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Description: 这是一道经典的线程同步问题——哲学家吃饭问题。这里结合了win32使得这个问题可视化了-This is a classic thread synchronization -- philosopher food problem. Win32 here combination of this makes the issue of visualization
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Size: 17079 |
Author: Freedom |
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Description: 哲学家问题的解决，对于并发程序以及多线程的一个简单的解决-philosopher solve the problem, and for the concurrent program in a multithreaded simple solution
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Size: 2576 |
Author: 汗颜 |
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Description: 这是一道经典的线程同步问题——哲学家吃饭问题。这里结合了win32使得这个问题可视化了-This is a classic thread synchronization-- philosopher food problem. Win32 here combination of this makes the issue of visualization
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Size: 796672 |
Author: Freedom |
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Description: 进程同步,哲学家进餐共享临界区变量.定义信号量机制控制进程不互斥!-process synchronization, philosopher dining area share critical variables. Definition signal to the process control mechanism not contradict!
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Size: 1024 |
Author: |
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Description: 在Linux环境下，用C语言实现哲学家进程问题。-the Linux environment, using C language philosopher process.
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Size: 5120 |
Author: weixiang |
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Description: 用图形界面模拟如下场景：一个圆桌上有一个大碗面，5个盘子，每位哲学家一个，还有5把叉子。每个想吃饭的哲学家将做到桌子旁边分配给他的位置上，使用盘子两侧的叉子，取面和吃面。问题是：设计一个算法以允许哲学家吃饭。算法必须保证互斥（没有两位哲学家同时使用同一把叉子），同时还要避免死锁和饥饿。-Use graphical interface simulation scenario is as follows: a round-table, there is a large bowl, five plates, one for each philosopher, there are five forks. Every philosopher would like to eat will be allocated to the table next to his position, the use of plates on both sides of the fork, take surface and eat noodles. The question is: to design an algorithm to allow philosophers to eat. Algorithm must ensure that mutually exclusive (no two philosophers use the same fork at the same time), but also to avoid deadlock and starvation.
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Size: 39936 |
Author: sdfsfdsf |
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Description: 五个哲学家的就餐问题，程序中有左撇子存在，不存在饿死的情况！-Five dining philosophers problem, procedures exist in the left-handed, there is no case of starvation!
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Size: 6144 |
Author: lq |
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Description: 用线程解决“N个哲学家”问题
1、目的：
学习线程的编程和同步
-Use threads to solve
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Size: 16384 |
Author: Yejianmei |
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Description: 哲学家进餐问题——Java语言实现
哲学家进餐问题是一个多线程运用的经典例子，涉及到线程同步/互斥，临界区访问问题以及一个避免死锁的解决方法。
有五个哲学家绕着圆桌坐，每个哲学家面前有一盘面，两人之间有一支筷子，这样每个哲学家左右各有一支筷子。
哲学家有2个状态，思考或者拿起筷子吃饭。如果哲学家拿到一只筷子，不能吃饭，直到拿到2只才能吃饭，并且一次只能拿起身边的一支筷子。一旦拿起便不会放下筷子直到把饭吃完，此时才把这双筷子放回原处。
如果，很不幸地，每个哲学家拿起他或她左边的筷子，那么就没有人可以吃到饭了。这就会造成死锁了。。这是需要坚决杜绝的，正如操作系统的死锁问题。
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Size: 6144 |
Author: stone |
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Description: OS的经典问题：哲学家吃饭问题！用gcc编译，重定向到一个文件就可以了！-OS classic problem: the problem of feeding a philosopher! Use gcc compiler, redirect to a file you can!
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Size: 2048 |
Author: 飞鱼 |
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Description: 哲学家就餐问题，一共七个哲学家，无限循环。结束进程才能停止程序-Dining philosophers problem, a total of seven philosophers, infinite loop. The end of the process in order to stop the procedure
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Size: 2048 |
Author: 张飞 |
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Description: ucos-dining-philosopher.rar
ucos下的哲学家就餐问题（dining philosopher problems)，采用信号量机制解决，有截图和感悟。dos界面文字演示（另有图形界面）。-ucos-dining-philosopher.rarucos under the dining philosophers problem (dining philosopher problems), using semaphore mechanism to resolve screenshot and insights. dos interface text presentation (otherwise graphical interface).
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Size: 281600 |
Author: xuxi |
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Description: 哲学家就餐问题的实现，进程死锁问题，PV原语-Philosophers eat the realization of the process of deadlock, PV primitives
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Size: 2048 |
Author: weishantc |
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Description: 操作系统课程设计，哲学家算法的模拟
程序简短-Philosopher of the simulation algorithm
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Size: 1024 |
Author: 黎伟军 |
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Description: 哲学家就餐问题（VC图形界面版，添加了暂停恢复演示功能）-philosopher eating demo
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Size: 3914752 |
Author: 洛伊 |
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Description: dinning philosopher problem
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Size: 1024 |
Author: rohit |
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Description: dinnig philosopher problem
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Size: 12288 |
Author: arpan bhardwaj |
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Description: Dining Philosopher problem solved, with graphical display for easy understanding.
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Size: 124928 |
Author: kk |
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Description: 哲学家问题。操作系统经典问题。非常好的资源，希望大家喜欢。-Philosophers problem. Classic problem of the operating system. Very good resources, I hope everyone likes.
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Size: 2896896 |
Author: miller |
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Description: 用C语言实现了经典的哲学家吃饭问题。使用了信号量机制。-Dinning philosopher s problem implemented in C
Platform: |
Size: 10240 |
Author: gb18030 |
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