problem with M-1, N 0 is the order (high-efficiency version) with a few : c (m n, n) of n 0, m one, I think is this : each can be arranged IPP : 0 whole, a whole, the sub- problems out of the long established : r, s, t.- is the question of (n, m) = (n-r, m-s), where 0

Filename	Size	Update
排列问题
........\c(n	k).txt
........\M个1	N个0的排列(DFS版).txt
........\M个1	N个0的排列(高效率版).txt.txt
........\排列.txt
........\无相同元素 提交版.txt

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