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Description: 输入三个整数x,y,z，请把这三个数由小到大输出。
1.程序分析：我们想办法把最小的数放到x上，先将x与y进行比较，如果x>y则将x与y的值进行交换，然后再用x与z进行比较，如果x>z则将x与z的值进行交换，这样能使x最小。
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Size: 19456 |
Author: |
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Description: will generate a voxel terrain map and place this data in a 2d array rotate the terrain map data about x,y,z
Platform: |
Size: 9843 |
Author: none |
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Description: OpenGL实现三维绘图 在VC中实现三维交汇图系统演示，主窗口是可以旋转的三维立体坐标系，还可以观察到在x，y，z方向上的投影。-OpenGL 3D graphics in the VC 3D map convergence demonstration, the main window is rotating three-dimensional coordinate system, also can be observed in the x, y, z direction of the projection.
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Size: 545621 |
Author: 黄应 |
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Description: 相关方法:
PictureBox.point(x,y)得到(x,y)点的RGB值
PictureBox.PSet(x,y) z: 设置(x,y)点的颜色为z颜色
不过这里的picture Load进来后要进行转换，因为不是按照像素值来进行的。
-correlation method : PictureBox.point (x, y) be (x, y) of the RGB values PictureBox.PSet (x, y) z : Setting up the (x, y) of the color of color z But the picture here after coming here to Load for conversion, because it is not in accordance with the pixel value to the.
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Size: 2575596 |
Author: 叶叶 |
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Description: Java3D显示空间x，y，z坐标轴，需要安装java3D jdk包！-Java3D show space x, y, z axis, the need to install java3D jdk package!
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Size: 3472 |
Author: 龙之子 |
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Description: 枚举法（穷举法）
“笨人之法”： 把所有可能的情况一一测试，筛选出符合条件的各种结果进行输出。
【例一】百元买百鸡:用一百元钱买一百只鸡。已知公鸡5元/只,母鸡3元/只,小鸡1元/3只。
分析：
这是个不定方程——三元一次方程组问题（三个变量，两个方程）
x＋y＋z=100
5x＋3y＋z/3=100
设公鸡为x-enumeration method (exhaustive) "Benren Regulation" : all possible test of January 1, and selected eligible for the results output. Cases -- 100 yuan to buy a 100 chicken : 100 yuan to buy 100 chickens. Known rooster 5 yuan / only, the hen 3 yuan / only and chicken one yuan / 3. Analysis : This is a volatile equation -- Group 3 linear equation (3 variable, equation 2) x + y + z = 100 5x +3 y + z / 3 = 100 x located rooster
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Size: 559589 |
Author: 林林 |
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Description: 能计算如下表达式：x=3 y=4 z=x^2+sin(y) -expression can be calculated as follows : 3 x = y = z = 4 x ^ 2 sin (y)
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Size: 196696 |
Author: 王箭 |
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Description: 求解定位方程组。并直接利用三元方程求出X,Y,Z时的误差子函数-positioning Solving equations. 3 yuan and the direct use of equations derived X, Y, Z of error Functions
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Size: 2850 |
Author: leaderbbs |
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Description: 一. 能根据需要自由编辑计算公式并得到结果，如编辑(345+345)*3.14+567/34，按“=”按钮即可得到计算结果。
二. 支持二、八、十、十六进制的数据计算。
三. 公式中可以带入最多三个参数，如编辑公式 (x+456)*y+345/z后，给x,y,z赋值，按“=”按钮即可得到计算结果。
四. 附带一个小型的进制转换器，可以使数据在不同的进制间自由转换。
如有意见或建议，或者发现bug，请Email到: zhongnanlifan@163.com
中南大学 计科0304 李凡
QQ：328865226 欢迎交流！-one. According need freedom editorial formula and the outcome, as Editor (345,345) * 3.14 567/34, according to the "=" button can be calculated. 2. Support 2, 8, 10, the hexadecimal data. 3. The formula can bring a maximum of three parameters, such as editorial formula (x 456) 345 * y / z, to x, y, z assigned by the "=" button can be calculated. 4. A small fringe of the band converters, data can be in different band freely switch between. For comments or suggestions, or discover bug, please Email to : zhongnanlifan@163.com Zhongnan University of dollars Li Fan Section 0304 QQ : 328865226 exchange welcome!
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Size: 63009 |
Author: 李凡 |
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Description: 支持X/Y/Z Modem协议的传输文件的通讯程序 -Commnication libraray supports XMODEM,YMODEM,FAX protocol
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Size: 316416 |
Author: 站长 |
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Description: 4.asm…… 响铃程序，输入一个数字字符N，响铃N次。（完成）ysk3.asm ……显示一个星型倒三角。m1.asm ………编程将键盘输入的8位无符号二进制数转化为十六进制数和十进制数，并输出结果form.asm ……采用子程序编程按以下三种格式（██，◣，◥）打印九九乘法表：（完成）char.asm ……小写字母a b c d ……x y z的ASCII码分别为61H 62H 63H 64H……78H 79H 7AH, 而大写字母A B C D ….X Y Z的ASCII码分别为41H 42H 43H 44H …58H 59H 5AH， 使用串处理指令编程从键盘输入16个字符（大小写字母及其它字母均有）， 存入以BUF1开始的一片存储区中，并将其传送到以BUF2开始的一片存储区中， 在传送是将其中的小写字母均改为大写字母，并将第一个小写字母在串中的位置 （距串头BUF1的相对位移量）以十六进制形式输出。（完成）-4.asm ... ... beep procedures, the importation of a number of characters N, N-beep. (Completed) ysk3.asm ... shows a Star inverted triangle. ... ... M1.asm programming to the keyboard input of eight unsigned binary number into a hexadecimal number and decimal number, and the output form.asm ... using subroutine program by the following three formats ( , TT, Short) Print Jiujiuchengfabiao : ( completed) char.asm ... lowercase letters a b c d ... x y z ASCII respectively 61H 62H 63H 64H 78H 79H ... 7AH and capital letters A B C D .... X Y Z ASCII respectively 41H 42H 43H 44H 58H 59H L1.5AH ..., the use of string processing programming instructions from the keyboard 16 characters (letters and other case-sensitive alphanumeric both), credited to BUF1 started a storage area and its transmission
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Size: 3072 |
Author: 冯萍 |
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Description: 绘制机器人
移动，整体旋转，手臂旋转。手肘旋转，行走
可以把机器人分别沿X,Y,Z方向缩放，也可以变成点模式线模式，面模式
有光照选项-mobile robot, the overall rotation, arm rotation. Elbow rotation, robot can walk along X, Y, Z direction zoom, can also become models point line model, Light-mode option
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Size: 192512 |
Author: gloria |
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Description: 本程序中利用了一个可用于有限空间内三维成像的简易算法。根据有限空间中底面上所有采样点在三维笛卡儿空间内的坐标（x，y，z），然后将其转换为计算机屏幕上的像素点的坐标（x，y），从而绘制出具有真实立体感的图像。实践证明，利用此算法可以很方便地在计算机屏幕上绘制任意旋转的三维图像。-the use of the procedure can be used to a limited space within 3D imaging of simple algorithm. According to the limited space the end of all surface sampling points in 3D space within the Cartesian coordinates (x, y, z), then be converted into computer on the screen coordinates of the pixel (x, y), thus drawn with a real sense of three-dimensional images. Practice has proved that this algorithm can be used conveniently on the computer screen drawing arbitrary rotation of three-dimensional image.
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Size: 1391616 |
Author: 刘洋 |
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Description: 试写一算法，如果三个整数x,y,z的值是依次非递增的，侧通过交换令其为非递增。
要求实现下列函数：
void Descend(int &x, int &y, int &z)
/* 按从大到小顺序返回x，y和z的值 */-Try to write a algorithm, if the three integers x, y, z values are followed by non-incremental, side by exchanging them for non-incremental. Requirements to achieve the following function: void Descend (int
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Size: 1024 |
Author: ln |
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Description: 实现最优二叉树的构造；在此基础上完成哈夫曼编码器与译码器。 假设报文中只会出现如下表所示的字符：
字符 A B C D E F G H I J K L M N
频度 186 64 13 22 32 103 21 15 47 57 1 5 32 20 57
字符 O P Q R S T U V W X Y Z ， ．
频度 63 15 1 48 51 80 23 8 18 1 16 1 6 2
要求完成的系统应具备如下的功能：
1．初始化。从终端（文件）读入字符集的数据信息，。建立哈夫曼树。
2．编码：利用已建好的哈夫曼树对明文文件进行编码，并存入目标文件（哈夫曼码文件）。
3．译码：利用已建好的哈夫曼树对目标文件（哈夫曼码文件）进行编码，并存入指定的明文文件。
4．输出哈夫曼编码文件：输出每一个字符的哈夫曼编码。
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Size: 132096 |
Author: 张娟 |
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Description: x,y,z,Modem协议实现的源码－C语言-x, y, z, Modem protocol source-C Language
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Size: 7168 |
Author: amo73 |
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Description: 在三维空间中画泡泡,可以指定在三维空间中的x,y,z的坐标以及泡泡的半径r和颜色c(RGB).-BUBBLEPLOT3(x,y,z,r), where x, y, z and r are four vectors of the
same length, plots bubbles of radii r in 3-space with centers at
the points whose coordinates are the elements of x, y and z. If r
is a matrix of size numel(x)x3, BUBBLEPLOT3 produces ellipsoids with
centers x(i),y(i),z(i) and radii r(i,1), r(i,2) and r(i,3).
BUBBLEPLOT3(x,y,z,r,c), where c is a rgb-triplet array (in [0,1])
with numel(x) rows, plots bubbles with colours specified by c.
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Size: 3072 |
Author: zha |
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Description: Create DXF Autocad 12 format from a text file that contains xyz coordinates of points
two format is supported no,x,y,z and no,x,y,z,code for input files
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Size: 13312 |
Author: bob |
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Description: 在屏幕上任意绘制一个多边形，在计算机内将其表示为一个以此多边形为底面的正n边棱柱(指定高度)，棱柱的各面具有不同的颜色。
用Z-Buffer算法做面消隐；
允许以棱柱中心为固定点，通过输入x, y, z方向的转动角度实现任意角度的旋转(或通过鼠标操作实现任意角度的旋转) ；
投影方式：正平行投影，并假设物体始终在裁剪空间内；-On the screen draw an arbitrary polygon, within the computer as a polygon of its represented as a positive for the bottom side of the prism n (specified height), the prism of each side has a different color. Z-Buffer algorithm is used to do face hidden allowed to prism center fixed point, by entering the x, y, z direction of the rotation angle to achieve any angle of rotation (or through the mouse to achieve any angle of rotation) projection mode: Positive parallel projection, and assuming that objects are always cutting space
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Size: 2112512 |
Author: 一个新名字 |
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Description: 输入两个字数据（16位的数）X,Y，计算Z=X+Y-Enter the word data (number 16) X, Y, Z = X+Y calculated
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Size: 1024 |
Author: 红尘_Sky |
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