Description: 用C语言编写的计算器,具有运算符优先级,采用堆栈实现。-C language prepared by the calculator, with priority Operators using stack to achieve. Platform: |
Size: 49152 |
Author:新新 |
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Description: 用栈实现算术表达式
一个小小的科学计算器,根据用户输入的表达式计算出结果-Arithmetic expressions using stacks to achieve a small scientific calculator, in accordance with user input to calculate the results of the expression Platform: |
Size: 1024 |
Author:jwjshitiancai |
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Description: C++ 用栈实现的命令符计算器,进行前缀表达式的计算-C++ Used stack order to achieve Fu calculator for the calculation of expression prefix Platform: |
Size: 284672 |
Author:罗媛 |
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Description: 对任意的一个算术表达式进行加减乘除运算,表
达式有误会显示提示。主要用的知识 : 栈,字符串处理等等
-Of an arbitrary arithmetic expressions Math & Computing, shows a misunderstanding has prompted expressions. The main use of knowledge: the stack, the string handle and so on Platform: |
Size: 3072 |
Author:小瑶 |
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Description: 这是一款非常实用的计算器,我认为其实用程度远远胜过Windows系统提供的计算器.主要特色是支持多项式运算,即可以一次输入整个多项式,并能够识别运算的优先级(利用堆栈实现)-This is a very practical calculators, in fact, in my opinion much better than using Windows system calculator. Main features are support for polynomial computing, you can enter an entire polynomial, and be able to identify the priority operator class (using the stack implementation) Platform: |
Size: 68608 |
Author:陈 波 |
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Description: 完成堆栈抽象数据类型的顺序、链式表示与实现。实现功能:数值转换,计算器(表达式求值),迷宫求解,判断某个字符串是否是回文
-Completion of the stack abstract data type of the order, said that with the realization of the chain. The realization of functions: numerical conversion calculator (expression evaluation), to solve the maze to determine whether a string is a palindrome Platform: |
Size: 32768 |
Author:韩非 |
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Description: 界面的表达式计算器,用对话框和栈实现,可以判断表达式的是否正确输入-Expression calculator interface with dialog boxes and stack to achieve, you can determine whether the correct input expression Platform: |
Size: 64512 |
Author:chenzhengjun |
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Description: 此程序用堆栈来实现多项式计算,用c++来实现-This program uses the stack to achieve polynomial calculation, using c++ to achieve the Platform: |
Size: 1556480 |
Author:王磊 |
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Description: 运用栈判断括号是否成对来实现的基本计算器-The use of the stack to determine whether the pairs of brackets to achieve the basic calculator Platform: |
Size: 6144 |
Author:guo |
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Description: 用C++编写带括号的算术表达式求值,利用堆栈实现,采用算符优先数算法。-Written with C++ arithmetic expression in parentheses is evaluated using the stack implementation, the use of operator priority number algorithm. Platform: |
Size: 440320 |
Author:JJWM |
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Description: 使用堆栈来解决计算器问题,非常详细的讲解了堆栈的使用方式。-Use the calculator stack to solve the problem, very detailed explanation of the stack is used. Platform: |
Size: 84992 |
Author:Tian |
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Description: 利用stack开发的简单计算软件,能进行各种简单运算(The simple computing software developed by stack can carry out a variety of simple operations) Platform: |
Size: 935936 |
Author:天南
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