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Description: Chipcon CC2420 reference design w/PA board rev B
CC2420_w_PA_PCB.ZIP
FABRICATION.PHO - fabrication drawing
COPPER1.PHO - copper layer #1 (top side)
COPPER2.PHO - copper layer #2 (inner ground plane)
COPPER3.PHO - copper layer #3 (inner power plane)
COPPER4.PHO - copper layer #4 (bottom side)
TOPMASK.PHO - top side solder mask
BOTTOMMASK.PHO - bottom side solder mask
NCDRILL.DRL - drill data file
NCDRILL.LST - drill list
NCDRILL.REP - drill report-Chipcon CC2420 reference design w/PA board rev B CC2420_w_PA_PCB.ZIP FABRICATION.PHO-fabrication drawing COPPER1.PHO-copper layer# 1 (top side) COPPER2.PHO-copper layer# 2 (inner ground plane ) COPPER3.PHO-copper layer# 3 (inner power plane) COPPER4.PHO-copper layer# 4 (bottom side) TOPMASK.PHO-top side solder mask BOTTOMMASK.PHO-bottom side solder mask NCDRILL.DRL-drill data file NCDRILL . LST-list NCDRILL.REP drill-drill report
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Size: 573440 |
Author: 宝嘉 |
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Description: 为了 设 计 好吻enSSL组件结构，本论文详细剖析了OpenSSL的基本结构和
程序流程，深入分析其存在不足的原因。文中也对COM组件技术和ATL库进
行了详细论述和仔细分析，得出了COM 组件技术的特点和优势所在。在上述
两点的基础上，说明了采用COM组件技术封装OpenSSL的原因和带来的好处，
并提出了映射和面向对象两种具体的封装思想，充分考虑到了传统用户和习惯
于面向对象方法用户的需求。在封装思想的指导下，课题采用VisualSt udio2 003
和其附带的ATL 7.0活动模板库作为开发工具和环境.因为OpenSSL和ATL本
身的特性，封装过程遇到了一些问题。通过对问题本质的详细分析，本文提出
了有效的解决方案，完成了封装工作.
封装 之 后 的OpenSSL有效地克服了原来面向过程、使用不方便、升级维护
困难等缺点。同时，原来具有的强大功能也得以保留。通过对封装前后OpenSSL
的使用方法对比，证明了OpenSSL的组件化能有效改善其结构、符合软件发展
潮流。-To d e sig ng oods tructureo fO penSSLc omponent,th eth esisan alyzesO penSSL s
structure and programming procedure in detail, and then finds the reasons about
defects. The thesis expatiates on COM technology and ATL library, and discusses
their advantages. Based on the two points, the thesis discusses encapsulation s
advantages and reasons. To consider traditional users and other users who are
accustomedto 。场ect-orientm ethod,tw ok indso fth inkinga rep resented.T hefi rstis
mapping method and the second is object-orient method. Visual Studio 2003 and
ATL7 .0l ibrary aret hed evelopmente nvironmenta ndt ool.B ecauseo fO penSSLa nd
ATUssp ecialty,th erear es omep roblemsp resentw hilee ncapsulatingO penSSL.T he
thesis proposes a solution for these problems, and implements encapsulation
sucessfully.
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Size: 5069824 |
Author: 冯俊 |
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Description: 实体的B-rep表示模型是一非常复杂的模型，要求能够表达出多面体各几何元素之间完整的几何和拓扑关系，并且允许对这种几何和拓扑关系进行修改.在B-rep表示中，体、面、边和顶点是最基本的几何元素，在实体的拼合、显示、分析计算或人机交互过程中-The B-rep solid representation model is a very complex model, requires the ability to express the polyhedron between the geometric elements of the complete geometry and topology, and allows for such changes the relationship between geometry and topology. In B-rep representation, body, face, edge and vertex is the most basic geometric elements, in the merging entities, display, analysis and calculation, or the process of human-computer interaction
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Size: 63488 |
Author: gisok |
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Description: Description
很多学校流行一种比较的习惯。老师们很喜欢询问，从某某到某某当中，分数最高的是多少。
这让很多学生很反感。
不管你喜不喜欢，现在需要你做的是，就是按照老师的要求，写一个程序，模拟老师的询问。当然，老师有时候需要更新某位同学的成绩。
Input
本题目包含多组测试，请处理到文件结束。
在每个测试的第一行，有两个正整数 N 和 M ( 0<N<=200000,0<M<5000 )，分别代表学生的数目和操作的数目。
学生ID编号分别从1编到N。
第二行包含N个整数，代表这N个学生的初始成绩，其中第i个数代表ID为i的学生的成绩。
接下来有M行。每一行有一个字符 C (只取 Q 或 U ) ，和两个正整数A，B。
当C为 Q 的时候，表示这是一条询问操作，它询问ID从A到B(包括A,B)的学生当中，成绩最高的是多少。
当C为 U 的时候，表示这是一条更新操作，要求把ID为A的学生的成绩更改为B。
Output
对于每一次询问操作，在一行里面输出最高成绩。
Sample Input
5 6
1 2 3 4 5
Q 1 5
U 3 6
Q 3 4
Q 4 5
U 2 9
Q 1 5
Sample Output
5
6
5
9
-Description
Many schools have a relatively popular habit. Teachers are likely to ask, to certain of them from certain, with the highest score is.
This makes a lot of students are very offensive.
Whether you like it or not, you now need to do is, that in accordance with the requirements of the teacher to write a program to simulate the teacher asked. Of course, teachers sometimes need to update certain students achievements.
Input
This topic contains several test cases, handle to the end of the file.
In the first line of each test, there are two positive integers N and M (0 <N <= 200000,0 <M <5000), respectively represent the number of students and number of operations.
Student ID numbers were compiled from one to N.
The second line contains N integers, representing the N initial student achievement, the first of which is i i rep ID number of student achievement.
Then there are M lines. Each line has a character C (just take the Q or U ), and two positi
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Size: 1024 |
Author: liuyudan |
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