博士论文中提出,但限于当时的技术条件,缺乏可行的译码(PEG Construction Algorithms for LDPC Codes)
Update : 2025-02-17 Size : 1kb Publisher : 程序开发1

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LDPC码编码的PEG算法,亲测代码真实有效(PEG algorithm for LDPC code coding)
Update : 2025-02-17 Size : 1kb Publisher : 特战雪豹

LDPC-PEG算法构造H矩阵源码程序,matlab源码程序 clear all; clc; %输入编码参数,m:校验节点数目,n:变量节点数目(注意码率R不一定为1/2) %构造任意码率的LDPC校验矩阵 m=input('The number of check nodes:'); n=input('The number of variable nodes:'); h=zeros(m,n); %给定变量节点度分布序列 dv=0.38354*x+0.04237*x^2+0.57409*x^3 %为了得到更好的性能,此处的度分布序列采用密度进化理论选取 dv=inline('0.38354*x+0.04237*x.^2+0.57409*x.^3','x'); %计算每个度分布的节点数 indv=quadl(dv,0,1); a2=round(n*(0.38354/2/indv)); a3=round(n*(0.04273/3/indv)); ds(1:a2)=2; ds(a2+1:a3+a2)=3;(LDPC-PEG algorithm constructs H matrix source code program, matlab source code program clear all; CLC; % Input coding parameters, m: number of check nodes, n: number of variable nodes (note that bit rate R is not necessarily 1/2) % Constructing LDPC Check Matrix with Arbitrary Bit Rate M = input ('The number of check nodes:'); N = input ('The number of variable nodes:'); H = zeros (m, n); % Given variable nodal degree distribution sequence DV = 0.38354*x+0.04237*x^2+0.57409*x^3 % In order to get better performance, the density evolution theory is used to select the degree distribution sequence. DV = inline ('0.38354 * x + 0.04237 * X. ^ 2 + 0.57409 * X. ^ 3','x'); % Calculate the number of nodes per degree distribution INDV = quadl (dv, 0, 1); A2 = round (n* (0.38354/2/indv)); A3 = round (n* (0.04273/3/indv); DS (1:a2) =2; DS (a2 + 1: A3 + a2) = 3;)
Update : 2025-02-17 Size : 1kb Publisher : MATLAB编程
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