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Description: 这是我自己写的gps航点输出的小程序
功能不太全,主要是取出航点,航点的翻译没做实在不知道该咋办-that I wrote a GPS destinations small output function is not the whole process, mainly out of routes, destinations translation is not done do not know how to manage
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Size: 188578 |
Author: 李晓东 |
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Description: 在本问题的求解中，修桥和挖隧道是两个相类似的求解过程，我们将求解过程分为两个部分：第一、对河岸边一固定点 ，将桥修在 处时，求解由起始点 到经固定点 到居民点 的最短路线。第二、如何确定 的位置，使得总路线的费用最小。我们分别用了两个模型来进行这两部分内容的求解。模型一、针对坡度的限制，利用小区域内的局部最优来达到全局最优。模型二、列出点 有一定的位移时，可以减少的费用 的函数方程，然后利用河岸附近等高线较紧密，公路不能沿偏离等高线方向前进的特性，求出减少的费用 的条件极值，从而确定最佳修桥地点 。最后，我们利用模型一、二的原理对隧道部分的公路做了同样的优化设计，然后得出总的修路费用估计为324万元，较合理。最后，我们对整个做法的误差及合理性做了分析。-in solving this problem, building bridges and two tunnels are dug similar to the solution process, we will be solving process is divided into two parts : the first, on the banks of the river a fixed point of the bridge repair in the Department, from the starting point to solve by the fixed point to settlements in the shortest routes. Second, how to determine the location, making the cost of the smallest general line. We were using the two models, both part of the solution. One model, the slope of the restrictions against use of the local small areas to achieve optimum global optimum. Model 2, listing a certain point of displacement, can reduce the cost of the equation, and then using the riverbank near the contours more closely, not along the highway from contour direction of the character
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Size: 194862 |
Author: 李凌 |
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Description: Everyone knows the Maths important.
the math routes are for beginner.
have a fun.
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Size: 7475 |
Author: 马国信 |
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Description: How to call some functions that you might though it is simle sometimes, but it could take your worthful time.
Try these short routes as fun whenever you take a break. -How to call some functions that you might though it is simle sometimes, but it could take your worthful time. Try these short routes as fun whenever you take a break.
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Size: 3888 |
Author: 马国信 |
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Description: 地理系信息专业必需基础知识的应用 vb与map objects的结合 本软件可提供路线的符号遍历显示-geography information necessary professional knowledge base of vb map objects with a combination of the software available routes traverse the symbols show
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Size: 225640 |
Author: 风沂 |
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Description: 游戏规则
目的：在本游戏中，你将作为一名裁缝，将尽可能多的纽扣穿成
一个闭合的路线。游戏初始有 15 个纽扣，随着时间的增
加，纽扣数目也增加，当达到70个时游戏即结束。
规则：只能在有纽扣的点穿线，且只能在水平方向或竖直方向穿
线。线可交叉，但有纽扣的点不能交叉连接。
秘诀：要尽可能使连线长且该连线上的纽扣数多。-purpose of the rules of the game : In the game, you will act as a tailor, as much as a button to wear closed routes. Initial games are 15 buttons, with the increase in time, increase the number of buttons, reached 70 at the end of that game. Rules : only when there is the point of threading button, and then only in the horizontal direction or vertical direction of threading. Cross-line, but the point Button can cross-connect. The secret : To the extent possible, but the long-line connections on the button a few more.
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Size: 50125 |
Author: 李平 |
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Description: 一、民航管理系统设计：
民航系统功能：能给客户提供订票、退票的功能，还能浏览航班航线信息（如航班号、航线、飞行时间及成员订额）和查询航班信息；
民航系统的具体实现如下形式：
1.系统以菜单方式工作
2.航班信息录入功能(航班信息用文件保存)－－输入
3.航班信息浏览功能－－输出
4.查询航线（按航班号查询）
5.承办订票和退票业务
-a CAD management system design : CAD system function : to provide their customers with booking, a refund of the function, flight routes can browse information (such as flight number, route, time of flight and members of the amount set), and check their flight information; the CAD system is a concrete realization of the following forms : 1. the menu system to work two ways. flight information into functional (flight information in document preservation) -- input 3. flights information browsing -- output 4. inquiries route (flights inquiry) 5. contractors booking business and Refund
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Size: 101753 |
Author: 李敬 |
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Description: 一个飞机定票系统,可以实现飞机定票,客户资料加载及删除,单航线有限只有两条,大家可以加以修改使用.-a plane ticket system, can achieve a plane ticket, customers loading and deletion of information, single only two limited routes, we can use modified.
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Size: 3702 |
Author: 优游 |
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Description: 航空定票系统模拟软件
要求C或C++编写。
具有功能：
可以录入航班情况；
查询某个航线的情况，可以输入起飞抵达城市，查询飞机航班情况；
可以订票；
可退票，退票后修改相关数据文件；
客户资料：姓名，证件号，订票数量及航班情况，定单有编号；
修改航班信息。
-air ticket system simulation software requirements C or C preparation. With function : entry flight; Inquiries certain routes, can be imported takeoff arrival, inquiries flights; can booking; refund, refund after the revision of relevant data files; customer information : name, identification number, booking flights and the number of orders is numbered; changes flight information.
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Size: 13019 |
Author: hi |
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Description: 最短路径算法源码，很多人需要的。本人载网站开发gis,游自编的最短路径查询程序，速度特快，3万节点，35000条路全部遍历，只需1秒。现将最短路径的思路告诉大家，希望大家在优化，并用不同语言编制，我正在学delphi,准备用delphi做成库，本例以由拓扑关系的arc/info 文件为数据源。其中a1,b1,c1是以fnode排序生成的数组，a1对应fnode,b1对应tnode,c1对应length,同样a2,b2,c2,是以tnode 生成的数组。Indexa1是对应某一起点与其相连的终点的个数，indexb1时对应某一终点与其相连的起点的个数，即其拓扑关系。
-shortest path algorithm source, a lot of people in need. I gis contained web site development, Yu directed the shortest path query procedures, speed express routes, 30,000 nodes, all 35,000 traverse the road, only a seconds. Now Shortest Path tell you the idea that we should optimization, and use different language, delphi is studying, I wanted to use delphi caused basement, in the cases from the arc topology / info file as the data source. Which a1, b1, c1 fnode ranking is generated by the array, a1 fnode counterparts, b1 counterparts tnode, c1 corresponding length, the same a2, b2, c2, tnode is generating array. Indexa1 counterparts is a starting point, linked with the end of the number, indexb1 counterparts at a terminal connected to its starting point the number, which is its topologic
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Size: 2416 |
Author: x |
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Description: 公交车路线B主要是模拟公交系统来发出汽车 -bus routes B is the main transit system simulation issued car
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Size: 288063 |
Author: 546 |
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Description: 钢管订购和运输的最优规划
程序使用说明：
两种方法进行
1，运行deal3,输入D,得到单价的矩阵7*15 运行showlj,得到运输的路线；
2, 运行deal2,输入D,得到单价的矩阵7*15
-ordering pipe and the optimal transportation planning process for use : two methods for a running deal3. D input, to be priced matrix 7 * 15 showlj operation, the transportation routes; 2. running deal2 input D, the matrix to be priced 15 7 *
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Size: 31943 |
Author: 孙竟飞 |
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Description: 本软件能够查询南京市的公交线路，功能包括指定站点查询通过其的路线，指定路线查询其通过的站点，查询指定的两个站点的路线，支持转车。（能力有限，比较简单，但是原创，期盼通过）-inquiries Nanjing bus lines, including the designation of functions through its site for the line, inquiries about their designated routes through the site, for the two sites designated routes, support interchange. (Limited capacity, relatively simple, but original and hopes through)
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Size: 37749 |
Author: magicW |
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Description: 用遗传算法解决城市的访问次序，可使其
旅行路线的总长度最短 可从该程序借鉴到其他应用
-using genetic algorithms to solve the city for the visit, travel routes can make the total length of the shortest can draw from the procedures of other applications
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Size: 8120 |
Author: 候海 |
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Description: 已知n个城市之间的相互距离，现有一个推销员必须遍访这n个城市，并且每个城市只能访问一次，最后又必须返回出发城市。如何安排他对这些城市的访问次序，可使其旅行路线的总长度最短？-known cities between the distance from the existing one must salesman n visited this city, every city and can only be visited once, finally starting to return to the city. How to arrange for him to visit these cities priorities, it can travel routes, the total length of the shortest?
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Size: 4223 |
Author: zhangy21cn |
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Description: csharp开发，为乘铁路出行的用户提供路线信息，计算特定路线的距离、两城镇间不同路线的数量并找出最短路线-csharp development of the railway transportation by the user route information to calculate the distance between specific routes, two different routes between towns in the volume and find the shortest route
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Size: 11264 |
Author: zhj |
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Description: VB绘制公交线路节点程序经典代码VB Classic draw bus routes node procedure code
-VB Classic draw bus routes node procedure code
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Size: 2048 |
Author: lijing |
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Description: DERIVING EFFICIENT MOBILE AGENT ROUTES IN WIRELESS SENSOR NETWORKS WITH NOID ALGORITHM
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Size: 372736 |
Author: kotaro |
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Description: 介绍了利用 WebService 技术结合数据库实现城市公共交通线路查询功能， 实现公交
线路数据库的设计和使用 C# 基于数据库的公交路线查询 WebService， 查询结果以 XML 格式返回数据。-It describes the use of WebService technology with implementation of urban public transport routes queries to achieve bus
Line design and query using C# WebService based bus route , query results are returned in XML data format.
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Size: 450560 |
Author: 罗青木 |
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Description: 问题描述
当一个用户从甲地到乙地时，由于不同需求，就有不同的交通方式及不同的交通路线。有人希望以最快速度到达，有人希望以最短距离到达，有人希望用最少的费用等。交通方式有公交车和地铁。编写一北京公交线路查询系统，通过输入起始站、终点站，为用户提供三种或以上决策的交通咨询。(problem description
When a user goes from point a to point b, there are different modes of transportation and different routes due to different demands. Some people want to arrive at the fastest speed, some people want to arrive at the shortest distance, some people want to use the least cost and so on. There are buses and subways. Compile a Beijing bus line inquiry system, provide users with three or more kinds of traffic consultation by entering the starting station and the terminal station.)
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Size: 431104 |
Author: 想梦 |
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