Search - acm Optimal Servic

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[Other] OptimalServices DL : 0: acm算法设计描述：设有n 个顾客同时等待一项服务。顾客i需要的服务时间为ti ,1 < = i < = n 。应如何安排n个顾客的服务次序才能使平均等待时间达到最小?平均等待时间是n 个顾客等待服务时间的总和除以n。对于给定的n个顾客需要的服务时间，编程计算最优服务次序。输入：第一行是正整数n，表示有n 个顾客。接下来的1行中，有n个正整数，表示n个顾客需要的服务时间。输出：最小平均等待时间例输入： 10 56 12 1 99 1000 234 33 55 99 812 例输出： 532.00 -acm algorithm design Description: n has a customer waiting for a service at the same time. I need to service customers time ti, 1 < = i < = n. N how to arrange the order of a customer' s service to make the average waiting time to a minimum? Average waiting time is n-time customers wait for service by dividing the sum of n. N for a given month of the service needs of customers, the best services to the order of the calculation program. Input: the first line is a positive integer n, that there are n customer. 1 the next line, there is a positive integer n, that n of the service needs of customers. Output: the minimum average waiting time for cases of type: 10 56 12 1 99 1000 234 33 55 99 812 cases Output: 532.00
Date : 2025-07-02 Size : 229kb User : 张波