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Description: 使用说明:
后台主要功能如下：
一、系统管理：管理员管理，可以新增管理员及修改管理员密码；发布网站公告；进行网站配置；网站统计和数据库备份，为保证您的数据安全本系统采用了数据库备份功能；上传文件管理，管理你增加产品时上传的图片及其他文件。
二、企业信息：可设置修改企业的各类信息及介绍。
三、产品管理：产品类别新增修改管理，产品添加修改以及产品的审核。
四、询价管理：查看询价的详细信息及询价处理。
五、下载中心：可分类增加各种文件，如驱动和技术文档等文件的下载。
六、会员管理：查看修改删除会员资料，及锁定解锁功能。
七、新闻管理：能分大类和小类新闻，不再受新闻栏目的限制。
八、留言管理：管理信息反馈及注册会员的留言，注册会员的留言可在线回复，未注册会员可使用在线发信功能给于答复。
九、荣誉管理：新增修改企业荣誉栏目的信息。新增修改企业形象栏目的信息。
十、人才管理：发布修改招聘信息，人才策略栏目管理，应聘管理。
十一、营销网络：修改营销网络栏目的信息。
十二、调查管理：发布修改调查。
-Usage:
The background of the main functions are as follows:
First, the system management: administrator management, administrators can add and modify the administrator password release site notice to carry out a site-targeted website statistics and database backup, in order to ensure your data security of the system using a database backup function Upload document management, management of the product when you upload pictures and other documents.
Second, enterprise information: can be set to amend the types of enterprise information and introduction.
Third, Product Management: Product Category Added to amend management, product revisions, as well as add products reviewed.
Fourth, Inquiry Management: View Inquiry Inquiry For more information and treatment.
V. Download Center: You can increase the classification of various documents, such as drivers and technical documentation such as file downloads.
Sixth, Member Management: See amendments to delete member information,
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Author: du wei hong |
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Description: JavaScript是由Netscape公司开发并随Navigator导航者一起发布的、介于Java与HTML之间、基于对象事件驱动的编程语言，正日益受到全球的关注。因它的开发环境简单，不需要Java编译器，而是直接运行在Web浏览器中，而因倍受Web设计者的所爱。为了帮助我国广大计算机用户尽快了解和掌握这些新技术,本着先进的技术,要大家分享的原则,电脑网络学校特组织JavaScript技术讲座。其各讲内容为:
第一讲 JavaScript语言概况
第二讲 JavaScript基本数据结构
第三讲 JavaScript程序构成
第四讲 基于对象的JavaScript语言
第五讲 创建新对象
第六讲 使用内部对象系统
第七讲 窗口及输入输出
第八讲 WEB页面信息交互
第九讲 实现更复杂交互-JavaScript was developed by Netscape Navigator and Navigator in conjunction with the release, between Java and HTML between the event-driven object-based programming language, is increasingly affected by global concerns. Development environment because of its simple, do not need Java compiler, but direct running on Web browser, and because of the much loved Web designers. In order to help the majority of computer users in China as soon as possible to understand and master these new technologies, based on advanced technology, it is necessary to share with you the principles of computer networks in schools organized special lectures JavaScript technology. Talk about its content as follows:
First language speakers JavaScript Overview
The second stresses the basic data structure of JavaScript
JavaScript speakers constitute the third procedure
The fourth talk of the JavaScript object-based language
The fifth stresses create a new object
The sixth stresses the use of internal object sy
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Author: meige |
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Description: 本例中四次输出了a,b的值，但由于格式控制串不同，输出的结果也不相同。第四行的输出语句格式控制串中，两格式串 d 之间加了一个空格(非格式字符)，所以输出的a,b值之间有一个空格。第五行的printf语句格式控制串中加入的是非格式字符逗号， 因此输出
的a,b值之间加了一个逗号。第六行的格式串要求按字符型输出 a,b值。第七行中为了提示输出结果又增加了非格式字符串。
-In this case four times the output of a, b values, but because of the format control string is different from the results of the output is not the same. The fourth line of the output control string in the format statement, the two format string d a space between the (non-format characters), so the output of a, b there is a space between. The fifth line of the statement printf format string to control the format by adding the non-comma characters, so the output of a, b the value of a comma in between. The sixth line of the format requested by the character string output a, b values. The seventh line of the output results in order to prompt an increase of non-format string.
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Author: lili |
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Description: 孙鑫vc++深入详解第六课，菜单的工作原理及编写应用，菜单命令消息在MFC框架程序的几个类中的传递顺序和处理过程-Sun Xin vc++ in-depth Xiangjie sixth classes, the menu works and preparing applications, the menu command message in the MFC framework of the program delivery of the order of several classes and processes
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Size: 56749056 |
Author: 张帅 |
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Description: Fifth-order/Sixth-order Runge-Kutta-Verner variable step-size method
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Size: 2048 |
Author: katore vishal |
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Description: 1.从键盘上输入正、反转命令，转速参数（16级）和转动步数显示在LED显示器上。
显示器上显示：第一位为0表示正转，为1表示反转；第二位0~F为转速等级，第三到第六位设定步数。
2. 单片机依显示器上显示的正、反转命令，转速级数和转动步数进行相应动作，转动步数减为零时停止转动。-1. From the keyboard input is, reverse order, speed parameters (16) and rotating steps displayed in the LED display. On the display: the first is to switch to 0, to 1 for reverse second 0 ~ F for the speed rating, the third to the sixth set number of steps. 2. Microcontroller is displayed by the monitor, reverse order, and rotational speed of progression steps for the appropriate action steps by zero rotation to stop rotation.
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Author: 小马 |
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Description: 题目是这样的，一队标上编号的犯人，让长官给出一个数字，比如说6，然后从犯人1开始数，数到6的就拉出去毙掉，再从7开始数到第六个拉出去毙掉，如果队伍到头了，依旧按顺序从第一个犯人开始数，这样最后只剩下一个犯人，就释放掉。-This topic is, a team of marked numbers of prisoners, so that Executive is given a number, say 6, then start from the number of inmates a few to pull out of 6 on banning federal funding, and then start counting from 7 to sixth pull out banning federal funding, if the team coming to an end, still a prisoner in order starting from the first number, so that last only a prisoner, to be released
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Author: wang |
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Description: Exercise 10: Pointers
1. Write a program that reads 5 integers into an array, and then uses four different methods of accessing the members of an array to print them out in reverse order.
2. Write a program that reads 8 floats into an array and then prints out the second, fourth, sixth and eighth members of the array, and the sum of the first, third, fifth and seventh, using pointers to access the members of the array.
3. Write a program that use a SINGLE FUNCTION （用一个函数）to find and return simultaneously both the lowest and highest values in an array of type int. Suppose the size of the array is 6.
-Exercise 10: Pointers
1. Write a program that reads 5 integers into an array, and then uses four different methods of accessing the members of an array to print them out in reverse order.
2. Write a program that reads 8 floats into an array and then prints out the second, fourth, sixth and eighth members of the array, and the sum of the first, third, fifth and seventh, using pointers to access the members of the array.
3. Write a program that use a SINGLE FUNCTION （用一个函数）to find and return simultaneously both the lowest and highest values in an array of type int. Suppose the size of the array is 6.
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Size: 1024 |
Author: Li Jingyang |
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Description: 六阶巴特沃斯低通滤波器cpp程序，戒指频率为35Hz-Sixth-order Butterworth low-pass filter cpp program
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Size: 1024 |
Author: 陈江明 |
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Description: 六阶状态空间模型，同步发电机模型和网络负载模型，可用于发电机励磁系统控制仿真-Sixth-order state space model, synchronous generator model and network load model can be used to control simulation of generator excitation system
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Size: 10240 |
Author: fhongxue |
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Description: 第六阶Runge+-+Kutta微分方程-Sixth-order differential equation ........... Runge+-+Kutta
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Author: Jack |
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Description: 后台主要功能如下：
一、网站基本设置；
二、企业信息；
三、产品管理；
四、订单管理；
五、下载中心；
六、导航管理；
七、新闻管理；
八、留言管理；
九、荣誉管理；
十、人才管理；
十一、营销网络；
十二、栏目管理；
十三、全站中英静态页面生成；
十四、友情链接；
十五、模板管理。-Background The main functions are as follows:
A website basic settings
Second, corporate information
Third, product management
Fourth, order management
V. Download Center
Sixth, navigation management
Seven, news management
Eight, message management
Nine, honors management
Ten, talent management
XI, marketing network
XII, section management
Thirteen, the station Britain static page generation
Fourteen, Links
Fifteen, template management.
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Author: 杨帆 |
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Description: 同步机块在发电机或电动机模式运营。操作模式是由机械功率的信号(阳性发电机模式,不利于运动模式。-mode). The electrical part of the machine is represented by a sixth-order state-space model and the mechanical part is the same as in the Simplified Synchronous Machine block.
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Author: 王超 |
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Description: 这是21天学通C#中文版，第四版，虽然现在有第六版了，仍然有许多刚入门的程序猿喜欢用VC2008，第六版的代码有相当一部分在VC2008上运行不了，为了帮助更多入门的程序猿，把第四版传上来了。-It is 21 days to learn through C# Chinese version, the fourth edition, although there are now sixth edition, there are still a lot just to get into the program ape like to use VC2008, the sixth edition of a considerable part of the code running on the VC2008 can not, in order to help Getting more programs ape, the fourth edition of the pass will come up.
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Author: 江村 |
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Description: 2维声波方程，时间2阶精度，空间六阶精度，恒密度介质。程序里包含吸收边界和自由边界。-2-dimensional acoustic wave equation, time second-order accuracy, spatial sixth-order accuracy, constant density of the medium. Program contains absorbing boundary and free boundary.
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Size: 9216 |
Author: ningwang |
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Description: 后台主要功能如下：
一、网站基本设置；二、企业信息； 三、产品管理；四、订单管理； 五、下载中心； 六、导航管理；七、新闻管理；八、留言管理；九、荣誉管理； 十、人才管理； 十一、营销网络；十二、栏目管理；十三、全站中英静态页面生成；十四、友情链接； 十五、模板管理。-Background main functions are as follows:
A web site, the basic settings second, enterprise information third, product management fourth, order management fifth, Download Center sixth, navigation management news management eight, message management Ninth, honor management ten, talent management Xi, marketing network 12, column management thirteen, the station Britain static page generation fourteen, links 15, template management.
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Author: 彭伟华 |
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Description: 第1章 线性定常系统的状态空间描述及运动分析
第2章 线性定常系统的能控性
第3章 状态反馈与闭环极点配置
第4章 线性定常系统的能观性
第5章 能控性，能观性与传递函数
第6章 状态观测器
第7章 线性二次型最优控制与系统输入输出解耦
第8章 不确定线性系统的鲁棒二次镇定(The first chapter is the description of state space and motion analysis of linear stationary system
The second chapter is the controllability of linear time invariant systems
The third chapter state feedback and closed-loop pole placement
The fourth chapter is the observability of linear time invariant systems
The fifth chapter controllability, observability and transfer function
The sixth chapter state observer
The seventh chapter is the linear two order optimal control and the system input-output decoupling
Eighth chapter two robust stabilization of uncertain linear systems)
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Author: ZenoOfElea
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Description: 波动方程正演MATLAB六阶有限差分程序(Wave equation forward modeling MATLAB sixth order finite difference program)
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Author: skl1993
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Description: 创建一个静态的顺序表存放整数。大小为10.完成以下的操作输入6个整数，1.打 印出顺序表中的内容，并显示表中剩余的空间个数。在顺序表中的第3个位置插入元素O.2.打印出顺序表中的内容，并显示表中剩余的空间个数。再试图向表中第11个位置插入整数0,3.程序提示超出范围。4.删除表中第6个元素，打印出顺序表中的内容，并显示表中剩余的空间个数。
二：编写一程序，动态地创建一个顺序表。要求顺序表初始长度为20,向顺序表中输 入15个整数，并打印出来: 再删除顺序表中的第5个元素。打印出删除后的结果。(Create a static sequence table to store integers. The size is 10., the following operations are input 6 integers, 1. prints out the contents in the sequence table, and displays the remaining space in the table. In the third place of the sequence table, insert the element O.2., print out the contents in the sequence table, and show the remaining space in the table. Then try to insert integer 0,3. program into eleventh locations in the table, indicating that it is out of range. 4., delete the sixth elements in the table, print out the contents in the sequence table, and show the remaining space in the table.
Two: write a program to create a sequence table dynamically. It is required that the initial length of the sequence table is 20, input 15 integers into the sequence table, and print it out: then delete the fifth elements in the order table. Print out the result after the deletion.)
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Author: 鬼谷丶逝 |
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