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Description: 虚拟机程序，实现的功能：
1.支持A，G，R，D，E，U，T，P等命令；
2.可读入.ASM汇编文件或者.COD二进制文件执行；
3.可选择不同的运行方式（全速，单指令，单微指令，暂停）；
4.支持中断实验（三级中断源），可以设定中断向量；
5.支持指令集与微指令集的动态扩充；
6.控件动态显示所有重要信号与数据状态（部分控件可点击）；-virtual machine procedures, functions : 1. Support A, G, R, D, E, U, T, P, etc. orders; 2. Readable income. ASM or compilation. COD binary implementation; 3. Choice of different operating mode (full speed, single-instruction, single microinstruction suspended); 4. Experimental support interruption (3 interrupt source), can set interrupt vector; 5. support instruction set with the task of collection of dynamic expansion; 6. Dynamic Display controls all important signals and data state (Department Control points can click);
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Size: 2290894 |
Author: 安黎 |
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Description: 解决时钟问题，acm竞赛题
A weird clock marked from 0 to 59 has only a minute hand. It won t move until a special coin is thrown into its box. There are different kinds of coins as your options. However once you make your choice, you cannot use any other kind. There are infinite number of coins of each kind, each marked with a number d ( 0 <= 1000 ), meaning that this coin will make the minute hand move d times clockwise the current time. For example, if the current time is 45, and d = 2. Then the minute hand will move clockwise 90 minutes and will be pointing to 15.
Now you are given the initial time s ( 0 <= s <= 59 ) and the coin s type d. Write a program to find the minimum number of d-coins needed to turn the minute hand back to 0.-clock to solve the problem, acm contest A weird clock marked from 0 to 59 has only a minute hand. It won t move until a special coin is thrown into its box. There are different kinds of coins as your options. However once you make your choice, you can not use any other kind. There are infinite number of coins of each kind, each marked with a number d (0 lt; = 1000), meaning that this coin will make the minute hand move clockwise d times the current time. For example, if the current time is 45, and d = 2. Then the minute hand will move clockwise 90 minutes and will be pointing to 15. Now you are given the initial time s (0 lt; s = lt; = 59) and the coin s type d. Write a program to find the minimum number of d-coins needed to turn the minute hand back to 0.
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Size: 1308 |
Author: 王冠 |
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Description: 数字电压表
AD芯片：
采用8位串行A/D转换器ADC0832。
● 8位分辨率，逐次逼近型，基准电压为 5V
● 5V单电源供电
● 输入模拟信号电压范围为 0～5V
● 有两个可供选择的模拟输入通道
显示：
使用三个数码管。
显示范围：
0.00 － 5.10 （单位：V）
连接方式：
AD_CLK → P1.0
AD_DAT → P1.1
AD_CS → P3.4
模拟输入 → CH0
(AD_DAT = DO + DI)
ADC0832输出最大转换值＝FFH (255)
设定最大测量值＝5.1V
255X=5.1 X=0.02 即先乘2再除以100
（小数点放在第三位数码管）- Digital voltmeter
AD chip: Uses 8 serial A/D switch ADC0832. * 8 resolution,
gradually approaching, the datum voltage is 5V * the 5V single power
source power supply * input simulated signal voltage scope is 0 ~ 5V *
has two to be possible to supply the choice the analog input channel
Demonstrated: Uses three digital tubes.
Demonstrates the scope: 0.00 - 5.10 (unit: V)
Connection way:
AD_CLK -> P1.0 AD_DAT -> P1.1 AD_CS -> P3.4 analog input -> CH0
(AD_DAT = DO DI)
ADC0832 output biggest transformation value = FFH (255)
establishes greatest observed value = 5.1V 255X=5.1 X=0.02 namely
first to ride 2 to eliminate again by 100 (decimal point puts on third
digital tube)
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Size: 7924 |
Author: lmhit |
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Description: This a set of notes I put together for my Computer Architecture
class in 1990. Students had a project in which they had to model a
microprocessor architecture of their choice. They used these notes to
learn VHDL. The notes cover the VHDL-87 version of the language.
Not all of the language is covered (about 95％).
You may use this booklet for your own personal learning purposes.
You may not use it for profit (eg, selling copies of it, using it in a
course for which people pay, etc). If you want to make use of it
beyond these conditions, contact me and we can come to some
arrangement.
-This a set of notes I put together for my Co. mputer Architecture class in 1990. Students ha d a project in which they had to model a microproc essor architecture of their choice. They used t hese notes to learn VHDL. The notes cover the Volume L-87 version of the language. Not all of the lang uage is covered (about 95%). You may use this boo klet for your own personal learning purposes. Y ou may not use it for profit (eg, selling copies of it, using it in a course for which people pay, etc). If you want to make use of it beyond these co nditions. contact me and we can come to some arrangement.
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Size: 245947 |
Author: 罗春晖 |
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Description: This is a set of notes I put together for my Computer Architecture
class in 1990. Students had a project in which they had to model a
microprocessor architecture of their choice. They used these notes to
learn VHDL. The notes cover the VHDL-87 version of the language.
Not all of the language is covered (about 95％).
-This is a set of notes I put together for my Co. mputer Architecture class in 1990. Students ha d a project in which they had to model a microproc essor architecture of their choice. They used t hese notes to learn VHDL. The notes cover the Volume L-87 version of the language. Not all of the lang uage is covered (about 95%).
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Size: 238174 |
Author: 罗春晖 |
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Description: Visual.C++编程技巧精选500例随书附盘
第1章 消息框
1.消息框设置演示
第2章 常用控件
13.如何使用picturebox 控件浏览多种格式的图像？
12.如何使listcontrol控件支持整栏选择？
11.如何在列表框中自动装载磁盘文件列表？
10.如何显示载有richedit 控件的对话框？
9.如何限制编辑控件输入的字符类型？
8.如何在程序窗口中创建按钮控件？
7.按钮设置演示
6.如何使用滚动条控件？
5.如何使用进度条控件？
4.如何使用列表控件？
3.如何使用树形控件？
2.如何使用标签控件？
1.如何使用滑块控件？
第3章 通用对话框
8.如何在程序启动时弹出文件打开对话框？
7.如何在文件对话框中预览位图文件？
6.文件对话框文件夹操作演示
5.文件对话框使用演示
4.如何使用查找与替换对话框？
3.如何使用页面设置对话框？
2.如何使用颜色对话框？
1.如何使用字体对话框？
第4章 标题栏与菜单栏
26.如何在子菜单中记录历史文件？
25.如何确定顶层菜单所占的行数？
24.如何取消对菜单状态的限制？
23.如何取消应用程序菜单栏？
22.如何获取菜单栏高度？
21.如何在对话框类型的应用程序中加载菜单？
20.如何设计自定义快捷菜单？
19.如何创建一个弹出式菜单？
18.如何触发一个菜-Visual.C programming skills selected 500 cases with Disks Chapter 1 of a news box. Speech news box set Chapter 2 of said common control 13. how to use the picturebox control View Multi-Format Image? 12. How listcontrol Control supportive of the whole column choice? 11. How the list box automatically loading disk document lists? 10. How to show contains dialog richedit controls? 9. How to restrict the importation of editorial control character type? 8. How to create window control buttons? 7. Button to display six. How to use the scroll controls? 5. How to use the progress of control? 4. How to use control list? 3. How to use tree controls? 2. How to use the label control? 1. How to use slider controls? Chapter 3 common dialog 8. How commencement of the proceedings while the document open d
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Size: 22677475 |
Author: lueying |
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Description: Securing Apache 2: Step-by-Step
When choosing a web server, Apache very often wins against its competitors because of stability, performance, that fact that it s open source, and many other advantages. But when deciding on which version of Apache to use, the choice is not always so simple. On the one hand there is a very popular, stable version used by millions of users, version 1.3, and on the other hand, there is an enhanced and re-designed version 2.0. -Securing Apache 2 : Step-by-Step When choosing a web server, Apache very often wins against its competitors because of stability, performance, that fact that it's open source, and many other advantages. But when deciding on which version of Apache to use, the choice is not always so simple. On the one han d there is a very popular, stable version used by millions of users, version 1.3, and on the other hand, there is an enhanced and re-designed version 2. 0.
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Size: 16396 |
Author: stoneson |
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Description: 功能：使用CCU的4个模块，实现非对称PWM输出。
说明：将跳线器J5、J6、J27取出，J3短接到OCD端，在JP6的PWM1、PWM2、PWM3
分别测试模块A、B、C的输出，DAOUT是模块D输出经漏波后的电压。
通过跳线器J8、J9选择高频晶振6MHz。
-function : the use of CCU's four modules, achieving non-symmetric PWM output. Note : All of the jumper J5 and J6, J27 Retrieve, J3 received OCD short end of the JP6 PWM1. PWM2, PWM3 tested modules A, B, C output, DAOUT D output module is missed by the voltage wave. Devices placed by the jumper, J9 choice of high frequency oscillator 6MHz.
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Size: 1149 |
Author: allen |
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Description: 1）实现以下常用的内部排序算法并对它们的时间效率进行比较：
必做（6种）：起泡排序、直接插入排序、简单选择排序、快速排序、希尔排序、堆排序；
选做：折半插入、二路归并、基数排序等等；
2）函数首部要求：void XXXXSort(char **list, int len, int n, int *c, int *s)
其中：
a) XXXXSort为排序函数名，具体如下：
起泡排序BubbleSort
直接插入排序InsertSort
简单选择排序SelectSort
快速排序QuickSort
希尔排序ShellSort
堆排序HeapSort
折半插入BInsertSort
二路归并Merge2Sort
基数排序RadixSort
b) list为二维字符数组的头指针，该二维数组的规格为：char list[n][len] 每行用于存放一个字符串（最大长度为len-1），共n行；
c) c用于返回关键字比较次数；
d) s用于返回移动次数；
3）要求把各种排序函数做成函数库（文件名统一为：sort.c），用统一提供的主程序进行调用和测评。
-a) achieve the following commonly used internal sorting algorithm as well as their time efficiency comparison : regimen (6) : bubble sort, direct insertion sequence and simple choice sorting, quick sort, Hill, ranked Heap Sort; elected to do : half of insertion, two-way merge. Sort base, and so on; 2) function first requirement : void XXXXSort (char ** list, int len, int n, int * c, int * s) which : a) XXXXSort sort of a function name, as follows : bubble sort BubbleSort direct insertion sort InsertSort simple choice ranking Sele ctSort Quick Sort QuickSort Hill Sorting ShellSort Heap Sort HeapS ort half insert BInsertSort two-way merge Merge2Sort radix sort Radi xSort b) list for the two-dimensional array of characters in the first indicator, the two-dimensional array specifications : cha
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Size: 10289 |
Author: 战天 |
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Description: 射线选择演示
通过使用glunproject(), 可以将平面的2D坐标,转换成空间的3D坐标.
所以我们使用glunproject()将鼠标的光标坐标转换成空间的坐标,这样就可以实现鼠标的选取
-ray choice demonstration through the use of glunproject (), can be a 2D plane coordinates, converted into space for the three D coordinates. So we use glunproject () to the mouse cursor coordinate conversion into space coordinates, we can choose the mouse
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Size: 113019 |
Author: hmn |
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Description: 3D mark 2003样式的按钮控件，替换CButton的理想选择-style button controls, replacing an ideal choice CButton
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Size: 253952 |
Author: 杨勋宇 |
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Description: AD876是由AD公司生产的10位20M的A/D转换芯片。两种供电3。3V和5V选择。160MW低功耗。28PIN的SSOP或者SOIC封装。本人花了1周时间调试。程序为KEIL C环境。特与大家分享。-AD876 is produced by the AD 10 41 A/D conversion chip. Two power supply 3. 3 V and 5 V choice. Low power consumption of 160 MW unit. 28PIN the SSOP or SOIC packaging. I spent a week debugging time. KEIL C procedures for the environment. Special share with you.
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Size: 873472 |
Author: goldman |
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Description: 非常不错得js得日期选择控件，外观漂亮实用。已经在多个项目中使用。-Js a very good choice of a date for controls, the appearance of a beautiful and practical. Has been implemented in many projects.
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Size: 268288 |
Author: mengoo |
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Description: 本人非常支持单片机设计DIY 在这里再次献出小弟的一点心意,下面是使用AT89S52驱动74HC4015,实现1选择8的数据通道切换器,可以在不8个通道出加上不同大小的电阻.可以用来单声道音量的大小控制.
下面作品图是小弟设计的廉价的 基于单片机的毕业设计 ,它还使用了无线接收发送模块,通过使用手上的遥控器能控制音量的大小,还加了一块HCF4052用于输入音道的选择,支持思路音频信号的输入,一路音频信号的输出:
-I very much support the single-chip design DIY here again gave a little boy s mind is to use the following AT89S52 drive 74HC4015, to achieve a choice of 8 switches the data channel, you can not add the 8-channel resistance of different sizes. Can used to the size of mono volume control. The following work plan is designed小弟cheap graduation based on single-chip design, it uses the wireless receiver send module, through the use of the hands of the remote control can control the volume size, but also Add a piece of HCF4052 Road for the importation of sound choices, to support the idea of audio signal input, the output audio signal all the way:
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Size: 84992 |
Author: 彬 |
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Description: 网上找到的LED模拟显示,都只能显示数字和字母.但我这个是可以显示简繁体中文的.可以调节显示的点数象素,还有显示速度选择.-Online to find the LED analog display can only display numbers and letters. But I can show this is simplified and traditional Chinese. It can adjust the display pixel points, but also show the speed of choice.
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Size: 235520 |
Author: vodchina |
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Description: 某次考试有20个单项选择题，下面是这20个题的正确答：
//* 1.B 2.D 3.A 4.A 5.C 6.A 7.B 8.A 9.C 10.D
//* 11.B 12.C 13.D 14.A 15.D 16.C 17.C 18.B 19.D 20.A
//* 采用数组存储上述20个标准答案，要求用户输入考生的答
//* 案，并采用另一个数组存储，程序显示该生是否通过考试，
//* 并显示考生答错的题数和题号。-A second examination 20 multiple-choice individual, the following is the correct title 20 Answer://* 1.B 2.D 3.A 4.A 5.C 6.A 7.B 8.A 9.C 10.D//* 11.B 12.C 13.D 14.A 15.D 16.C 17.C 18.B 19.D 20.A//* using an array of storage above 20 standard answer that requires a user to Enter the candidate s FOR//* case, and uses another array to store, process shows whether the student passed the exam,//* and display the number of candidates got the wrong answer and the question of its title.
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Size: 1024 |
Author: yann |
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Description: 这个是用系统时间产生随机数应用的一个小程序，用到了J2ME底层绘图机制。功能：在你输入4个选项后，系统自动筛选出一个结果。就像考试时a,b,c,d四个选项瞎蒙出来一个-This is the system time with the application of random numbers generated in a small procedure, use the bottom of the drawing mechanism of the J2ME. Function: you input at four options, the system automatically filter out a result. Examinations as a, b, c, d four options out of a blind Monte ... ...
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Size: 1024 |
Author: jessie |
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Description: DICOM3DSDK开发包是一套专业的PACS系统开发工具，包括DICOM协议和影像处理两大部分，它的特点是使用方便、功能强大、适应性强，是快速开发PACS的理想选择，该版本包括DICOM_Strings, DICOM_Table, DICOM_Printers, DICOM_ImageFile, DICOM_Network, DICOM_ImageViewer, DICOM_FilmBox, DICOM_IconBar, DICOM_DicomDir, DICOM_SDKRegister等控件。-The DICOM3DSDK development package is a set of specialized PACS development tool kit, including two major parts of DICOM propotol and the image process,its characteristic is easy to operate and its function is formidable and compatible, So it is a ideal choice develops PACS fast, This version include the controls of DICOM_Strings, DICOM_Table, DICOM_Printers, DICOM_ImageFile, DICOM_Network, DICOM_ImageViewer, DICOM_FilmBox, DICOM_IconBar, DICOM_DicomDir, DICOM_SDKRegister.
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Size: 14922752 |
Author: xianing |
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Description: CHOICE.EXE
在纯 DOS 下可以使用 CHOICE 这个命令，但在 Windows 下由于没有 CHOICE.EXE 这个程序，所以不能执行 CHOICE.EXE 命令。在 Windows 下要正常使用 CHOICE 这个命令就必须有这个文件，这是我收集的多个操作系统的 CHOICE.EXE 文件。注 X86 表示 32 位系统，X64 表示 64 位系统。
-CHOICE.EXE in pure DOS can use the CHOICE command, but for the absence of CHOICE.EXE under Windows, we can not use the command. This is my collection of a number of operating system files CHOICE.EXE. Note that the X86 means 32bit systems, while X64, the 64-bit systems.
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Size: 69632 |
Author: 邹勇卿 |
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Description: The Tcl Dev Kit (TDK) 5.02 provides essential tools for Tcl programmers, making it easy to create, build and deploy applications. Rapidly deploy Tcl applications to a broad range of platforms, as ready-to-run executables, starkits or tarpacks. Simplify development with tools for finding and fixing bugs, managing complex code bases, and optimizing your programs. Take control and work the way you want with a choice of GUIs or command line interfaces for most tools.
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Size: 38673408 |
Author: TopQuark |
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