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Description: 卡尔曼滤波器matlab源代码。 function [Y,PY,KC]=myKalman(x,A,B,Q,H,R,y0,P0) 这是我课程设计时做的。-Source code of kalman filter using matlab. function [Y,PY,KC]=myKalman(x,A,B,Q,H,R,y0,P0) This is made by me for my course design。
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Size: 1229 |
Author: 王卫 |
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Description: 卡尔曼滤波器matlab源代码。 function [Y,PY,KC]=myKalman(x,A,B,Q,H,R,y0,P0) 这是我课程设计时做的。-Source code of kalman filter using matlab. function [Y,PY,KC]=myKalman(x,A,B,Q,H,R,y0,P0) This is made by me for my course design。
Platform: |
Size: 1024 |
Author: 王卫 |
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Description: NEC 78K0-KC2 系列单片机demo 源码-NEC 78K0-KC2 Series MCU demo source code
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Size: 17408 |
Author: huang |
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Description: 用局部参数最优化方法设计一个模型参考自适应系统,可调增益的初值Kc(0)=0.2，给定值r(t)为单位阶跃信号，即r(t)=A×1(t)。
要求：
1把连续系统离散化(采样时间可取0.1)。
2编制并运行这个系统的计算机程序(注意调整B值，使系统获得较好的自适应特性)。
3记录ym、yp的曲线 记录kp×kc的曲线 记录广义输出误差e的变化曲线。
4在参数收敛后，让Kp=2变为Kp=1，重新观察Kp×Kc及e的变化曲线。
5找出在确定的B值下，使系统不稳定的A值(阶跃信号的幅值)，并与用劳斯稳定判据计算的结果比较。
-With local parameter optimization method to design a model reference adaptive system, adjustable gain initial Kc (0) = 0.2, for a given value of r (t) for the unit step signal that r (t) = A × 1 ( t). Requirements: a continuous system discretization (sampling time of 0.1 preferred). 2 compiled and run the system computer program (Note B to adjust the value of the system to obtain better adaptive characteristics). 3 records ym, yp curve record kp × kc curve records generalized output error e curves. 4 parameter convergence, let Kp = 2 into the Kp = 1, re-observed Kp × Kc and e curves. B-5 to find value in determining the next, making the system unstable A value (step signal of amplitude), and using Routh stability criterion and the comparison of the results calculated.
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Size: 1024 |
Author: yk |
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Description: 为了满足市场对于人才招聘解决方案的需求，推出了网上人才招聘解决方案。作为一种专业化的业务流程改进工具，有效地解决了人才招聘工作效率和效果改进提升中所面临的问题。-In order to meet the market solution for recruitment needs, the introduction of online recruitment solutions. As a professional business process improvement tools to effectively address the recruitment of talent to enhance the efficiency and effectiveness in improving the problems faced.
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Size: 737280 |
Author: 李玮 |
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Description: 利用区间树实现简易课表管理系统 内有课表范例-Summary schedule of interval tree management system to achieve
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Size: 773120 |
Author: 孙奇 |
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Description: 扩散系统之浓度分布的装置。管中储放静止液体B，高度为L=10 ㎝，放置于充满A 气体的
环境中。假设与B 液体接触面之浓度为3
C 0 0.01mol m A = ，且此浓度不随时间改变
而改变，即在操作时间内( h = 10天)维持定值。气体A 在液体B 中之扩散系数为
D m s AB
= 2×10− 9 2 。试决定以下两种情况下，气体A溶于液体B中之流通量(flux)。
(a) A 与B 不发生反应；
(b) A 与B 发生以下之反应
A+ B→C ， A A − r = kC
其反应速率常数k = 2×10− 7 s− 1。
-Diffusion system of concentration reference device shown in Figure 3. Tube in the store still liquid B, L = 10 cm height, placed in full A gas environment. Assuming the contact surface of the liquid with the B concentration of 3 C 0 0.01mol m A =, and this concentration does not change with time and change, that is, the operating time (h = 10 days) to maintain constant. Gas A in liquid B, the diffusion coefficient D ms AB = 2 × 10-9 2. Decided the following two test cases, the gas dissolved in liquid B in the A liquid (flux). (A) A and B do not react (b) A and B of the following reaction occurs A+ B → C, AA- r = kC, the reaction rate constant k = 2 × 10-7 s-1.
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Size: 3072 |
Author: zhouyanghua |
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Description: 新安江模型VB代码, 新安江模型，欢迎大家提出各种宝贵意见，以完善该程序，还缺少参数率定的程序，谁写过了？可以分享一下吗？-xinanjiang vb code
Option Explicit
Private Sub Command1_Click()
Dim P(366) As Single, E(366) As Single, PE(366) As Single
Dim P1(366) As Single, P2(366) As Single, P3(366) As Single, P4(366) As Single
Dim E0(366) As Single, Ep(366) As Single
Dim EU(366) As Single, EL(366) As Single, ED(366) As Single
Dim WU(366) As Single, WL(366) As Single, WD(366) As Single, W(366) As Single
Dim Q(366) As Single, R(366) As Single, sumR As Single, sumQ As Single
Dim i As Integer, Kc As Single, WMM As Single, a(366) As Single
Const WUM 20, WLM 60, WDM 60
Const C 0.16
Platform: |
Size: 7168 |
Author: 潘娅英 |
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