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Description: 1. 学习和掌握结构体和链表相关知识，掌握程序设计基本过程；
2. 简单的系统与功能分析，了解航班信息管理系统的需求，用C语言开发航班信息管理系统；
3. 建立数据结构链表，数据内容包括航班号、航线、起飞时间、到达时间、机型、所属公司、价格；
4. 编写实现程序功能的各个函数；
5. 建立一个测试数据表，包含十多条航班信息，进行数据测试；
6. 使用数据链表实现数据的：录入、查询、显示、删除、修改、排序、文件保存、系统退出等功能；
调试系统，处理少数系统出错，优化系统界面。
-#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <conio.h>
#define LEN sizeof(struct AIR)
struct AIR//定义结构体
{
char Number[10]
char Airline[15]
char start_time[6]
char arrived_time[6]
char Plane[6]
char Company[15]
float Price
struct AIR*next
}
Platform: |
Size: 4096 |
Author: Joe |
Hits:
Description: NStepSCAN N步磁盘扫描调度算法C++程序-#include "stdafx.h"
#include "stdlib.h"
int L,P
int a[20]
int flag //访问位
typedef struct TASK
{
int requrie
int io
} TASK
TASK T[50][50]
TASK N[50]
int diskway //当前磁道
void iodowith()
void init()
{
int i,j
for(i=0 i<20 i++)
{
for(j=0 j<20 j++)
{
T[i][j].requrie=-1
}
}
for(i=0 i<L i++)
{
for(j=0 j<P j++)
{
T[i][j].requrie=rand() 200
T[i][j].io=rand() 2
}
}
}
void output()
{
printf("磁盘访问的初始顺序是：\n")
for(int i=0 i<L i++)
{
printf("第 d组是:\n",i+1)
for(int j=0 j<P j++)
{
printf(" d d\t",T[i][j].requrie,T[i][j].io)
}
printf("\n")
}
}
void sort_btos(TASK x[],int n)
{
int i,j,k
TASK t
for(i=0 i<n-1 i++)
{
k=i
for(j=i+1 j<n j++)
if(x[j].requrie>x[k].requrie)
k=j
if(k!=i)
{
t=x[i]
x[i]=x[k]
x[k]=t
}
}
}
void sort_stob(TASK x[],int n)
{ int i,j,k
TASK t
fo
Platform: |
Size: 1024 |
Author: 吴英杰 |
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Description: 矩阵操作 c++实现 课程设计
#include <iostream.h>
#include <stdlib.h>
#include<iomanip.h>
void fanzhuan1(int b[5][5])
void fanzhuan2(int b[5][5])
void juandong1(int b[5][5])
void juandong2(int b[5][5])
void print(int b[5][5])
int a[5][5]
void start(int b[5][5]) //初始化数组
{
int i,j
for(i=0 i<5 i++)
for(j=0 j<5 j++)
b[i][j]=a[i][j]
}
void print(int b[5][5]) //输出函数
-Matrix operation
Platform: |
Size: 2048 |
Author: 黄苏敏 |
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Description: 在C++用递归实现链表逆序 使得倒序输出。-#include <stdio.h>
#include <stdlib.h>
#include <time.h>
const int M=10
typedef int Type
typedef struct Node{
Type data
struct Node* next
}Node
void add_elem(Node**head,Type data){
Node* tmp = (Node*)malloc(sizeof(Node))
tmp->data = data
tmp->next = (*head)
*head = tmp
}
void print_list(Node*head){
while(head){
printf(“ d “, head->data)
head = head->next
}
printf(“\n”)
}
void reverse_list(Node**head){
if(!*head)//如果(*head)==NULL
return
Node*p1,*p2
p1 =*head
p2 = (*head)->next
if(!p2)//如果没有下一个节点
return
reverse_list(&p2) //同时存在两个节点就要进行翻转
p1->next->next = p1
p1->next = NULL //主要是保证，第一个节点指向NULL
(*head) = p2
}
int main(){
Node*head = NULL
for(int i=0 i<M i++)
add_elem(&head, rand() 100)
print_list(head)
reverse_list(&head)
print_list(head)
}
Platform: |
Size: 3072 |
Author: ye zi |
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Description: c++头文件用来加载c++动态库时候的头文件，stdlib.h的头文件-c++ code
Platform: |
Size: 1024 |
Author: 刘浪 |
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Description: 最新版本的ffplay，已经调试成功的代码。-/*
* Various utilities for command line tools
* Copyright (c) 2000-2003 Fabrice Bellard
*
* This file is part of FFmpeg.
*
* FFmpeg is free software you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation either
* version 2.1 of the License, or (at your option) any later version.
*
* FFmpeg is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with FFmpeg if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
*/
#include <string.h>
#include <stdlib.h>
#include <errno.h>
#include <math.h>
/* Include only the enabled headers s
Platform: |
Size: 90112 |
Author: 金丰 |
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Description: 用C语言编写实现解释器，希望对你们有所帮助。
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
main()-C language interpreter, you want to be helpful.# Include <stdio.h># Include <stdlib.h># Include <string.h> main ()
Platform: |
Size: 1024 |
Author: 杨晨 |
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Description: 以前自己编的一个小游戏，输入姓名然后可以对战，可以自娱自乐一下-#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define S Sleep(1000)
#define P printf
char name1[20],name2[20]
int k1,k2,i,t1,t2,sxq
int x1=100,x2=100,pow1,pow2,spe1,spe2
void main()
{
void xz(int pow1,int pow2,int spe1,int spe2)
void zs(int c)
int xh,error
char js
START:
while(1)
{
P(" \n · 名字对战游戏v2.2 · \n\n")
P(" ====================\n | 1.开始游戏 |\n")
P(" \n | 2.游戏介绍 |\n")
P(" \n | 3.关 于 |\n")
P(" \n | 4.退 出 |\n
Platform: |
Size: 2048 |
Author: 安若 |
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Description: C语言实验5,学生信息管理系统#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#include "malloc.h"
-student infomation management system
Platform: |
Size: 12288 |
Author: 月心月士 |
Hits:
Description: C运行库函数介绍（stdio.h stdlib.h）-C runtime library functions (stdio.h stdlib.h)
Platform: |
Size: 3072 |
Author: spp |
Hits:
Description: #include "stdlib.h"
#include"graphics.h"
main()
{
int gd=DETECT,gr,a[8],b[8],x,y,i,j,c
initgraph(&gd,&gr,"")
randomize()
for( !kbhit() )
{
x=rand() 500+100 /*随机中心坐标*/
y=rand() 300+100
a[0]=x /*各点坐标的计算,我的烟花图形没能是圆的*/-# Include " stdlib.h" # include " graphics.h" main () {int gd = DETECT, gr, a [8], b [8], x, y, i, j, c initgraph (& gd, & gr , " " ) randomize () for ( ! kbhit () ) {x = rand () 500+100 /* Random center coordinates*/y = rand () 300+100 a [0] = x /* calculate the coordinates of each point, I was not able to fireworks graphics is round* /
Platform: |
Size: 1024 |
Author: 阿鑫 |
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Description: #include <stdio.h>
#include <stdlib.h>
//输入十进制数N和转化的进制数M
void trans(int n,int m)
{ char str[100] int i
for(i=0 n>0 i++)
{if (n m<10) {str[i]=n m+ 0 }
else {str[i]=n m-10+ A }
n=n/m
}
for(n=i n>0 n--){printf(" c",str[n-1]) }
}
void main()
{ int m,n,x char ch
printf("给定进制 M---")
scanf(" d",&m)
loop:
printf("给定一个 d 进制的数 X---",m)
fflush(stdin) //一个M进制的数X转10进制
for(x=0 )
{ ch=getchar()
if(ch>= 0 && ch<= 9 ) { n=ch- 0 }
else if(ch>= a && ch<= z ) { n=ch- a +10 }
else if(ch>= A && ch<= Z ) { n=ch- A +10 }
else { break }
if(n>=m){goto loop }
x=x*m+n
}
printf("转换成 10 进制的数为 --- d\n",x)
printf("给定要转换成的进制 N---")
scanf(" d",&m)
printf("转换成 d 进制后的结果 ---",m)
trans(x,m)
printf("\n")
}-#include <stdio.h>
#include <stdlib.h>
//输入十进制数N和转化的进制数M
void trans(int n,int m)
{ char str[100] int i
for(i=0 n>0 i++)
{if (n m<10) {str[i]=n m+ 0 }
else {str[i]=n m-10+ A }
n=n/m
}
for(n=i n>0 n--){printf(" c",str[n-1]) }
}
void main()
{ int m,n,x char ch
printf("给定进制 M---")
scanf(" d",&m)
loop:
printf("给定一个 d 进制的数 X---",m)
fflush(stdin) //一个M进制的数X转10进制
for(x=0 )
{ ch=getchar()
if(ch>= 0 && ch<= 9 ) { n=ch- 0 }
else if(ch>= a && ch<= z ) { n=ch- a +10 }
else if(ch>= A && ch<= Z ) { n=ch- A +10 }
else { break }
if(n>=m){goto loop }
x=x*m+n
}
printf("转换成 10 进制的数为--- d\n",x)
printf("给定要转换成的进制 N---")
scanf(" d",&m)
printf("转换成 d 进制后的结果---",m)
trans(x,m)
printf("\n")
}
Platform: |
Size: 9216 |
Author: 868123 |
Hits:
Description: 俄罗斯方块
。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。
#include <iostream>
#include <stdlib.h>
#include <windows.h>
#include <time.h>
#include <conio.h>
using namespace std
#define A1 0//A代表长条型，B为方块，C为L型，D为闪电型（实在无法描述那个形状）
#define A2 1
#define B 2
#define C11 3
#define C12 4
#define C13 5
#define C14 6
#define C21 7
#define C22 8
#define C23 9
#define C24 10
#define D11 11
#define D12 12
#define D21 13
#define D22 14
/*typedef struct COORD { // coord.
SHORT X // horizontal coordinate
SHORT Y // vertical coordinate
} COORD
*/
void SetPos(int i,int j)//设定光标位置
{
COORD pos={i,j}
HANDLE Out=GetStdHandle(STD_OUTPUT_HANDLE)
SetConsoleCursorPosition(Out, pos)
}-Tetris. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .# Include <iostream># Include <stdlib.h># Include <windows.h># Include <time.h># Include <conio.h> using namespace std # define A1 0// A representative of the long bar, B is a block, C is L-shaped, D is the Lightning (really can not describe the shape)# define A2 1# define B 2# define C11 3# define C12 4# define C13 5# define C14 6# define C21 7# define C22 8# define C23 9# define C24 10# define D11 11# define D12 12# define D21 13# define D22 14 /* typedef struct COORD {//coord SHORT X .// horizontal coordinate SHORT Y // vertical coordinate} COORD */void SetPos (int i, int j)// set the cursor position {COORD pos = {i, j} HANDLE Out = GetStdHandle (STD_OUTPUT_HANDLE) SetConsoleCursorPosition (Out, pos) }. . . .
Platform: |
Size: 275456 |
Author: 天河 |
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Description: 用于计算印度神庙的柱子问题，怎样子才能以最快速的方式算出其最优顺序。-#include stdio.h
#include stdlib.h
void move(char getone,char putone)
{
printf( c-> c\n ,getone,putone)
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)
move(one,three)
else
{
hanoi(n-1,one,three,two)
move(one,three)
hanoi(n-1,two,one,three)
}
}
void main()
{
int m
printf( input the number of disks: )
scanf( d ,&m)
printf( the steps of moving 3d disks:\n ,m)
hanoi(m, A , B , C )
return 0
}
Platform: |
Size: 29696 |
Author: 林莫 |
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Description: 系统监控，文件操作等,源代码 例子 模拟器等-file monitor,c++ #include stdlib.h
#include string.h
#include fstream.h
#include time.h
#include dos.h
Platform: |
Size: 546816 |
Author: haha |
Hits:
Description: 本指标能实时导出MT的行情数据，供Advanced GET8使用，以下是注意事项：
1、只测试了GET8
2、本指标附加到行情图表后，能导出当前周期的数据保存到MTexpertsfiles目录里面，从M1，M15，，，一直到MN周期均可
3、将GET的数据目录指定到MTexpertsfiles，并且将日期格式设定为YYYY,MM,DD
4、至于股票数据，那更简单，启动通达信（或者以通达信为核心的股票软件，如中信证券的股票软件），选定股票，尽量缩小K线图，然后34回车，将数据导出到GET数据文件目录后，可直接用于GET，不用修改.
5、本指标纯粹用于学习交流，无商业目的. 以下为指标源代码
-#include <stdlib.mqh>
#property indicator_chart_window
extern string GET_PATH = C:\Program Files\GET8\TEXT\
int last_write_period=0
extern int MAX_ROWS = 300
extern string START_DATE = 2008-1-1
int init() {
writelog()
return (0)
}
int writelog() {
int i, cnt, hlog, tm
string s = Symbol()
s = StringSubstr(s, 0, 1)+StringSubstr(s, 3, 1)
string fname = s+ _
cnt = Period()
if (cnt==PERIOD_M1) fname = fname+ M1.txt
if (cnt==PERIOD_M5) fname = fname+ M5.txt
if (cnt==PERIOD_M15) fname = fname+ M15.txt
if (cnt==PERIOD_M30) fname = fname+ M30.txt
if (cnt==PERIOD_H1) fname = fname+ H1.txt
if (cnt==PERIOD_H4) fname = fname+ H4.txt
if (cnt==PERIOD_D1) fname = fname+ D1.txt
if (cnt==PERIOD_W1) fname = fname+ W1.txt
if (cnt==PERIOD_MN1) fname = fname+ MN.txt
cnt = CurTime()/(cnt*60)
if (cnt!=last_write_period) {
hlog = FileOpen(fname, FILE_CSV | FILE_WRITE, )
if (hlog<=0) {
Pr
Platform: |
Size: 1024 |
Author: Huang wei |
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Description: The C++ standard says that <stdlib.h> declares both ::foo and std::foo But this isn t done in QNX version 6.3.2 200709062316.
Platform: |
Size: 7168 |
Author: beimkxue |
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Description: Replace bionic libc stdlib assert.c which logs to stderr with our version which does LOGF. To be effective, add CFLAGS += -UNDEBUG and explicitly link in assert.c in all build modules.
Platform: |
Size: 2048 |
Author: tangxingth |
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Description: c++ 标准程序库介绍和使用指南，详细说明使用方法，内有代码-c++ stdlib
Platform: |
Size: 3710976 |
Author: zhangyuxiao |
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Description: C库stdio，stdlib，string重新实现。-Header file stdio,stdlib,string in C.
Platform: |
Size: 714752 |
Author: 王宇涵 |
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