Title:
to-determine-a-leap-year
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Description: 3, the title: Enter 1842--2006 decimal number between the years. Requirements: (1) requires the existence of a message, and its own line. (2) to determine whether it is a leap year, if the output " yes" , otherwise output " no" . (Hint: first addition to the 100, except if divisible by the then 400 is a leap year if the indivisible (If you just use the 100 is not divisible by 4 except, divisible was a leap year.) (3) in the binary output xxxx August 29 from August 29, 1842 the number of months. (4) decimal output xxxx years from August 29, August 29, 1842 the number of days.
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案例1判断闰年程序\Ifleap.ASM
.................\IFLEAP.EXE
.................\说明.txt
案例1判断闰年程序
