Description: This section contains a brief introduction to the C language. It is intended as a tutorial on the language, and aims at getting a reader new to C started as quickly as possible. It is certainly not intended as a substitute for any of the numerous textbooks on C. 2. write a recursive function FIB (n) to find out the nth element in theFibanocci sequence number which is 1,1,2,3,5,8,13,21,34,55,…3. write the prefix and postfix form of the following infix expressiona + b – c / d + e * f – g * h / i ^ j4. write a function to count the number of nodes in a binary tr-This section contains a brief introductio n to the C language. It is intended as a tutorial o n the language, and aims at getting a reader new to C started as qu ickly as possible. It is certainly not intended as a substitute for any of the numerous textbook 's on C. 2. write a recursive function FIB (n) to fi nd out the nth element in sequence theFibanocci number which is 1,1,2,3,5,8,13,21,34,55, ... 3. write the prefix and postfix form of the follo wing infix expressiona b-c/d e f*- g* h/i ^ j4. wr ite a function to count the number of nodes in a bi nary tr Platform: |
Size: 22528 |
Author:jim |
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Description: 通过该程序可以计算前缀、中缀和后缀表达式的值。-Through the program can calculate the prefix, infix and postfix expressions value. Platform: |
Size: 375808 |
Author:许娜娜 |
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Description: Java版运算表达式解析器
主要功能:
对有括号的四则运算解析并求解.
支持多种表达式类型
思路:
1.把中缀表达式转化成后缀表达式
2.从后缀表达式得到解
注意:
该版本只支持1.6JDK,如果想替换成1.5JDK改替换LinkedList的几个方法就行了.
详细内容:
http://jomper.javaeye.com/blog/464906-Java version of computing expressions parser main functions: to have the brackets, and four computing analytic solution. Supports a variety of types of ideas the expression: 1. The infix expression into postfix expression 2. Postfix expression is obtained from the solution Note: This version only supports 1.6JDK, If you want to make changes to replace LinkedList replaced 1.5JDK several methods on the list. Details: http://jomper.javaeye.com/blog/464906 Platform: |
Size: 2048 |
Author:jomper |
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Description: 利用栈将中缀表达式转化成后缀表达式并计算-Using the stack to postfix infix expression into an expression and calculate Platform: |
Size: 48128 |
Author:秦朔 |
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Description: 表达式求值是程序设计语言编译中的一个最基本问题。与人们习惯的中缀表示的表达式相比,后缀表达式不存在括号,没有优先级的差别,表达式中各个运算是按照运算符出现的顺序进行的。因此非常适合串行工作的计算机处理方式。该文首先对这两种表达式表示方法进行了分析比较,然后通过具体分析实现这两种表达式求值的算法来论证表达式后缀表示优于中缀表示。最后简要谈一下中缀表达式到后缀表达式的转换。-Evaluation of the expression is a basic problem in the programming language compiler. Compared to people accustomed to infix expressions, postfix expression does not exist in parentheses, no priority difference, the various arithmetic expression is carried out in accordance with the order of appearance of the operator. Therefore very suitable for computer processing of the serial work. In this paper, the analysis and comparison of both expressions representation of these two expressions evaluated algorithm, and then through a concrete analysis to demonstrate that the expression suffix indicates better than infix. Finally, a brief talk about infix expression to postfix expression conversion. Platform: |
Size: 130048 |
Author:逆水之寒 |
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Search - Postfix to infix