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[JSP/JavaiReport+Hibernate+SubReport

Description: 一个ireport+Hibenrate的使用的视频+源代码
Platform: | Size: 24101422 | Author: lifenote | Hits:

[JSP/JavaiReport+Hibernate+SubReport

Description: 一个ireport+Hibenrate的使用的视频+源代码-A ireport+ Hibenrate the use of video+ Source code
Platform: | Size: 24100864 | Author: lifenote | Hits:

[JSP/Javasubreport_tutorial

Description: JasperReport是不错的Java报表工具 subreport_tutorial看完之后你就能了解JasperReport生成的基本过程及原理-JasperReport is a good tool for Java statements subreport_tutorial after reading you will be able to understand the basic process of generating JasperReport and Principle
Platform: | Size: 948224 | Author: 刘永 | Hits:

[CSharpRDLCDR

Description: C#+rdlc 的很多很酷的例子,排序,子报表-c sharp and rdlc reports examples
Platform: | Size: 320512 | Author: 李海生 | Hits:

[Windows Developconvert

Description: 由程序中输入一个合法的后缀式子,将其转化为中缀式-From the program enter a valid suffix subreport, be converted into infix-style
Platform: | Size: 98304 | Author: han | Hits:

[OtherSequenceChangeInPost-sequenceSystem

Description: 輸入一行我們平常在寫的運算式子~用stack方式轉換成後制序列-Enter a line we normally write operations in the subreport ~ with the stack converted into a sequence of post-
Platform: | Size: 1024 | Author: 阿凱 | Hits:

[Otherzhongzhui

Description: 本程序能将运算式从中缀表达式转换为后缀表达式,并计算运算式的值。暂时仅可计算正整数之间的运算。暂时无法处理负数,要计算负数请用 (0-n) 的形式。输入仅含数字0~9及+、-、*、/、(、)的式子,并在结尾处加 # 字作为结束符。-This program can convert an expression from infix expressions to postfix expressions, and calculate the expression value. Calculate the time being, only the operation between the positive integers. Is temporarily unable to process negative, please use to calculate the negative (0-n) form. Input contains only numbers 0 to 9 and+,-,*,/,(,) the subreport, and at the end add# character as a terminator.
Platform: | Size: 52224 | Author: moon walker | Hits:

[OtherTautologiesJudge

Description: 完成判断任意输入的一个式子是否是重言式。c语言实现。-The completion of any input to determine whether a subreport tautology. c language.
Platform: | Size: 1171456 | Author: luye | Hits:

[Mathimatics-Numerical algorithms24dian_1

Description: 每次输入4个数字,程序采用递归算法,打印出第一个符合条件的式子。-Enter 4-digit time, the program uses a recursive algorithm, print out the first one eligible subreport.
Platform: | Size: 1024 | Author: hao | Hits:

[Web ServerCR_DynLoadPics

Description: 水晶功能的实现,子报表的使用,多表连接,和多表但独立的表表关系.-The realization of the crystal function, the use of the subreport, multi-table joins, and multi-table but independent exemplar relations.
Platform: | Size: 80896 | Author: zhou | Hits:

[JSP/JavaPDFJasper

Description: ireport模板生成PDF map数据源 多报表 子报表 分组报表 后台java代码示例-ireport templates to generate PDF map data sources and multiple subreport grouped report java code examples
Platform: | Size: 4096 | Author: xf | Hits:

[Embeded-SCM DevelopSequenceChangeInPost-sequenceSystem

Description: 輸入一行我們平常在寫的運算式子~用stack方式轉換成後制序列-Enter a line we normally write operations in the subreport ~ with the stack converted into a sequence of post-
Platform: | Size: 1024 | Author: pointf | Hits:

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