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Description: 一个用java实现的解决理发师睡觉问题的代码-used to achieve a solution to the problem of sleep Barber code
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Size: 1619 |
Author: ivyinwinter |
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Description: 理发师睡觉问题 可以利用它来解决嗜睡的理发师问题 进程调度与信号量问题-Seville sleep problems can use it to solve the problem sleepiness barber process scheduling and capacity problems of signal
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Size: 861 |
Author: 高磊 |
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Description: 一个用java实现的解决理发师睡觉问题的代码-used to achieve a solution to the problem of sleep Barber code
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Size: 1024 |
Author: ivyinwinter |
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Description: 理发师睡觉问题 可以利用它来解决嗜睡的理发师问题 进程调度与信号量问题-Seville sleep problems can use it to solve the problem sleepiness barber process scheduling and capacity problems of signal
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Size: 1024 |
Author: 高磊 |
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Description: 理发师睡觉问题两种实现方法-Barber sleep problems of two methods
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Size: 3072 |
Author: |
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Description: 经典的理发师问题，用C语言实现，程序实现了几个进程之间的相互调度关系，预防死锁。-Classic barber problem using C language, the program realize a number of the process of scheduling the relationship between the prevention of deadlock.
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Size: 10240 |
Author: 王栩 |
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Description: 睡眠理发师问题算法实现， 在LINUX 操作系统下实现的算法。-Barber Algorithm sleep problem, under the LINUX operating system algorithms.
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Size: 56320 |
Author: ##真 |
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Description: 一个理发店，只有一个理发师，只有n张可供顾客等待理发的椅子，如果没有顾客，则理发师睡觉；如果有一顾客进入理发店发现理发师在睡觉，则把他叫醒，写一个程序协调理发师和顾客之间的关系。-A barber shop, there is only one barber, only the n Zhang barber' s chair waiting for customers, without customers, the barber to sleep if there is a customer into the barber shop barber was found sleeping, others view him wake up, write a program Coordination between barber and customer relations.
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Size: 13312 |
Author: leaf |
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Description: 理发师睡眠问题，实验课的作业，各位可以参考，还是不错的-Barber sleep problems, experimental studies homework assignment, you can refer to, or good
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Size: 1024 |
Author: qxf |
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Description: 这是关于多线程的理发师睡觉问题,对于在校大学生或者初学者可以参考学习用-This is a multi-threaded barber on sleep problems, for college students or beginners can learn to use reference
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Size: 4225024 |
Author: 老岩 |
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Description: GUI barbershop with java
5 customer with barber sleep and cutting hair
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Size: 433152 |
Author: nina |
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Description: ,（1）一个理发店接待室有n张椅子，工作室有1张椅子； （2）没有顾客时，理发师睡觉； （3）第一个顾客来到时，必须将理发师唤醒； （4）顾客来时如果还有空座的话，他就坐在一个座位上等待； （5）如果顾客来时没有空座位了，他就离开，不理发了； （6）当理发师处理完所有顾客，而又没有新顾客来时，他又开始睡觉。用条件变量实现(3张椅子)-, (1) a barber shop reception room with n chairs, studios have a chair (2) no customers, the barber sleep (3) the first customer arrives, the barber must wake up (4 ) to the customer if there are empty seats, then when he sat on a seat to wait (5) If the customer to an empty seat when not, and he left, not a haircut (6) When the barber finished with all customers, but no new customers to come, he began to sleep. With the condition variable implementation (three chairs)
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Size: 1024 |
Author: 贾流洋 |
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Description: 基于操作系统的，理发师睡觉的问题，关于信号量的问题-Based on the operating system, the barber sleep problems, about the amount of signal
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Size: 1643520 |
Author: haha |
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Description: （1）一个理发店接待室有n张椅子，工作室有1张椅子；
（2）没有顾客时，理发师睡觉；
（3）第一个顾客来到时，必须将理发师唤醒；
（4）顾客来时如果还有空座的话，他就坐在一个座位上等待；
（5）如果顾客来时没有空座位了，他就离开，不理发了；
（6）当理发师处理完所有顾客，而又没有新顾客来时，他又开始睡觉。
用条件变量实现(3张椅子)
-(1) a barber shop in the reception room with n chairs, the studio has a chair (2) no customers, the barber sleep (3) The first customer arrives, the barber must wake up (4) When customers come to, then if there is room, he sat on a seat to wait (5) If the customer does not come empty seats, and he left, not a haircut (6) When the barber finished with all customers, and and no new customers come, he began to sleep. With the condition variable implementation (three chairs)
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Size: 1024 |
Author: 33 |
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Description: 理发店里有一位理发师，一把理发椅和 N 把供等候理发的顾客坐的椅子 如果没有顾客,则理发师便在理发椅上睡觉。当一个顾客到来时，他必须先唤醒理发师。如果顾客到来时理发师正在理发，则如果有空椅子，可坐下来等；否 则离开。操作系统信号量控制进程同步。-Barbershop, a hairdresser, a barber chair and N customer sat waiting Barber chair if no customers, the barber would sleep in the barber chair. When a customer comes, he must wake up to the barber. If the customer comes barber is Barber, if the empty chair, sit down and so on otherwise leave. The semaphore control of the operating system process synchronization.
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Size: 171008 |
Author: Miami |
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Description: 睡眠理发师问题源码，理发店有一位理发师，一把理发椅和n把用来等候理发的椅子。如果没有顾客，则理发师在理发椅上睡觉，顾客理来时，如理发师闲则理发，否则如有空椅则坐等，没有空椅则离开，编写程序实现理发师和顾客程序，实现进程控制，要求不能出现竞争。-This is a classic problem of IPC, there is a barber barber shop, a barber chair and n barber chair waiting to be used. If there is no customer, the barber in the barber chair to sleep, to manage the customer, such as when the barber barber idle, otherwise as empty chairs are waiting, you leave no empty chairs, barbers and customers realize programming procedures to achieve process control requirements can not compete.
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Size: 2048 |
Author: 亦噷依弋 |
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Description: 操作系统课程设计 理发师睡眠问题 经典ipc-Courses on operating system design classic barber sleep problems ipc
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Size: 4096 |
Author: jadelin |
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Description: 实现睡眠理发师问题，一个理发师服务多个顾客。(To achieve a sleep barber problem, a hairdresser serves multiple customers.)
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Size: 1024 |
Author: 时光清浅
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Description: 有一个理发师，一把理发椅和n把提供给等候理发的顾客座的椅子。如果没有顾客，则理发师便在理发椅子上睡觉；当第一个顾客到来时，必须唤醒该理发师进行理发；如果理发师正在理发时又有顾客到来，则如果有空椅子可坐，他就坐下来等待，如果没有空椅子，他就离开理发店。
为理发师和顾客各编一段程序描述他们的行为，要求不能带有竞争条件，试用P、V操作实现。(There was a barber, a barber's chair and a chair n offered to the customer waiting for the haircut. If no customers, the barber would sleep in the barber chair; when the customer comes first, must arouse the barber for a haircut; if the barber is the barber again when customers come, if the empty chair sitting, he sat down to wait, if there is no empty seat, he left the barber shop.
Prepare a program for barbers and customers to describe their actions, requiring no competition, and trial P and V operations.)
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Size: 1024 |
Author: 千万不要慌
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