Description: Find a wire bent into a circle, so that the diameter is precisely equal to the distance d between the parallel lines. Imagine, for this circle, no matter how dropped and parallel lines have two points of intersection. Therefore, if the circle dropped the number of n times, then the total number of the intersection point of intersection must be 2n. Now imagine the circle straightened into a long πd the wire. Obviously, this wire dropped the case of parallel lines intersect than circle complex, there may be four intersection of the three intersection 2 intersection, an intersection, and even do not intersect. As the circle and the length of the straight line with πd, according to the principle of equality of opportunity, when they throw more frequently, and equal, the total number of the intersection of two parallel lines group is also expected the same. This means that when the wire length πd dropped n times the total number of the intersection with the parallel lines intersect should b
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布冯投针\Debug\vc60.idb
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........\.....\布冯投针.exe
........\.....\布冯投针.ilk
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........\布冯投针.cpp
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........\布冯投针.ncb
........\布冯投针.opt
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布冯投针
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