Description: 对图像进行拉普拉斯变换，边缘检测，现有Sobel算子计算二阶差分，再由内核做卷积-Laplace transform of images, edge detection, Sobel operator calculation of the existing second-order difference, and then by the convolution kernel to do Platform: |
Size: 151552 |
Author:方方 |
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Description: 有限差分法求解有两种介质的正方形区域的二维拉普拉斯方程的数值解-Finite difference method, there are two medium square region of two-dimensional numerical solution of Laplace equation Platform: |
Size: 1024 |
Author:姜枫 |
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本程序是用五点差分格式解拉普拉斯方程，采用MATLAB作为开发环境，拉普拉斯方程有广泛的应用，五点差分格式的精度高
-This procedure is a five-point difference scheme for solution of Laplace equation, using MATLAB as a development environment, Laplace equation has a wide range of applications, a five-point difference schemes of high accuracy Platform: |
Size: 1024 |
Author:马冠男 |
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Description: 由于噪声点(灰度与周围点相差很大的点)对边沿检测有一定的影响，所以效果更好的边沿检测器是高斯拉普拉斯(LOG)算子。它把我们在第3章中介绍的高斯平滑滤波器和拉普拉斯锐化滤波器结合了起来，先平滑掉噪声，再进行边沿检测，所以效果会更好。-As the noise points (points, a big difference with the surrounding gray points) on the edge detection to a certain extent, the effects are therefore a better edge detector is the Laplace Gaussian (LOG) operator. It is our described in Chapter 3 of the Gaussian smoothing filter and Laplacian sharpening filter combines first smooth out the noise, and then to edge detection, it would be more effective. Platform: |
Size: 124928 |
Author:zoubinbin |
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Description: In this code the laplace equation is solved by iterative method.For solving matrix of unknowns a method like Jacubi method is used that dependet to little difference between iterations for convergence. Platform: |
Size: 1024 |
Author: |
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In this code the laplace equation is solved by iterative method.For solving matrix of unknowns a method like Jacubi method is used that dependet to little difference between iterations for convergence.
Platform: |
Size: 4096 |
Author: |
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Description: 一中空的横截面为正方形的长导体盒，与横截面垂直的方向上可认为是无限长。用求解横截面上电位的差分法和超松弛迭代计算拉普拉斯方程，-A hollow cross-section of a long conductor of square boxes, vertical cross-sectional direction can be considered infinitely long. Calculation of the Laplace equation by solving the cross section of the potential difference and over relaxation Platform: |
Size: 12288 |
Author:ckj |
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Description: 用五点差分公式数值求解了一个laplace方程，改编后可以用于求解其他laplace方程-Five-point difference formula for numerical solution of a laplace equation can be used to solve other laplace equation adapted Platform: |
Size: 1024 |
Author:小蒋 |
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Description: 用拉普拉斯变换差分法求解试井分析中的一维渗流问题-Laplace transform difference method for solving one-dimensional flow problem in well test analysis Platform: |
Size: 260096 |
Author:li |
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Description: 利用拉普拉斯变换的思想，通过对数据进行差分，近似得到拉普拉斯变换后的结果，然后检查正负交换的位置，则此为极值点位置，利用此思想得到极值点的位置。-Using the ideas of Laplace transform of the data by the difference approximation get results Laplace transform, and then check the position of the positive and negative exchange, this is the extreme position, take advantage of this thinking of getting extreme points location. Platform: |
Size: 1024 |
Author:类淑河 |
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Description: 用有限差分法编程求解拉普拉斯方程在网格结点处的值并统计迭代次数-Solving the value of the Laplace equation in a grid junction with the finite difference method and statistical programming iterations Platform: |
Size: 1024 |
Author:wang |
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