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Description: 1） 随机产生四个1-13的数，分别代表13张牌。
2） 提示玩家输入算式。
3） 判断玩家输入的表达式是否合法，其中算式中的四个数字只能是程序所给的四个数字，非法则回到1）。
4） 如果玩家认为这四张牌算不出24点（如：1，1，1，1），可只输入？，程序将判断这四张牌是否能得出24点，如果能，则程序将给出算式，如果不能，说明不能，并回到1）。
5） 当用户正确输入算式后，用“堆栈来求表达式的值”的原理 求出结果并判断是否为24，得出用户是输是赢的结果。
6） 询问用户是否继续，是则回到1），否则结束程序。
-1) randomly generated a number of four 1-13 representing 13 licenses.
2) Players are prompted to enter the formula.
3) to determine whether the players enter the legitimate expression, which in the formula can only be four digits of the four procedures to the number of illegal then back 1).
4) If the licensing of four players that can not count 24 points (for example: 1,1,1,1), can be input only? , The program will determine whether this card can come four 24-point, if we can, then the procedure will be given formula, if not, that can not, and return to 1).
5) When the user enter the correct formula, the use of "stack to seek expressions of value" principle and to determine whether the results obtained for 24, to draw customers to win or lose, it is the result.
6) asking the user whether or not to continue, is the return to 1), otherwise the end of the procedure
Platform: |
Size: 5120 |
Author: 涂舒 |
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Description: 如何使用GUI那就下这个吧，可能对你有很大帮助呢-how do you use GUI， it can tell you ,don t lose it ,you can get something from it.thank you
Platform: |
Size: 55296 |
Author: aichao |
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Description: 用c++ builder做了一个可以实现数据库备份，还原的主档，有参考别人的资料，只是共享，-create databases when it lose
Platform: |
Size: 19456 |
Author: zjl |
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Description: 芯片能够提供实时日历/时钟。在断电情况下运行十年以上不丢失数据，可用于参数的掉电保护-Chip can provide real-time calendar/clock. Running in power do not lose more than a decade of data, parameters can be used to power-down protection
Platform: |
Size: 1024 |
Author: 不说 |
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Description: 迷失森林 一个精灵在森林里走迷宫，有生命值-LOSE Sprite mySprite.paint(g)
Platform: |
Size: 81920 |
Author: raito |
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Description: 足球联赛计分并排名，工大课程设计。赢一球3分，输一球-1，平0分-Football League scoring and ranking, the major curriculum design. A ball to win 3 points,-1 lose a ball, ping 0 points
Platform: |
Size: 1024 |
Author: Vc_Ly |
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Description: FGPA code to implement a ping-pong game. There will be LEDs simulating the path of ball , and two button representing the player. The player should hit the button when the ball reach his end. If the player hit the ball, it will go to the other player. When the player does not hit at the right time, he will lose.-FGPA code to implement a ping-pong game. There will be LEDs simulating the path of ball , and two button representing the player. The player should hit the button when the ball reach his end. If the player hit the ball, it will go to the other player. When the player does not hit at the right time, he will lose.
Platform: |
Size: 196608 |
Author: lzm |
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Description: 输入一个十进制输，将其转换为二进制八进制和十六进制-Enter a decimal lose, will convert it to binary octal and hexadecimal
Platform: |
Size: 1024 |
Author: John |
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Description: 只是简单的五子棋游戏，AI做的还是蛮简单的 不过可以把你下输哦
早先学人工智能做出来的，还是蛮有成就感的。-Gobang simple game, AI is still pretty simple to do the next but you can lose, oh you earlier study done by artificial intelligence, or quite the sense of accomplishment.
Platform: |
Size: 3888128 |
Author: 杜立扬 |
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Description: Bugs suck. Period. Bugs are the reason you endure death-march projects with missed deadlines, late nights, and grouchy coworkers. Bugs can truly make your life miserable because if enough of them creep in to your software, customers will stop using your product and you could lose your job. Bugs are serious business.-Bugs suck. Period. Bugs are the reason you endure death-march projects with missed deadlines, late nights, and grouchy coworkers. Bugs can truly make your life miserable because if enough of them creep in to your software, customers will stop using your product and you could lose your job. Bugs are serious business.
Platform: |
Size: 1730560 |
Author: dingxu |
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Description: 四人玩火柴棍游戏，每一次都是三个人赢，一个人输。输的人要按赢者手中的火柴
数进行赔偿，即赢者手中有多少根火柴棍，输者就赔偿多少根。现知道玩过四次后，
每人恰好输过一次， 而且每人手中都正好有１６根火柴。问此四人做游戏前手中各有
多少根火柴? 编程解决此问题。-Four matches to play club games, every time the three win, lose one. Losers who should win a few matches their compensation, that is, the number of hands to win match stick, the number of losers on the compensation root. Played four times now to know, the person happens to lose one, and each of the hands are exactly 16 matches. Asked to do the four games before the match the hands of the respective numbers? Programming to solve this problem.
Platform: |
Size: 1024 |
Author: lcch |
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Description: WINDING COIL CONTROLLER, programable to max 9999 winding, magnetic sensor (reed rele), in the case of lose power controller have memory, sound alarm for last 9 winding, button "pause".
Platform: |
Size: 90112 |
Author: Tih |
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Description: 最经典的UCOS中文手册！学习ucos的不要失去次机会-The most classic UCOS English manual! Learning ucos' s not lose this opportunity! !
Platform: |
Size: 4044800 |
Author: 北方 |
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Description: 賭骰子程式
現金money：開始時給100元 m1下注金為 m2：下注旗標(0豹子1小2大)
(贏的次數：win 輸的次數：lose 總次數：total)
s0 骰子總合 s1、s2、s3骰子點數
p1：豹子 p2：小 p3：大 p0：豹子旗標 -Gambling dice program cash money: the beginning to 100 yuan m1 bet payment for m2: bets flag (0 leopard a small 2 large) (the number of win: win lost more often: lose the total number of: total) s0 dice aggregate s1 , s2, s3 Dice Points p1: leopard p2: Small p3: Big p0: leopard Flag
Platform: |
Size: 1024 |
Author: ALO |
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Description: 一个综合6大搜索引擎的代码,简单实用,即使不开个站放本地自己用用都是非常方便的,输一次关键词可同时得到6大搜索引擎的搜索结果,网页\图片\MP3等都可使用-A comprehensive six major search engine code, simple and practical, if not to open a place for local stations they use are very convenient to use, and lose a keywords can simultaneously be six major search engines search results, web pages \ images \ MP3 and so on use
Platform: |
Size: 233472 |
Author: 张辉 |
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Description: 这是一个简单的Java程序，将产生出25 numbers.Then随机数，用户可以选择其中25个按钮，猜数是程序随机generated.Once用户猜测正确，则会显示“双赢”的按钮，否则将显示“输”。-This is a simple java program that will generate a random number out of 25 numbers.Then,user can choose among 25 button to guess which number is the program randomly generated.Once the user guess correctly,it will display "win" on the button,or else it will display "lose".
Platform: |
Size: 1024 |
Author: felix |
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Description: labview编写的关于时域分析求互相关的程序，输两个信号，并且可以加噪声，求互相关-labview write on the time-domain analysis of demand cross-correlation procedures, lose two signals, and can add noise, seek cross-correlation
Platform: |
Size: 16384 |
Author: tongx |
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Description: This the complete source code for winquake, glquake, quakeworld, and
glquakeworld.
The projects have been tested with visual C++ 6.0, but masm is also required
to build the assembly language files. It is possible to change a #define and
build with only C code, but the software rendering versions lose almost half
its speed. The OpenGL versions will not be effected very much. The
gas2masm tool was created to allow us to use the same source for the dos,
linux, and windows versions, but I don t really recommend anyone mess
with the asm code.-This is the complete source code for winquake, glquake, quakeworld, and
glquakeworld.
The projects have been tested with visual C++ 6.0, but masm is also required
to build the assembly language files. It is possible to change a#define and
build with only C code, but the software rendering versions lose almost half
its speed. The OpenGL versions will not be effected very much. The
gas2masm tool was created to allow us to use the same source for the dos,
linux, and windows versions, but I don t really recommend anyone mess
with the asm code.
Platform: |
Size: 7991296 |
Author: mmkhz1 |
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Description: 你是否曾经为要做一个试用软件而苦苦写很多代码，这个控件为你解决了写共享软件的麻烦，它可以把你的软件加一把锁，让用户注册，在规定期限内如果用户不注册就会不能试用或丧失一些功能。-Do you have to do a lot of trial software, which are hard to write code, this control is for you to solve the trouble to write-sharing software, which can put your software plus a lock, allowing users to register within the prescribed time if the user do not register will not be a trial or lose some of the features.
Platform: |
Size: 229376 |
Author: wangtao |
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Description: Java版的拼图游戏，玩家可以自己更换图片，只要你把它分成块，另外它是以成绩=1000-时间（秒）-移动步数*10来决定你是否输了，按F1键开始游戏，Y健预览图片。-Java version of the puzzle, players can change their own image, as long as you put it into blocks, while it is based on results = 1000- Time (seconds)- moves* 10 to determine whether you lose, press F1 key to start the game , Y Kin preview image.
Platform: |
Size: 252928 |
Author: 231 |
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