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[Multimedia program] Mod xm

Description: 其中调用控件来播放MOD XM 等文件,还有8,8,1的PCM文件,不含什么技术性内容,可以用于练习使用DLL文件.-which controls called XM to broadcast MOD documents, 8,8,1 PCM, what is non-technical content, which can be used to practice the use of DLL files.
Platform: | Size: 1246619 | Author: 耿海瑞 | Hits:

[Other] Uniform Generator

Description: Uniform Generator Computer simulations often require random numbers. One way to generate pseudo-random numbers is via a function of the form where `` " is the modulus operator. Such a function will generate pseudo-random numbers (seed) between 0 and MOD-1. One problem with functions of this form is that they will always generate the same pattern over and over. In order to minimize this effect, selecting the STEP and MOD values carefully can result in a uniform distribution of all values between (and including) 0 and MOD-1. For example, if STEP = 3 and MOD = 5, the function will generate the series of pseudo-random numbers 0, 3, 1, 4, 2 in a repeating cycle. In this example, all of the numbers between and including 0 and MOD-1 will be generated every MOD iterations of the function. Note that by the nature of the function to generate the same seed(x+1) every time seed(x) occurs means that if a function will generate all the numbers between 0 and MOD-1, it will generate pseudo-random numbers uniformly with every MOD iterations. If STEP = 15 and MOD = 20, the function generates the series 0, 15, 10, 5 (or any other repeating series if the initial seed is other than 0). This is a poor selection of STEP and MOD because no initial seed will generate all of the numbers from 0 and MOD-1. Your program will determine if choices of STEP and MOD will generate a uniform distribution of pseudo-random numbers. Input Each line of input will contain a pair of integers for STEP and MOD in that order ( ). Output For each line of input, your program should print the STEP value right- justified in columns 1 through 10, the MOD value right-justified in columns 11 through 20 and either ``Good Choice" or ``Bad Choice" left-justified starting in column 25. The ``Good Choice" message should be printed when the selection of STEP and MOD will generate all the numbers between and including 0 and MOD-1 when MOD numbers are generated. Otherwise, your program should print the message ``Bad Choice". After each output test set, your program should print exactly one blank line. Sample Input 3 5 15 20 63923 99999 Sample Output 3 5 Good Choice 15 20 Bad Choice 63923 99999 Good Choice
Platform: | Size: 360 | Author: samurai1x4kyo@126.com | Hits:

[Other resource] minecraft mod

Description: minecraft mod 使用後加上cjb就可以像gm1樣無所不能
Platform: | Size: 83191 | Author: jim9851 | Hits:

[Multimedia Develop] zinf-2.2.1

Description: MutilMedia Player支援MOD MP3 WAVE OGG等格式-MutilMedia Player support MOD MP3 WAVE OGG format, etc.
Platform: | Size: 2338816 | Author: 林正旺 | Hits:

[Windows Develop] 算术表达式解析器

Description: 此算术表达式能够在程序运行时根据输入的变量大小和算术表达式动态解析表达式，得到运算结果。支持多项算术运算符和数学函数如下：: + - * / ^ ( ) mod abs, atan, cos, exp, ln, round, sin, sqrt, sqr, trunc 例如设定a1和a2的大小，就可计算下列表达式: exp(sin(a1)*cos(a2))操作系统： Visual C++语言 -this arithmetic expression in accordance with the procedures in the importation of variable size and arithmetic expressions dynamic analytical expression to be Operational results. Support for a number of arithmetic operations and mathematical functions are as follows : :-*/^ () mod abs, atan, cos, exp, ln, round, sin, sqrt, sqr, for example, to set trunc a1 and a2 the size, can be calculated by the following formula : exp ( sin (a1)* cos (a2)) Operating System : Visual C language
Platform: | Size: 49152 | Author: 曲贵增 | Hits:

[Crack Hack] RSA解密和加密算法的实现和应用

Description: RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s <= n, 通常取 s = 2^t), 则每一位数均小于 n, 然後分段编码...... 接下来, 计算 b == a^m mod n, (0 <= b < n), b 就是编码后的资料。解码的过程是, 计算 c == b^r mod pq (0 <= c < pq), 于是, 解码完毕-RSA algorithm : First, find a few 3, p, q, r, p, q is the two different prime number, with the r (p-1) (q-1) coprime several ... p, q, r it person_key number is three, and then find m, making r ^ m == a mod (p-1) (q-1 m ...................................... this must exist, because r (p-1) (q- 1) coprime, with the division algorithm can be a ..... Next, calculate n = pq ....... m, n is the number two public_key, coding process is that if a data and to treat it as a big Integer assuming a <n. ... If a> = n, a table will be rounding into s (s <= n, usually from 2 ^ s = t), each n is less than the median, and then sub-coding ..... . Next, calculate a == b ^ m mod n, (0 <= b <n), b is encoded information. Decoding is the process of calculating c == b ^ r mod pq (0 <= c &
Platform: | Size: 1024 | Author: 胡康康 | Hits:

[Multimedia Develop] Mod xm

[Other] cdma_coding

Description: cdma coding mod and demod
Platform: | Size: 1024 | Author: benny | Hits:

[Communication-Mobile] FSK_Mod_Demod

Description: FSK调制Matlab程序。包括FSK mod and demod；CPFSK mod and demod代码。-Matlab procedures FSK modulation. Including FSK mod and demod CPFSK mod and demod code.
Platform: | Size: 2048 | Author: 吴昊 | Hits:

[Post-TeleCom sofeware systems] MSK_Mod_Demod

Description: MSK的调制解调程序，包括传统MSK mod and demod，以及GMSK的mod and demod.-MSK modem procedures, including the traditional MSK mod and demod, and GMSK the mod and demod.
Platform: | Size: 2048 | Author: 吴昊 | Hits:

[matlab] mod-demod

Description: BPSK.QPSK.16QAM.64QAM调制解调-BPSK.QPSK.16QAM.64QAM modem
Platform: | Size: 4096 | Author: 周郭楠 | Hits:

[Communication-Mobile] mod..demod

Description: BPSK, QPSK, !6QAM, 64QAM的matlab调制与解调算法与编程， -BPSK, QPSK,! 6QAM, 64QAM modulation and demodulation of matlab algorithms and programming,
Platform: | Size: 4096 | Author: 张鑫 | Hits:

[matlab] Mod

Description: 有关于相位，频率，等数字调制技术识别的MATLAB代码，-Have on the phase, frequency, and other digital modulation techniques to identify the MATLAB code,
Platform: | Size: 10240 | Author: shirley | Hits:

[Other] momi

Description: 大数的模幂算法(GUI)，用密码学课本中的算法，快速、高效。计算(x的r次方) mod p 的值-Large numbers of modular exponentiation algorithm (GUI), used cryptography algorithm textbooks, fast and efficient. Calculation of (x of the r-th power) mod p value
Platform: | Size: 22528 | Author: LYC | Hits:

[Multimedia Develop] bass24

Description: BASS 音频库最新2.4版。内含basscd24、bassenc24、bassflac24、bassmidi24、bassmix24、basswm24、basswv24等多个插件。是进行音频处理的理想函数库。 BASS is an audio library for use in Windows and Mac OSX software. Its purpose is to provide developers with the most powerful and efficient (yet easy to use), sample, stream (MP3, MP2, MP1, OGG, WAV, AIFF, custom generated, and more via add-ons), MOD music (XM, IT, S3M, MOD, MTM, UMX), MO3 music (MP3/OGG compressed MODs), and recording functions. All in a tiny DLL, under 100KB* in size.-BASS audio library latest 2.4 version. Intron basscd24, bassenc24, bassflac24, bassmidi24, bassmix24, basswm24, basswv24 and many other plug-ins. Is ideal for audio processing libraries. BASS is an audio library for use in Windows and Mac OSX software. Its purpose is to provide developers with the most powerful and efficient (yet easy to use), sample, stream (MP3, MP2, MP1, OGG, WAV, AIFF, custom generated, and more via add-ons), MOD music (XM, IT, S3M, MOD, MTM, UMX), MO3 music (MP3/OGG compressed MODs), and recording functions. All in a tiny DLL, under 100KB* in size.
Platform: | Size: 1214464 | Author: Ferret | Hits:

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