Welcome![Sign In][Sign Up]
Location:
Search - lie group

Search list

[Multimedia programrealalgebraicgeometry

Description: intoduce the lie group
Platform: | Size: 18543988 | Author: 曾文武 | Hits:

[Multimedia programrealalgebraicgeometry

Description: intoduce the lie group
Platform: | Size: 18543616 | Author: 曾文武 | Hits:

[matlabburger

Description: 这个是burger方程,李群的方法,求生成元-This is a burger equations, Lie group methods, and generator
Platform: | Size: 5120 | Author: 潘学军 | Hits:

[Mathimatics-Numerical algorithmsjj_

Description: 一类Heisenbergn_李代数的自同构群A class of Heisenbergn_ Lie algebra automorphism group-A class of Heisenbergn_ Lie algebra automorphism group
Platform: | Size: 445440 | Author: chenzhanyi | Hits:

[Algorithmdmnew

Description:  有一群喜欢带小红帽的家伙举行了一场别开生面的聚会,然而某些人被邪恶的WM讲帽子上涂了大灰狼的图标,可是每个人看不到自己头上的帽子有没有被涂,他们只能看到其他人头上的帽子是不是大灰狼的图案,现在告诉你每个人看到的别人头上大灰狼帽子的数量,聪明的你啊,能不能判断出来一共有多少个人头上被汪淼涂了可恶的大灰狼呢,当然如果你发现有些人撒谎的话,就直接输出-1吧-A group of like guys held a special party with Little Red Riding Hood, however, some people are evil WM stresses hat painted on the icon of the big bad wolf, but everyone can not see the hat of his head was not coated, they can only see the hat of others is not a big bad wolf pattern, and now tell everyone you see on others the number of wolf hat, smart, can not be judged a number of personal head Wang Miao painted evil one, of course, if you find that some people lie, on the direct output-1
Platform: | Size: 6144 | Author: 王子正 | Hits:

[Other6_5

Description: 该题是2000年全国青少年信息学奥林匹克的一道试题。叙述如下: 一条小溪尺寸不大,青蛙可以从左岸跳到右岸,在左岸有一石柱L,面积只容得下一只青蛙落脚,同样右岸也有一石柱R,面积也只容得下一只青蛙落脚。有一队青蛙从尺寸上一个比一个小。我们将青蛙从小到大,用1,2,…,n编号。规定初始时这队青蛙只能趴在左岸的石头L上,按编号一个落一个,小的落在大的上面。不允许大的在小的上面。在小溪中有S个石柱,有y片荷叶,规定溪中的柱子上允许一只青蛙落脚,如有多只同样要求按编号一个落一个,大的在下,小的在上,而且必须编号相邻。对于荷叶只允许一只青蛙落脚,不允许多只在其上。对于右岸的石柱R,与左岸的石柱L一样允许多个青蛙落脚,但须一个落一个,小的在上,大的在下,且编号相邻。当青蛙从左岸的L上跳走后就不允许再跳回来;同样,从左岸L上跳至右岸R,或从溪中荷叶或溪中石柱跳至右岸R上的青蛙也不允许再离开。问在已知溪中有S根石柱和y片荷叶的情况下,最多能跳过多少只青蛙? -This topic is the 2000 National Youth Information question the olympic. The narrative follows: A stream size, the frog can jump from left to right, there is a pillar of L on the left bank, area of only one frog settled, the same right bank also has a stone R, area is only one frog. A group of frogs from a size smaller than the one of. We will frog from small to large, with 1, 2,... , n number. Provisions of this team initially frog only lie on the left bank of stone L, according to the number one upon another, small on top. Do not allow big in small. S columns in the creek, y Creek in the lotus leaf, provisions of columns allows a frog settled, if there are more than just the same as required by the number one upon another, bigger in the next, small in number, and must be adjacent to. The lotus leaf only allows a frog to stay, not allowed only on the. For the pillars of R, and on the left bank of stone like L allows multiple frog settled, but must be one upon another, small in the b
Platform: | Size: 1024 | Author: yin | Hits:

[OtherSTATE-ESTIMATION

Description: 四旋翼数学建模,姿态估计方向,李群算法基础教程,英文原版。-STATE ESTIMATION FOR ROBOTICS A Matrix Lie Group A
Platform: | Size: 4371456 | Author: 王逸帆 | Hits:

CodeBus www.codebus.net