Welcome![Sign In][Sign Up]
Location:
Search - xc

Search list

[Communication-Mobilexc-4.3.2.tar.gz

Description: 支持X/YModem和cis_b+协议的串口通讯程序
Platform: | Size: 162098 | Author: | Hits:

[TreeViewmfcfqa

Description: treeview控件 $c6 dimension xc(3),uc(3),fx1(3),fx2(3),fx3(3),fx4(3) $c6 dimension fx13(3),fx16(3),fx18(3),fx27(3),fx38(3),fx57(3)-treeview controls $ tangible and intangible cultural heritage dimension xc (3), uc (3), FX1 (3), accordance (3), fx3 (3), fx4 (3) $ tangible and intangible cultural heritage dimension fx13 (3), fx16 (3), fx18 (3), fx27 (3), fx38 (3), fx57 (3)
Platform: | Size: 214800 | Author: 恢复 | Hits:

[Other resourcegeng13

Description: 用matlab仿真的xc = [1 1 1 1 1 1 1 1 1 1] 的fft时序幅频图形-simulation using Matlab xc = [1 1 1 1 1 1 1 1 1 1] fft timing frequency graphics
Platform: | Size: 845 | Author: tin_liu | Hits:

[Otherjsjqgbs

Description: 某幼儿园按如下方法依次给A,B,C,D,E五个小孩发糖果。将全部糖果的一半再加二分之一块糖果发给第一个小孩;将剩下糖果的三分之一再加三分之一块糖果发给第二个小孩;将剩下糖果的四分之一再加四分之一块糖果发给第三个小孩;将剩下糖果的五分之一再加五分之一块糖果发给第四个小孩;将最后剩下的11块糖果发给第五个小孩。每个小孩得到的糖果数均为整数。试确定原来共有多少块糖果?每个小孩各得到多少块糖果? 要求结果的输出格式为 sum=糖果总数 xa=A得到的糖果数 xb=B得到的糖果数 xc=C得到的糖果数 xd=D得到的糖果数 xe=E得到的糖果数 -a kindergarten followed by the following method to the A, B, C, D, E five children made candy. Candy will be half plus half of the candy to the first block of a child; of the remaining one-third of the candy with candy third block to the second child; candy will be left with the fourth quarter to the third block candy child; candy will be left with the fifth block fifth candy to the fourth child; the last remaining 11 candy to the fifth child. Each child received a candy few are integral. The original trial to determine the total number of pieces of candy? Each of the children received how many pieces of candy? The results of the request output format for the total sum = candy xa = A number of the candy xb = B the candy few xc C = the number of candy xd = D The candy few xe E = the number
Platform: | Size: 1148 | Author: dear | Hits:

[Other resourcemoniyunxing

Description: 恒日PLC编程软件具有非常完善的模拟运行功能,该功能能够完全反映梯形图程序下载到控制器中的实际运行结果。 XC变成软件的模拟运行窗口含有48个模拟开关量输入点,48个开关量模拟输出点,两个7段LED数码显示模块。 -PLC programming software is a very sound operation of the simulation function, The function can fully reflect Ladder downloaded to the controller of actual operating results. XC into simulation software running window containing 48 Analog Switches input, 48 Switch Analog Output, two seven-segment LED digital display module.
Platform: | Size: 131368 | Author: xwq1211 | Hits:

[Other(XC-Talk

Description: this is a telephone sofe
Platform: | Size: 3314270 | Author: f | Hits:

[Other resourcejisuanjituxing

Description: 根据多边形区域的填充原理可以推广到圆域的填充,由于圆的特殊属性,即可根据任何欲填充的像素点与圆心的距离是否大于或小于半径来判断是否在圆内或圆外,具体实现程序如下; 利用中点画圆算法实现边界程序: void CArea_FillData::MidpointCircle(int xc, int yc, int r, int color) {//画八分之一的圆 int x,y,d x=0 y=r d=1-r WholeCircle(xc,yc,x,y,color) while(x<y) -According to the regional polygon filling principle can be extended to the domain filled round, a round of special attributes, can be filled under any wishes to the central pixel and the distance is greater than or less than the radius to determine whether the circle or round, realize the procedure is as follows; Midpoint Circle Algorithm border procedures : void CArea_FillData : : MidpointCircle (int xc. yc int, int r, int color) (/ / painting of the eighth round int x, y, d x = 0 y = r d = 1-r WholeCircle (xc, yc, x, y, color) while (x
Platform: | Size: 81758 | Author: 周林 | Hits:

[Other resourceexaples

Description: 一些数据库的实例。共12章。如第八章: 第8章数据库环境的建立 1. 用MISDBA用户登录MISDB数据库。 2. 在ISQL中,输入第8章提供的SQL语句;或者根据表8-1至表8-4在SQL Explorer中自行创建数据表。 3. 根据表8-5至表8-7设置初始数据,另外需要在PERSON数据表中设置一个具有培训管理系统管理权限的用户(ID=’PXC’,PASSWD=’PASSWORD’,AUTHORITY=’6’,STATE=’F’)和用于外派培训的用户(ID=’PXCOUT’,NAME=’外派培训’)。 4. 修改Admin源程序中的数据库连接属性,并且重新编译training.exe。 5. 修改Client源程序中数据库连接属性,并且重新生成html文件和cab文件,然后将这两个文件拷贝到web服务器指定目录中。-some examples of the database. A total of 12 chapters. If the eighth chapter : Chapter 8 database to establish an environment. User login with MISDBA MISDB database. 2. In ISQL, the importation of Chapter 8 of SQL; Or, according to Table to Table 8 -1 8-4 in SQL Explorer to create data sheets. 3. According to Table 8-5 8-7 to set up tables initial data, Another need PERSON data tables set up with a training management system for the management competence of the users (ID = 'P XC ', PASSWD =' PASSWORD 'AUTHORITY ='6', STATE = 'F') for assignment and training of users (ID = 'PXCOUT' NAME = 'assignment training'). 4. Admin change the source of database connection attribute, and recompile training.exe. 5. Client amend the source database connecti
Platform: | Size: 2540594 | Author: bansom | Hits:

[Delphi VCLXJPrint

Description: excel import excel importe xcel importexcel import-excel import excel importe xc el importexcel import
Platform: | Size: 417806 | Author: aaa | Hits:

[Other resourceBastile

Description: XC的儿子小XC最喜欢玩的游戏用积木垒漂亮的城堡。城堡是用一些立方体的积木垒成的,城堡的每一层是一块积木。小XC是一个比他爸爸XC还聪明的孩子,他发现垒城堡的时候,如果下面的积木比上面的积木大,那么城堡便不容易倒。所以他在垒城堡的时候总是遵循这样的规则。小XC想把自己垒的城堡送给幼儿园里漂亮的女孩子们,这样可以增加他的好感度。为了公平起见,他决定把送给每个女孩子一样高的城堡,这样可以避免女孩子们为了获得更漂亮的城堡而引起争执。可是他发现自己在垒城堡的时候并没有预先考虑到这一点。所以他现在要改造城堡。由于他没有多余的积木了,他灵机一动,想出了一个巧妙的改造方案。他决定从每一个城堡中挪去一些积木,使得最终每座城堡都一样高。为了使他的城堡更雄伟,他觉得应该使最后的城堡都尽可能的高。任务:请你帮助小XC编一个程序,根据他垒的所有城堡的信息,决定应该移去哪些积木才能获得最佳的效果。 ACM 题目 -XC XC Jr., the son most like playing with building blocks, softball games beautiful castle. Castle is using some of the cube made up of building blocks, each level of the castle is a building block. XC is a smaller than his father XC also smart children, he found the time barrier castle, If the following modular building blocks than the above, then it is not easy to Castle reversing. So his base of the castle always follow such rules. XC want to make their small base of the castle gave kindergarten beautiful girls, this would increase the goodwill of his degree. For the sake of fairness, he decided to give each girl a high castle, It takes the girls to be more beautiful castle and the management. But he found himself in the barrier Castle did not advance to this point. So he is now to tran
Platform: | Size: 809 | Author: shao | Hits:

[Communicationfft_add

Description: 产生一512点的随机序列下Xe(n),并用Xc(n) 和Xe(n) 作线性卷积,观察卷积前后Xe(n) 频谱的变化。要求将Xe(n)分成8段,采用重叠相加法。
Platform: | Size: 43098 | Author: 万宁宁 | Hits:

[Communicationfft_stay

Description: 产生一512点的随机序列下Xe(n),并用Xc(n) 和Xe(n) 作线性卷积,观察卷积前后Xe(n) 频谱的变化。要求将Xe(n)分成8段,采用重叠保留法。
Platform: | Size: 36299 | Author: 万宁宁 | Hits:

[Process-Threadxc

Description: 自己写的一段VC线程案例,做教材很好的!
Platform: | Size: 992445 | Author: pusecjj | Hits:

[WEB Codexc

Description: 中国NJ娱乐DJ网站宣传系统 v0.1 后台地址:admin.asp 后台管理帐号密码:admin
Platform: | Size: 141388 | Author: 郑小舟 | Hits:

[Other图形学直线的生成算法

Description: 圆心在原点,半径为R的第一个4分圆的Bresenham画圆算法程序,将该算法程序推广到任一四分圆,从而形成一般的Bresenham画圆算法。并利用Bresenham画圆算法画出一个圆心在点(xc,yc), 半径为R, 圆周颜色为color的圆-Center in the basics of radius R for the first four hours round the Bresenham algorithm Circle procedures, procedures for the promotion of this algorithm, arrived on January 4 pm yen, thus forming a general Circle Bresenham algorithm. Circle and the use of Bresenham algorithm to identify a point in the center of a circle (xc, yc), the radius R, Circle color color circle
Platform: | Size: 878 | Author: 成龙 | Hits:

[Communication-Mobilexc-4.3.2.tar

Description: 支持X/YModem和cis_b+协议的串口通讯程序 -Serial communication supports X/YModem and cis_b+ protocol
Platform: | Size: 161792 | Author: 站长 | Hits:

[SCMXC-511

Description: XC-51实验板_4位数码管计数器的内容。-XC-51 experimental board _4-bit digital counter
Platform: | Size: 12288 | Author: 周星驰 | Hits:

[SCMXC-512

Description: XC-51实验板_5110液晶+1302,可以理解5110的特点-XC-51 experimental board _5110 LCD+1302,,, understandable 5110 Features
Platform: | Size: 43008 | Author: 周星驰 | Hits:

[SCMXC-513

Description: XC-51实验板_5110液晶显示,知道怎么显示。-XC-51 experimental board, _5110 LCD, know how to display.
Platform: | Size: 48128 | Author: 周星驰 | Hits:

[OS programXC-USER

Description: XC 系列PLC 的基本单元具备多个子系列产品线,可扩展性强,多种组合可自由选择 -The basic unit of XC series PLC has a plurality of sub series product line, strong expansibility, various combinations of free choice
Platform: | Size: 1557504 | Author: jinjin | Hits:
« 12 3 4 5 6 7 8 »

CodeBus www.codebus.net