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Description: using System
using System.Runtime.InteropServices
namespace JustinIO {
?class CommPort {
??public string PortNum
??public int BaudRate
??public byte ByteSize
??public byte Parity // 0-4=no,odd,even,mark,space
??public byte StopBits // 0,1,2 = 1, 1.5, 2
??public int ReadTimeout
??
??//comm port win32 file handle
??private int hComm = -1
??
??public bool Opened = false
??
??//win32 api constants
??? private const uint GENERIC_READ = 0x80000000
??? private const uint GENERIC_WRITE = 0x40000000
??? private const int OPEN_EXISTING = 3 ??
??? private const int INVALID_HANDLE_VALUE = -1
-using System using System.Runtime.InteropServices
Namespace JustinIO {? Class CommPort {
? ? Public string PortNum? ? Public int BaudRate? ? Public byte
ByteSize? ? Public byte Parity // 0-4=no, odd, even, mark, space? ?
Public byte StopBits // 0,,1,2 = 1, 1.5, 2? ? Public int ReadTimeout?
? ? ? //comm port win32 file handle? ? Private int hComm = -1? ? ? ?
Public bool Opened = false? ? ? ? //win32 api constants? ? ? Private
const uint GENERIC_READ = 0x80000000? ? ? Private const uint
GENERIC_WRITE = 0x40000000? ? ? Private const int OPEN_EXISTING = 3? ?
? ? ? Private const int INVALID_HANDLE_VALUE = -1? ?
Platform: |
Size: 9142 |
Author: liucheng |
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Description: 基于DOS的多任务系统的实现
1. 用C语言完成线程的创建和撤消，并按优先权加时间片轮转算法对多个线程进行调度；
2. 改变时间片的大小，观察结果的变化。思考：为什么时间片不能太小或太大；
3. 假设两个线程共用同一软件资源（如某一变量，或某一数据结构），请用记录型信号量来实现对它的互斥访问；
4. 假设有两个线程共享一个可存放5个整数的缓冲，一线程不停的计算1到50的平方，并将结果放入缓冲中，另一个线程不断的从缓冲中取出结果，并将他们打印出来，请用记录型信号量实现这一生产者和消费者的同步问题；
5. 实现消息缓冲通信，并于3，4中的简单通信进行比较；
6. 思考：在线程间进行消息缓冲通信时，若对消息队列的访问没有满足互斥要求，情况会怎么样？-DOS-based multi-tasking system in a. C language to complete the creation and thread lift Priority increase as time slice Web algorithm for multiple-thread scheduling; 2. change the timing of the unit size, The results change. Thoughts : Why not films too little time or too much; 3. Assuming two threads to share the same software resources (such as a variable, or a data structure), with record-volume signal to achieve its exclusive interviews. 4. Suppose two threads share a deposit of five integer buffer keep a thread of 1-50 calculating the square, and the results Add buffer, Another constant thread removed from the buffer, and print them out, Please record-volume signal achieve this producers and consumers synchronization; 5. Implementation news buffer communications, and 3, 4 simple comm
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Size: 4139 |
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Description: The code, images and designs for this book are released under a Creative Commons Attribution-NonCommercial-ShareAlike 2.5 License.
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*Any of these conditions can be waived if you get permission from the copyright holder.
CONTACT ME
Please address any questions to info@andybudd.com.-The code, images and designs for this book are released un der a Creative Commons Attribution- NonCommer Reconciliation- ShareAlike 2.5 License. http :// creativecommons.org/licenses/by-nc-sa/2.5/You are free :* to copy, distribute, display, and perform the work* to make derivative works U nder the following conditions :* Attribution. You must attribute the work in th e manner specified by the author or licensor.* N oncommercial. You may not use this work for comm ercial purposes.* Share Alike. If you alter, transform, or build upon this work, you may distribute the resulting work only unde r a license identical to this one.* For any reuse or distribution. you must make clear to others the license terms o f this work.* Any of these conditions can be waiv ed if you get pe
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