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Description: 在现代的企业管理中，火车管理系统有着重要作用。由于现代的竞争力的加强，讲究效率，不管是时间、还是地点，两地的生意常常因为距离而无法得到理想的解决。火车作为一个传统的交通工具，需要进行改革。由于订票、退票常常给乘客带来一定的麻烦，因此作为一个火车管理系统解决了这个问题。它方便乘客最快地订到自己想要的票也同时解决了退票的问题。-in modern enterprise management, train management system plays an important role. Contemporary the strengthening of competitiveness, focusing on efficiency, regardless of time or location, two of business because of distance and often can not be the ideal solution. Train as a traditional means of transport, the need for reforms. Since booking, a refund to passengers often cause some trouble, as a train management system to solve this problem. It is the convenience of passengers to the fastest set of the votes they want to also address the issue of refunds.
Platform: |
Size: 2959 |
Author: 0505424 |
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Description: 这是一个在C环境下编写的链表操作，主要实现集合的交，并，补操作-This is an environment in C List prepared by the operation, main set of reference and that the fill operation
Platform: |
Size: 1760 |
Author: 李强 |
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Description: 这是一个在C环境下编写的链表操作，主要实现集合的交，并，补操作-This is an environment in C List prepared by the operation, main set of reference and that the fill operation
Platform: |
Size: 1024 |
Author: 李强 |
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Description: 在现代的企业管理中，火车管理系统有着重要作用。由于现代的竞争力的加强，讲究效率，不管是时间、还是地点，两地的生意常常因为距离而无法得到理想的解决。火车作为一个传统的交通工具，需要进行改革。由于订票、退票常常给乘客带来一定的麻烦，因此作为一个火车管理系统解决了这个问题。它方便乘客最快地订到自己想要的票也同时解决了退票的问题。-in modern enterprise management, train management system plays an important role. Contemporary the strengthening of competitiveness, focusing on efficiency, regardless of time or location, two of business because of distance and often can not be the ideal solution. Train as a traditional means of transport, the need for reforms. Since booking, a refund to passengers often cause some trouble, as a train management system to solve this problem. It is the convenience of passengers to the fastest set of the votes they want to also address the issue of refunds.
Platform: |
Size: 3072 |
Author: 0505424 |
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Description: 介绍了基于嵌入式实时操作系统uCOS - ii 的有线数字电视机顶盒的设计及其组成,并阐述其
具体实现,该机顶盒以实时多任务操作系统uCOS - ii 为核心,以信道解码模块、信号解码模块和网络链
接接口模块、遥控交互模块为基础,以有线电视机顶盒专用芯片MB87M2140 为主要实现方式,有效实现
了数字电视信号的交互应用-Introduce a real-time operating system based on embedded uCOS- ii cable digital TV set-top box design and its components, and explains its concrete realization of the set-top box in real-time multi-tasking operating system uCOS- ii as a core and channel decoding module, signal decoding modules and network link interface module, remote control-based interactive module to cable TV set-top box ASIC MB87M2140 realize as the main way of effective realization of the digital TV signals in interactive applications
Platform: |
Size: 92160 |
Author: pengrong |
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Description: 凌阳公司机sunplus1002在这个芯片做为机顶盒主芯片下的嵌入式字体库。-Sunplus sunplus1002 machine company in the chip as a set-top boxes under the main chip embedded font libraries.
Platform: |
Size: 911360 |
Author: 王 |
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Description: 工作之余，用VC作了一个小程序，是VC SQL server模式的，程式内容比较简单，主要设及以下内容：
1、窗口如何分割；
2、多视图之间如何通信；
3、列表视图的操作及事件处理；
4、树形控件的操作及事件处理，利用递归根据数据库动态生成目录；
5、实现主从表的显示； -Spare time, using VC made a small program is VC SQL server mode, the program content is relatively simple, the main set and the following: one, how the window segmentation 2, multi-view of how communication 3, list view operation and event handling 4, tree controls the operation and events that deal with the use of recursive dynamically generated according to the database directory 5, realize the main display from the table
Platform: |
Size: 384000 |
Author: winhex |
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Description: STL 教程-Set使用方法演示，主要介绍set的操作参数。-STL Tutorial-Set the use of demonstration, introduce the main set of operating parameters.
Platform: |
Size: 355328 |
Author: zhangziliang |
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Description: 利用红外发射器和接收器，可是小车按照设定好的黑线寻迹-The use of infrared transmitter and receiver, but the car set in accordance with good black line tracing
Platform: |
Size: 1024 |
Author: linfaming |
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Description: 很好的源代码，对初学者有何大帮助。欢迎下载-Good source code, what is very helpful for beginners. Welcome to download
Platform: |
Size: 2382848 |
Author: haihai |
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Description: If a tree falls in the forest, and there s nobody there to hear, does it make a sound? This classic conundrum was coined by George Berkeley (1685-1753), the Bishop and influential Irish philosopher whose primary philosophical achievement is the advancement of what has come to be called subjective idealism. He wrote a number of works, of which the most widely-read are Treatise Concerning the Principles of Human Knowledge (1710) and Three Dialogues between Hylas and Philonous (1713) (Philonous, the "lover of the mind," representing Berkeley himself). -A forest contains T trees numbered from 1 to T and P people numbered from 1 to P. Standard input consists of a line containing P and T followed by several lines, containing a pair of integers i and j, indicating that person i has heard tree j fall. People may have different opinions as to which trees, according to Berkeley, have made a sound.
Input contains multiple test cases. Subsequent test cases are separated with a single blank line.
How many different opinions are represented in the input? Two people hold the same opinion only if they hear exactly the same set of trees. You may assume that P < 100 and T < 100.
Platform: |
Size: 1024 |
Author: 朱鹏飞 |
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Description: LED交替闪烁
可以高低4位交替
可以全亮全灭闪烁
可以设置延时时间-Alternating high and low LED flashes can be a full four alternate flashing light body can set the delay time
Platform: |
Size: 1024 |
Author: july |
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Description: ATC89C51下开发的带万年历的电子钟设计，可设置4个闹钟-ATC89C51 developed under the electronic clock with calendar design, you can set 4 alarm clocks
Platform: |
Size: 2048 |
Author: 素娟 |
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Description: 窗口源码！
本源码只是建立了窗口，如果想要实现其他功能，请自己添加。
代码内附说明-Windows source code! The source code is only set up the window, if you want to achieve other functions, please add yourself. Code containing a description
Platform: |
Size: 1024 |
Author: kushinn |
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Description: 多种排序的比较给定N个int类型（自定N的上限M，例如M=100000，N的取值不能少于10000）的整数，分别使用插入排序、快速排序、归并排序和堆排序方法进行升幂排序。-Comparison of a variety of sorting a int type of the given N (since N limit set M, for example, M = 100000, N values can not be less than 10000) and integer, respectively, using the insertion sort, quick sort, merge sort and heap sort method l power to sort.
Platform: |
Size: 2048 |
Author: 赵欣婷 |
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Description: Description:
对整型有序关键码序列进行折半查找，待排序序列以数组存储。如果找到待查记录，返回找到的位置下标，并删除该关键码记录；如果没找到待查记录，返回0，并将待查记录插入到适当位置，即该查找属于动态查找。输出查找过程中每一轮的low，mid，high 值，以及与给定值相比较的关键码值，并输出最后找到的位置，及变化后的数组。
注意：该数组为整型，数组中关键码存储位置为r[1]~r[n]，r[0]留作它用，且关键码个数大于4.
Input Format:
第一行输入数组中记录个数n
第二行输入n个有序的整型关键码，以空格隔开
接下来输入三个待查关键码，每个关键码占一行
Output format:
对于每个关键码，分别输出：
找到给定值之前的每一轮的low，mid，high及相比较的待查找序列中的关键码，以空格隔开
接下来一行输出查找到的位置
接下来一行输出变化后的待查找序列
-Description:
The key codes for integers ordered sequence of binary search until the sorting sequence to an array of storage. If you find a complete set of records, returns to find the location of the next standard, and delete the key code is recorded if not find a complete set of records, returns 0, and a complete set of records inserted into the appropriate location, that is, the search was part of search. Find out the process for each one of the low, mid, high value, as well as compared to the value given the key code value and output of the last to find the location, and the array after the changes.
Note: The array of integers, an array of key code storage location r [1] ~ r [n], r [0] reserved for its use, and the key number is greater than 4 yards.
Input Format:
The first line in the input array records the number of n
The second line, type n-ordered integer key code, separated by a space
Next, enter the three complete set of key codes, key codes for each accounting l
Platform: |
Size: 5120 |
Author: kernel |
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Description: TMS320F2812_XNMI 中断设定C语言主函数-TMS320F2812_XNMI interrupt set C language main function
Platform: |
Size: 1024 |
Author: fuyan |
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Description: 一款有8种闹钟设置的时钟，通过一段时间的使用，情况良好。适用于CC100B、CC100C-The one with 8 kinds of alarm clock is set, through the use of a period of time in good condition.
Platform: |
Size: 5120 |
Author: 薛林 |
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Description: 程序功能：接收来自PC机的字符，然后重新发送给PC机
通信格式：N.8.1, 9600
无校验，8个数据位，1个停止位，波特率9600
------------------------------------------------------
测试说明：打开SSCOM，正确设置通信格式，向学习板发送一个
字符或者是字符串（字符和字符串结尾必须添加结束
符 \ ），观察PC机是否正确收到回发的字符-Program features: Receive the characters from the PC, and then re-sent to the PC, communication format: N.8.1, 9600 no parity, 8 data bits, 1 stop bit, baud of 9600------------------------------------------------------ Test Description: Open SSCOM, properly set up communication format, to learn from board to send a character or a string (characters and end of the string must be added to end of the character ' \' ), observe the PC, the correct characters received back
Platform: |
Size: 2048 |
Author: pbj |
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Description: 多家大公司笔试题目程序解答：
1.1-20的两个数把和告诉A,积告诉B，A说不知道是多少，B也说不知道，
这时A说我知道了，B接着说我也知道了，问这两个数是多少？
设这两个数是x和y。且x+y=A, xy=B
计算结果：1~20： 结果为2，2
2~20： 结果为4，3
2. 2~100中两个数，把和告诉A，乘积告诉B，A说：我不知道，你也不知道；
这时B说我知道了，A说我也知道了。
设这两个数是x和y，且x+y=A, xy=B-Many large companies program written questions:
The two Numbers 1.1-20 and tell A, B, tell how much is A says don t know, B also said don t know,
Then said I know A, B then said I also know, ask the two Numbers?
Set the two Numbers is x and y. And x, y+ xy = B
Results: 1 ~ 20: the results for the viewpoint
2 ~ 20:4,3 results
Platform: |
Size: 1024 |
Author: tfy |
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