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Description: 十个小孩围成一圈分糖果，老师分给第一个小孩10块，第二
个小孩2块，第三个小孩8块，第四个小孩22块，第五个小孩16块
，第六个小孩4块，第七个小孩10块，第八个小孩6块，第九个小
孩14块，第十个小孩20块。然后所有的小孩同时将手中的糖分一
半给右边的小孩；糖块数为奇数的人可向老师要一块。问经过这
样几次后大家手中的糖的块数一样多？每人各有多少块糖？-10 points .... candy children, teachers added to a child 10 and the second two children, the third child eight, the fourth child 22, the fifth child 16, a sixth four children, the seventh child 10, the eighth child six, nine children 14, 10, 20 child. Then all of the children to the hands of sugar to the right half of the children; Retrievers few odd people to be a teacher. Q After this we After several hands of the few pieces of sugar as much? The number of blocks each have sugar?
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Size: 1291 |
Author: 姚紫欣 |
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Description: 计算机图形处理的软件，candy算法是当今最很流行的一种算法。同学可以自己在源代码中学习到新的知识。-computer graphics software, candy algorithm is the most popular day of an algorithm. Students can in the source code to learn new knowledge.
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Size: 6889 |
Author: 何学洲 |
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Description: 某幼儿园按如下方法依次给A，B，C，D，E五个小孩发糖果。将全部糖果的一半再加二分之一块糖果发给第一个小孩；将剩下糖果的三分之一再加三分之一块糖果发给第二个小孩；将剩下糖果的四分之一再加四分之一块糖果发给第三个小孩；将剩下糖果的五分之一再加五分之一块糖果发给第四个小孩；将最后剩下的11块糖果发给第五个小孩。每个小孩得到的糖果数均为整数。试确定原来共有多少块糖果？每个小孩各得到多少块糖果？
要求结果的输出格式为
sum＝糖果总数
xa＝A得到的糖果数
xb＝B得到的糖果数
xc＝C得到的糖果数
xd＝D得到的糖果数
xe＝E得到的糖果数
-a kindergarten followed by the following method to the A, B, C, D, E five children made candy. Candy will be half plus half of the candy to the first block of a child; of the remaining one-third of the candy with candy third block to the second child; candy will be left with the fourth quarter to the third block candy child; candy will be left with the fifth block fifth candy to the fourth child; the last remaining 11 candy to the fifth child. Each child received a candy few are integral. The original trial to determine the total number of pieces of candy? Each of the children received how many pieces of candy? The results of the request output format for the total sum = candy xa = A number of the candy xb = B the candy few xc C = the number of candy xd = D The candy few xe E = the number
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Size: 1148 |
Author: dear |
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Description: 糖果水晶按钮,听名字就不错,是的,这个代码支持XP按钮,XP工具栏按钮,水晶和冰块(基于水晶)等风格,
所有按钮都支持Checked/Unchecked状态.代码仅用4个API函数,4种不同的样式,缺点是有点慢.-crystal candy buttons, listening to name Yes, yes, the button code to support XP, XP toolbar buttons, crystal and ice (based on the crystal) style, all the buttons are supported Checked / Unchecked state. only four code API function, four different styles and shortcomings is a bit slow.
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Size: 55397 |
Author: 郑为发 |
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Description: A lot of people asked me, \"So how do i put it all together?\"
I have taken some of the other tutorials and created this piece of eye candy.
It uses slightly modified versions of the Bouncing Ball and Water Ripple tutorials.-A lot of people asked me, "So how do i put it all together," I have taken some of the other tutorials and created this piece of eye candy. It uses slightly modified versions o f the Bouncing Ball and Water Ripple tutorials.
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Size: 112271 |
Author: 古洪 |
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Description: 计算机图形处理的软件，candy算法是当今最很流行的一种算法。同学可以自己在源代码中学习到新的知识。-computer graphics software, candy algorithm is the most popular day of an algorithm. Students can in the source code to learn new knowledge.
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Size: 6144 |
Author: 何学洲 |
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Description: Canny 方法使用两个阈值来分别检测强边缘和弱边缘,而且仅当强边缘和弱边缘相连时,弱边缘才会包含在输出中,因此,此方法不容易受噪声的干扰,能够检测到真正的弱边缘, 但由于检测阈值固定,当检测具有模糊边缘的图像时,很可能导致平滑掉部分边缘信息。
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Size: 4096 |
Author: sun |
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Description: 边缘提取，用的是一种比较新颖的算法，提取的效率比较高。-Edge extraction, using a relatively new algorithm, the efficiency of extraction is relatively high.
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Size: 4096 |
Author: 111111111 |
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Description: candy算子对于图像分割有着非常重要的作用，此程序正是candy算子的源码-candy for the image segmentation operator has a very important role in this process is the candy of the source operator
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Size: 1024 |
Author: 西宁 |
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Description: Let us design a control unit for a simple coin-operated candy machine. Candy costs 20 bath ,and the machine accept 5 bath and 10 bath. Change should be return if less than 5 bath is deposited. No more than 25 bath can be deposited on a single purchase therefore ,the maximum change is 5 bath.-Let us design a control unit for a simple coin-operated candy machine. Candy costs 20 bath ,and the machine accept 5 bath and 10 bath. Change should be return if less than 5 bath is deposited. No more than 25 bath can be deposited on a single purchase therefore ,the maximum change is 5 bath.
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Size: 1024 |
Author: adearong |
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Description: example of candy problem, solved in java using backtracking algorithm and keeping saved solutions
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Size: 3072 |
Author: ploper |
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Description: 一个简单的自动售货机控制器，投足25美分便发糖果，并且自动找零-A simple vending machine controller, 25 cents will be made every move she makes candy and give change automatically
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Size: 1024 |
Author: treeyellow |
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Description: 用Candy算子提取图像边缘，建立DIB类读取BMP文件，提取边缘并储存-Candy operator with image edge extraction
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Size: 22439936 |
Author: shen |
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Description: candy边缘检测，可用于集成电路版图的边缘检测-candy edge detection, edge detection can be used for integrated circuit layout
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Size: 318464 |
Author: 李玻玻 |
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Description: 本人自己编写的关于Candy边缘检测的matlab源代码，包含了多个程序，一个是加噪声的，还有不加噪的，非常适合初学者使用。-I have written about Candy edge detection matlab source code contains multiple programs, a plus noise, there are not adding noise, very suitable for beginners to use.
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Size: 1024 |
Author: rao |
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Description: candy算子 基于图像检索的candy边缘算法-To be or not to be,That is a good question.
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Size: 5120 |
Author: cube |
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Description: 糖果分配问题——2013百度之星-ARM-STM32竞赛算法题的递归实现-Candy allocation- 2013 Baidu Star-ARM-STM32 contest theme recursive algorithm
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Size: 5935104 |
Author: Tracy |
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Description: 经典糖果机问题 类的使用以及面向对象的实现-Achieve the classic problem of a class using candy machine and object-oriented
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Size: 1024 |
Author: 姜硕 |
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Description: 图像处理，边沿检测算法 candy，做神经网络算法的朋友可以参考-candy border check algorithm
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Size: 101376 |
Author: tan |
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Description: 应用candy算子进行灰度图像的识别，需要先把图像转为灰度图(Application of candy operator to gray image recognition)
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Size: 1024 |
Author: 乳酸钙 |
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