Description: void main() (E3BGX[
{
const int N=15420 //N=sr*time M./3@A
const int n=(int)sr*0.04,yanshi=(int)sr*0.2,back=(int)sr*0.04 //n=sr*0.04,yanshi=sr*0.2?,back=sr*0.04 PDl=!>u
const int M=N //负斜率找寻阵维数M=N-n "q"$bY9<3
const int R=200 UUFW =m`
int Q=(int)sr*1.2 T/- VpU #
const int RR1=1.2*sr,RR4=(int)sr*1.6 //RR1=1.2*sr,RR2=1.5*sr,RR3=0.5*sr,RR4=1.6*sr tU {1.&D
float data[N][13],time,I,II,III,avr,avl,avf,v1,v2,v3,v4,v5,v6 { ft(y.#C=
const int F=2 ^qH|x>Z
int i=0
To Search:
- [OSTS] - This procedure demonstrated through a se
- [iic_time] - The sampling to the A/D data processing,
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Rbo.txt
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