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[TreeView] 2_s DL : 0: 汇编语言编写的小程序，不知道有没有用，也不知道在网站上有没有z，看看吧！-assembly language prepared by the small program was not aware of no use, do not know the web site, there is no z, let's see it!
Date : 2008-10-13 Size : 2.41kb User : jiao
[TreeView] 2_s DL : 0: 汇编语言编写的小程序，不知道有没有用，也不知道在网站上有没有z，看看吧！-assembly language prepared by the small program was not aware of no use, do not know the web site, there is no z, let's see it!
Date : 2025-07-09 Size : 2kb User : jiao
[assembly language] intel-assembly-program DL : 0: Intel汇编语言程序设计第五版的随书源代码，看这本书不可少的。-Intel Assembly Language Programming With the fifth edition of the book source code, look at this book indispensable.
Date : 2025-07-09 Size : 5.57mb User : 周龙亭
[Internet-Network] uwow_0_0_01 DL : 0: C编译器产生的可显示机器码/汇编代码文件,其中附有源C v: v: @8 g: X& z代码作为注释 : z! [3 \) O&...UWOW Grave Composer音乐模块(MOD)文件 + Q* T) \ z) R f$ a: H, iWP WordPerfect文档 H! t7 D2 |... -C compiler generated displays binary/assembly code document attached to the source of C v: v: @ 8 g: X
Date : 2025-07-09 Size : 541kb User : 许庭洲
[assembly language] huibianshiyan1 DL : 0: 汇编语言程序上机过程DEBUG程序的使用 1.编制程序计算Z=X+Y，其中X、Y、Z均为字型无符号数。2．将数据区中的100个‘A’字符组成的字符串传送到附加段中。-Assembly language program on the machine the process of using one of the DEBUG program. Programming calculation Z = X+ Y, which X, Y, Z are the number of fonts unsigned. 2. Data area of 100
Date : 2025-07-09 Size : 38kb User : 卢雪
[assembly language] z DL : 0: IBM-PC汇编语言程序设计实现字母Z的输出，简单的“*”字符组成的字母Z-IBM-PC assembly language programming to achieve the output of the letter Z, the simple * characters comprising letters Z
Date : 2025-07-09 Size : 7kb User : 周爽
[assembly language] assembly DL : 0: 里面有六个汇编程序，分别为：实验一：在屏幕上显示数字串“0123456789”，每串一行，共显示10行。实验二：从键盘上输入一含有多个随机出现的空格的字符串，滤出其中所有空格后，输出显示不含空格的该字符串。实验三：从键盘输入一个字母，然后输出它的前一个字母，和后一个字母。这里必须考虑大小写字母，还要考虑A、a只会输出它后面那个字母，Z、z只会输出它前面那个字母。实验四：显示小于1000的素数（用十进制数显示它们）。实验五：分别统计内存中从0f00H开始的1024个字型数据中正数.负数及0的个数，并用十进制的形式输出其结果。实验六：从键盘上输入一个多位数的整数n，用递归法求“1+2+3+.....+n”的和运算，并用十进制的形式输出其结果。-There were six assembler, for: Experiments on the screen: "0123456789 numeric string," each string line, show 10. Lab 2: from the keyboard input a contains multiple random space, filter out of the string, after all Spaces that do not contain Spaces of the output of the string. Lab 3: a letter from the keyboard input and output, and it s a letter, and before a letter. There must be considered letters, consider A, A will only output the letters, behind it will only output the Z Z, its front that letter. Experiments showed less than 1000 4: (decimal number of primes display them). Five: the statistics experiments in memory of 0f00H from start to 1,024 fonts data in the negative and positive. 0, and the number of decimal form output. Experiments on the keyboard input from 6: an integer numerals in positional notation, using a recursive method n o "1+ 2+ 3+...+ n" and the operation, and the results of the decimal form output.
Date : 2025-07-09 Size : 3kb User : superww
[assembly language] jisuan DL : 0: 汇编语言顺序程序设计计算(x+(y*z-100))/w-The order of assembly language programming computing (x+ (y* z-100))/w
Date : 2025-07-09 Size : 1kb User : 李昕
[assembly language] Game DL : 0: 记忆力的小游戏，汇编语言。游戏开始，提示“Please show seeds: (press 0 – 2)”，按键0~2 提供三种方案供选择。每种方案在不同的位置显示4个“种子”，种子的形状自定，颜色区别于背景色。按“E”或“e”让“种子”消失。“W”、“A”、“S”和“Z”键分别控制色块向上、向左、向右和向下移动。如果经过原定的“种子”处，种子现形。实现了光标移动，边界设定，判断等功能。-Memory games, assembly language. Start of the game, prompted " Please show seeds: (press 0- 2)" , 0 to 2 key three options available for selection. Program in a different location each show four " seed" , seed shape custom color different from the background color. Press " E" or " e" for " seed" disappear. " W" , " A" , " S" and " Z" key to control the color blocks are up, left, right and moving down. If you read the original " seed" Department, seed borrow this. Realized the cursor, margin settings, check other functions.
Date : 2025-07-09 Size : 2kb User : Leon
[SCM] Assembly DL : 0: kniga za asembler PCI Enumerate Tool by WuJun@amoi.com.cn copy Irvine16.inc into c:\masm611\include copy Irvine16.lib into c:\masm611\lib compile command: ML /nologo -c -Fl pci.asm link command: LINK /nologo pci,,NUL,Irvine16 History 2004-11-29 v0.1 prime version to show pcicfg as bus dev func venid devid class in hex code 2004-12-1 v0.1 added function to show class and subclass string instead of hex code 2004-12-2 v0.2 added pci struct,improve the data struct,make program to has more readablilty -kniga za asembler PCI Enumerate Tool by WuJun@amoi.com.cn copy Irvine16.inc into c:\masm611\include copy Irvine16.lib into c:\masm611\lib compile command: ML /nologo -c -Fl pci.asm link command: LINK /nologo pci,,NUL,Irvine16 History 2004-11-29 v0.1 prime version to show pcicfg as bus dev func venid devid class in hex code 2004-12-1 v0.1 added function to show class and subclass string instead of hex code 2004-12-2 v0.2 added pci struct,improve the data struct,make program to has more readablilty
Date : 2025-07-09 Size : 881kb User : 123
[assembly language] spd DL : 1: DOS下读取内存SPD信息，C语言与汇编代码混合-Information to read memory SPD DOS, C language and assembly code mixed
Date : 2025-07-09 Size : 2kb User : 张峻海
[VHDL-FPGA-Verilog] MIPS1CYCLE DL : 0: MIPS single-cycle processor design in verilog.Instruction memory to the design and initialise it with your assembly code-a. Load the data stored in the X and Y locations of the data memory into the X and Y registers. b. Add the X and Y registers and store the result in the Z register. c. Store the data from the Z register into the Z memory location. d. Load the data in the Z memory location into the T register.
Date : 2025-07-09 Size : 2kb User : chenghao wei
[assembly language] Char-0-9-a-z-ASM DL : 0: assembly Char 0-9 a-z ASM
Date : 2025-07-09 Size : 24kb User : mohsen
[JSP/Java] SCA_AssemblyModel_V100c_pub DL : 0: 该文档描述SCA装配模型，其覆盖如下内容： z 服务的装配模型，既适合紧耦合也适合松散耦合。 z 应用基础设施功能于服务与服务交互模型，包括安全性和事务性-This document describes the SCA assembly model, which covers the following: z service assembly model, both for tight coupling is also suitable for loosely coupled. z application infrastructure capabilities in the service interact with the service model, including security and transactional
Date : 2025-07-09 Size : 645kb User : 刘落
[assembly language] shz22 DL : 0: 通过利用汇编语言中的循环，堆栈，延时等技巧以及子程序，BIOS和DOS的调用，由用户选择，实现在屏幕中央输出A到Z或者显示黑客帝国式的屏保。-Through the use of the cycle, stack, and delay in the assembly language skills and the subroutine, the BIOS and DOS calls, selected by the user to achieve in the center of the screen output A to Z, or display on the Matrix-style screensaver.
Date : 2025-07-09 Size : 1kb User : permanent
[assembly language] 4.11 DL : 0: 编写一个带符号数四则运算的汇编语言程序，完成（Z-（X*Y+200）/20的运算，商送V单元，余数送W单元。-Write a signed four arithmetic assembly language program to complete the computation of (Z-(X* Y+200)/20 V unit, suppliers to send the remainder sent W unit.
Date : 2025-07-09 Size : 1kb User : loginid
[assembly language] 5 DL : 0: 多模块程序设计及多语言混合编程。要求： ⑴ 编写一个求Nm的汇编语言子程序（子模块）。 ⑵ 编写一个计算Z=(X2+Y4)的汇编语言主模块，其中X2、Y4通过调用⑴中的Nm实现，并显示当X=5，Y=6时的结果。 -Multi-module programming and multi-language programming mix. Requirements: ⑴ write a request Nm assembly language subroutines (sub-modules). ⑵ write a calculated Z = (X2+Y4) main module assembly language, where X2, Y4 by calling ⑴ in Nm achieved, and shows when X = 5, Y = 6 for the results.
Date : 2025-07-09 Size : 665kb User :