Location:
Search - pi
Search list
Description: 哈明窗设计带通滤波器
低阻带边缘：0.3*pi ；
高阻带边缘：0.6*pi AS＝50dB；
低通带边缘：0.4*pi RP＝0.5dB；
高通带边缘：0.5*pi
-hamming window design a bandpass filter
Platform: |
Size: 1024 |
Author: 王硕 |
Hits:
Description: Photovoltaic array modeling explained. Matlab/Simulink models available for download.
Platform: |
Size: 793600 |
Author: mvillabr |
Hits:
Description: hurst parameter: 給入一序列的資類，程式會畫出husrt 參數的figure和估計值
例 hurst_expo(sin(0:0.01:5*pi)) -hurst parameter: the sequence into a category of funding, the program will draw the figure and husrt parameter estimates were hurst_expo (sin (0:0.01:5* pi))
Platform: |
Size: 1024 |
Author: 桂枝 |
Hits:
Description: Java 数值计算库
数列求和算法、求解方程的根、插值法和近似法、
数值积分、求解微分方程、矩阵运算及其它一些有趣的东西，
比如：大数、素数算法、PI、分形-Java Number Cruncher
Platform: |
Size: 295936 |
Author: shane liu |
Hits:
Description: 求一个复正弦加白噪声随机过程的信号：
xn=exp(j*pi*n-j*pi)+exp(j*w0*n-j*0.7*pi)+v v(n)为零均值白噪声。S/N=10dB。取P=3，构造4阶的自相关矩阵R的基于MUSIC算法的功率谱估计的MATLAB程序-For a complex sinusoid plus white noise of the signal random process: xn = exp (j* pi* nj* pi)+ exp (j* w0* nj* 0.7* pi)+ v v (n) zero mean white noise. S/N = 10dB. Take P = 3, constructed of 4-order auto-correlation matrix R of the MUSIC algorithm based on power spectrum estimation procedure of MATLAB
Platform: |
Size: 1024 |
Author: 秀秀 |
Hits:
Description: 掌万皮肤非常地好用啊，大家快来下吧-zhang wan pi fu，fei chang de vb et kb da jia kuai lai xia ba ~~~
Platform: |
Size: 9216 |
Author: 曾大将军 |
Hits:
Description: 用vc6.0解决背包问题。给定 n 种物品和一背包。物品 i 的重量是 wi，其价值为 pi，背包的容量为 m。问应如何选择装入背包中的物品，使得装入背包中物品的总价值最大-Solve the knapsack problem with vc6.0. Species of a given n items and a backpack. The weight of item i is wi, the value of pi, the capacity of backpack m. Asked should be how to choose the items into the backpack, the backpack load in the largest total value of goods
Platform: |
Size: 1024 |
Author: 潘玉丽 |
Hits:
Description: #define PI 3.1415926
double angle=(double)theta/10.0*PI/180.0
double anglecos=cos(angle)
double anglesin=sin(angle)
Platform: |
Size: 22528 |
Author: 陈奇 |
Hits:
Description: #define PI 3.1415926
double angle=(double)theta/10.0*PI/180.0
double anglecos=cos(angle)
double anglesin=sin(angle) -# define PI 3.1415926 double angle = (double) theta/10.0* PI/180.0 double anglecos = cos (angle) double anglesin = sin (angle)
Platform: |
Size: 507904 |
Author: 陈奇 |
Hits:
Description: function [hough_space,hough_circle,para] = hough_circle(BW,step_r,step_angle,r_min,r_max,p)
input
BW:二值图像；
step_r:检测的圆半径步长
step_angle:角度步长，单位为弧度
r_min:最小圆半径
r_max:最大圆半径
p:阈值，0，1之间的数
output
hough_space:参数空间，h(a,b,r)表示圆心在(a,b)半径为r的圆上的点数
hough_circl:二值图像，检测到的圆
para:检测到的圆的圆心、半径
[m,n] = size(BW)
size_r = round((r_max-r_min)/step_r)+1
size_angle = round(2*pi/step_angle)
hough_space = zeros(m,n,size_r)
-function [hough_space,hough_circle,para] = hough_circle(BW,step_r,step_angle,r_min,r_max,p)
input
BW:二值图像；
step_r:检测的圆半径步长
step_angle:角度步长，单位为弧度
r_min:最小圆半径
r_max:最大圆半径
p:阈值，0，1之间的数
output
hough_space:参数空间，h(a,b,r)表示圆心在(a,b)半径为r的圆上的点数
hough_circl:二值图像，检测到的圆
para:检测到的圆的圆心、半径
[m,n] = size(BW)
size_r = round((r_max-r_min)/step_r)+1
size_angle = round(2*pi/step_angle)
hough_space = zeros(m,n,size_r)
Platform: |
Size: 272384 |
Author: 董必磊 |
Hits:
Description: 第四节百度杯A题答案。水杯的问题！To solve this problem, you should know that the volume of one cup is pi * (r * r + R * R + r * R) * h / 3.
If you don t know this formula, you could find by this formula: s * h / 3.
It s the formula to calculte the volume of taper.
The next step after you know the formula is to calculate the high of the water.-A Cup of section IV of Baidu answer questions. The problem of glass! To solve this problem, you should know that the volume of one cup is pi* (r* r+ R* R+ r* R)* h/3. If you don' t know this formula, you could find by this formula : s* h/3. It' s the formula to calculte the volume of taper. The next step after you know the formula is to calculate the high of the water.
Platform: |
Size: 1024 |
Author: 晓天 |
Hits:
Description: 待处理的信号为：
y=sin(2*10000*pi*t)+sin(2*pi*1000*t)。目的是将其中调频分量
sin(2*10000*pi*t)滤除掉-Pending signals: y = sin (2* 10000* pi* t)+ sin (2* pi* 1000* t). The aim is to one frequency component sin (2* 10000* pi* t) to filter out
Platform: |
Size: 322560 |
Author: laopowoaini |
Hits:
Description: PIC 单片机 SPI 例程
PI C 单片机 SPI 例程-PIC single-chip SPI routines
Platform: |
Size: 31744 |
Author: redmajor |
Hits:
Description: 最小二乘法仿真y=20*sin(100*pi*t+pi/3)+4*sin(200*pi*t)+10*sin(300*pi*t)+2*sin(400*pi*t)+6*sin(500*pi*t)波形-y=20*sin(100*pi*t+pi/3)+4*sin(200*pi*t)+10*sin(300*pi*t)+2*sin(400*pi*t)+6*sin(500*pi*t)
Platform: |
Size: 1024 |
Author: 邹文兵 |
Hits:
Description: 采用3-6-1型bp网络学习非线性正弦信号sin(2pi*k/50),其中2*pi/50是正弦信号的频率，k是采样次数。-Bp-based 3-6-1 network used to learn non-linear sinusoidal signal sin (2pi* k/50), which is 2* pi/50 frequency sinusoidal signal, k is the sampling frequency.
Platform: |
Size: 1024 |
Author: fu_jasmine |
Hits:
Description: 判断PI在有限位的情况下是否是循环小数-PI is a recurring decimal to determine whether
Platform: |
Size: 2048 |
Author: nYE |
Hits:
Description: linux下管道监视程序，父进程通过管道发送信息给子进程-linux monitoring procedures under the pipeline, the father of the process of sending information through the pipeline to the child process
Platform: |
Size: 1024 |
Author: hc |
Hits:
Description: 采用极点配置的电压电流双PI闭环PWM逆变器仿真-Pole placement using the voltage and current dual-PI closed-loop simulation of PWM inverter
Platform: |
Size: 18432 |
Author: 孔维靖 |
Hits:
Description: 随机算法的模拟实现 该算法在visual c++2008上实现了pi的求值该算法具有界面实现，用的是随机算法。算法比较简单-Stochastic simulation algorithm to achieve the algorithm in visual c++2008 on the realization of the value of pi for the interface of the algorithm, using a random algorithm. Relatively simple algorithm
Platform: |
Size: 8472576 |
Author: 蒲平 |
Hits:
Description: 蒙特卡罗分析求圆周率，设置循环次数可以调节精度-Monte Carlo analysis for pi, the number of settings can be adjusted cycle accuracy
Platform: |
Size: 1024 |
Author: wanggang |
Hits: