Given task sequence J1J2 ... Jn, the assumption that only one service processor for these operations. Ji each task given a time limit and the corresponding di profits Pi. Only the stipulated time-frame to complete operations, profit would have been Pi. By designing a suitable algorithm for the selection and arrangement task subset Ji, makes J each operation can be in their respective time-frame for completion, and so was the largest sum of profits ΣPi. Order d = max (di) 1 ≤ i ≤ n, b = min (n, d) the highest profits of any sequence can be completed in the number of operations will not be greater than b.

Job.cpp

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