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[
Other resource
]
pcmcode
DL : 0
将输入A律PCM编码器的正弦信号采样,进行PCM编码,求出编码器的输出码组序列。-legal importation A PCM encoder sinusoidal signal sampling, PCM coding, coding obtained the output code sequence.
Update
: 2008-10-13
Size
: 28.27kb
Publisher
:
刘奇
[
Other
]
PCMcode
DL : 0
程序为将a律十三折线的PCM信号经量化后的信息编为0101二进制的编码。
Update
: 2008-10-13
Size
: 1.28kb
Publisher
:
刘乐
[
matlab
]
pcmcode
DL : 0
将输入A律PCM编码器的正弦信号采样,进行PCM编码,求出编码器的输出码组序列。-legal importation A PCM encoder sinusoidal signal sampling, PCM coding, coding obtained the output code sequence.
Update
: 2025-02-17
Size
: 28kb
Publisher
:
刘奇
[
Other
]
PCMcode
DL : 0
程序为将a律十三折线的PCM信号经量化后的信息编为0101二进制的编码。-Procedures will be a law broken line thirteen of the PCM signal after quantization information as binary code 0101.
Update
: 2025-02-17
Size
: 1kb
Publisher
:
刘乐
[
matlab
]
pcmcode
DL : 0
对单个采样点进行PCM编码的matlab源程序,是A律PCM。-code for A PCM
Update
: 2025-02-17
Size
: 1kb
Publisher
:
小龙女
[
Multimedia program
]
PCMcode
DL : 0
PCM码的编码译码程序,PCM码的编码译码程序.-Procedures of PCM s coding and encoding
Update
: 2025-02-17
Size
: 1kb
Publisher
:
Kang xiaoyang
[
Other
]
PCMcode
DL : 0
实现通信原理上的PCM(脉冲编码调制)调制与解调等 功能-MATLAB PCM
Update
: 2025-02-17
Size
: 148kb
Publisher
:
gaoshang
[
Software Engineering
]
pcmcode
DL : 0
律u律pcm编码 若输入A律PCM编码器的正弦信号为x(t)=sin(1600πt),采样序列为x(n)=sin(0.2πn),n=0,1,2,…,10,将其进行PCM编码,求出编码器的输出码组序列y(n)。 要求:1) 直接采用A律扩展器函数求解上述问题。 2)使用13折线法近似A律PCM 求解上述问题。 3)计算量化误差。-Law a law pcm coding If the input A-law PCM encoder is sinusoidal signal x (t) = sin (1600πt), for the sample sequence x (n) = sin (0.2πn), n = 0,1,2, ..., 10, it will be PCM coding to obtain the coded output code group sequence y (n). Requirements: 1) directly A-law expander function to solve the above problems. 2) using a 13 fold line approximation A-law PCM to solve the above problems. 3) calculating the quantization error.
Update
: 2025-02-17
Size
: 28kb
Publisher
:
高山
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