Description: Mathematical two race question: if two people racing 25 meters in length, A B the first 10 m A speed of 5 meters per second, the speed of B is twice that of A' s. In this way, because the A in front of the B, B over he will come by the position, before the A and B to 10 meters, A to 15 meters. B to 15 m, 17.5 m. B to A takes time. This time A to B in front. So it can never catch up. But. Using mathematical methods. A :25-10 = 5t A 3 seconds. B: 25 = 10t B only 2.5 seconds. Able to catch up.
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数学计算-无限小数
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