Description: 本程序定义了长度为41的数组来存放大数，进行对大数的运算。四则运算的算法就跟平时我们笔算四则运算的方法基本上一样，加减法的时间复杂度为n，乘除法的时间复杂度为n的平方。对四十位内的计算几乎都可以瞬时完成。-definition of the procedures for the length of the 41 arrays to store large numbers, the majority of arithmetic. Four computing algorithm just as we usually four Operational written calculation methods are basically the same, subtract the time complexity of n, multiply and divide the time complexity of n square. 40 pairs of calculation can be almost instantaneous. Platform: |
Size: 22528 |
Author:liuchuan |
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Description: 这是一个用c语言实现的2个32大数相乘，乘积为64.-This is a use of language c 2 32 multiply large numbers, the product of 64. Platform: |
Size: 1024 |
Author:bolin.gong |
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Description: 文件包括RSA算法原程序及详细注释。可以实现使用1024位以上大素数进行加解密。其中包括大整数的加、减、乘、除、模幂运算，求逆元运算，以及大素数的判定等算法。稍做扩展即可在实际中应用。-Documents include the RSA algorithm for the original procedures and detailed notes. Can be achieved using more than 1024 large prime numbers for encryption and decryption. Including large integer add, subtract, multiply, divide, modular exponentiation computation, and inverse calculations, as well as the large prime numbers, such as algorithms to determine. Can be extended slightly in the actual application. Platform: |
Size: 112640 |
Author:wp |
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Description: 能实现大数的乘法运算，大数运算在各个方面都要用到-Can realize the multiplication of large numbers, large numbers in the various aspects of computing should be used Platform: |
Size: 1024 |
Author:xiongwei |
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Description: 本程序的主要功能在于中缀表达式的计算,
其中运算符有加,减,乘,除,乘幂基本运算符
,运算数为实数之间运算，并可以实现循环
计算..完成基本操作是进行字符处理,栈的使用.
-The primary function of this program is made up of the calculation of expression, in which operators are add, subtract, multiply, divide, take the power of basic operator, computing the number of operations between real numbers, and the cycle can be calculated to achieve the basic operation is completed .. characters to deal with the use of stacks. Platform: |
Size: 2048 |
Author:Jun |
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Description: This a program to multiply 2 infinite Digit numbers.
The program also calculates the execution time.
thanks
Kr Anurag Platform: |
Size: 1024 |
Author:Kumar Anurag |
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Description: 用类实现大数的数据结构算法，可以比较两个大数的大小，两个大数间相加，大数与普通整数相加，两个大数相乘等-Large numbers with the class implements the data structure algorithms, can compare the size of two large numbers, between the sum of two large numbers, large numbers of ordinary integer add, multiply two large numbers, etc. Platform: |
Size: 3072 |
Author:pig |
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Description: 大数相乘，支持10000位的大型数字，可以快速算得结果-Multiply large numbers in support of a large number 10000, the results can quickly be regarded Platform: |
Size: 3072 |
Author:mayuqiang |
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Description: 大数相乘，自带的类型如long处理的范围是有限的，所以对于超大可以用代码实现。-Multiply large numbers, the type that comes with dealing with such long range is limited, so the code can be achieved for large. Platform: |
Size: 1024 |
Author:daiminmin |
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Description: 大数（含小数）的加、减、乘、除、幂运算，支持正负，用链表实现，理论上无限大小-Large numbers (including decimals) and add, subtract, multiply, divide, power operations and support positive and negative, with a linked list to achieve, theoretically unlimited size Platform: |
Size: 11264 |
Author:林凯杰 |
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Description: RSA公钥加密算法是1977年由Ron Rivest、Adi Shamirh和LenAdleman在（美国麻省理工学院）开发的。RSA取名来自开发他们三者的名字。RSA是目前最有影响力的公钥加密算法，它能够抵抗到目前为止已知的所有密码攻击，已被ISO推荐为公钥数据加密标准。RSA算法基于一个十分简单的数论事实：将两个大素数相乘十分容易，但那时想要对其乘积进行因式分解却极其困难，因此可以将乘积公开作为加密密钥。
-Public key encryption algorithm RSA in 1977 by Ron Rivest, Adi Shamirh and LenAdleman in (MIT) development. RSA name from the development of their three names. RSA is the most influential public-key encryption algorithm, it can resist all known password attack so far, has been recommended for ISO public key data encryption standard. RSA algorithm is based on a number of very simple fact: to multiply two large prime numbers is very easy, but then you want their product is extremely difficult to factorization, it can be the product of the public as the encryption key. Platform: |
Size: 8192 |
Author:YCLIU |
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Description: 1、实现算术表达式的求值运算，程序通过键盘输入一个表达式，通过运算得到表达式的值，并在显示器上输出完整的表达式及其值；
2、程序实现时，采用栈数据结构
3、表达式以字符串的形式输入；
4、表达式中包括的基本运算符有加、减、乘、除（分别用+、-、*、、表示），表达式中包括括号的处理，括号可以嵌套；表达式中的数字可以是整数，也可以是小数-1, and the evaluation of arithmetic operations, the program through keyboard input an expression, obtained by computing the value of the expression and display the full expression of the value of output 2, program implementation, the use of the stack data structure 3, the expression as a string input 4 expression, including the basic operators are add, subtract, multiply and divide (respectively+,-,*,, said), the expression including the handling of parentheses, Parentheses can be nested expressions can be integer numbers, can also be fractional Platform: |
Size: 3072 |
Author:张笑薇 |
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Description: 采用两种方式解决大数相乘问题，一种是采用链表的方式。另外一种是采用字符串的方式。-Multiply large numbers in two ways to solve the problem, one way is to use list. Another way is to use a string. Platform: |
Size: 3072 |
Author:任胜强 |
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Description: 大数阶乘 本代码是用c++编写以类来实现的，采用链表的形式-Factorial of large numbers of the code written using c++ to class, using a linked list in the form of Platform: |
Size: 1024 |
Author:wyt |
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Description: 包含一个文件打包函数与一个大数相乘函数，是公司常见的面试题之一。-Contains a file is packaged function with a multiply large numbers function is one of the common face questions. Platform: |
Size: 1024 |
Author:远野瞬 |
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Description: RSA公钥加密算法的大数相乘C代码，可进行任意位数的两个数相乘。-RSA public key encryption algorithm for multiplication of large numbers of C code, multiply two numbers can be arbitrary digit. Platform: |
Size: 1024 |
Author: |
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Description: 1.所有已知错误除大数乘法外皆解决
2.添加按键音
3.解决老版本缓冲区清空问题
4.添加类似windows计算器的/=功能（即自身作为第二个操作数）
5.目前小数仅保留4位以内-1. All known bugs are solved outside except multiply large numbers
2. Add the key tone
3. Solve the problem the old version of the buffer empty
4. Similar windows calculator/= function (ie itself as the second operand)
5. Currently only reserved four decimals less Platform: |
Size: 2733056 |
Author:谢 |
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Search - multiply 2 numbers