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Description: 算法的基本思路是：
定义结构体：struct PLACE{int x, int y}表示棋盘上的位置。
依题意，马每跳一步之后都可以从七个不同的方向选择下一步的跳马，当然，前提是跳的这一步在棋盘内且它前面的任何一步都没跳到这一格子上（限界），就可以认为这一步跳成功，否则跳马不成功。若跳马不成功，则找下一个方向尝试跳马，若七个方向都跳马不成功，则回溯。
-algorithm for the basic ideas : the structure definition : PLACE struct (int x, int y) expressed position on the chessboard. According to that intended, Ma every step dancing followed from 7 to choose a different direction next vault, of course, the premise is this step jump on the chessboard in front of it, within any step no jumping on the lattice (Bound), that could jump to success, or else vault unsuccessful. Vault if unsuccessful, to find a direction to vault, if the seven directions vault unsuccessful, then backtracking.
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Size: 47636 |
Author: 杨小娜 |
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Description: 用c＃实现动态点阵（x，y），数据来源不限。-with dynamic lattice (x, y), the open-source data.
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Size: 9722 |
Author: 苏大亮 |
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Description: 12*12点阵汉字库，做LCD汉字显示必备-Lattice Store, the Chinese character LCD display so essential
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Size: 112145 |
Author: 张文 |
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Description: 12*12点阵汉字库，做LCD汉字显示必备-Lattice Store, the Chinese character LCD display so essential
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Size: 111616 |
Author: |
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Description: 算法的基本思路是：
定义结构体：struct PLACE{int x, int y}表示棋盘上的位置。
依题意，马每跳一步之后都可以从七个不同的方向选择下一步的跳马，当然，前提是跳的这一步在棋盘内且它前面的任何一步都没跳到这一格子上（限界），就可以认为这一步跳成功，否则跳马不成功。若跳马不成功，则找下一个方向尝试跳马，若七个方向都跳马不成功，则回溯。
-algorithm for the basic ideas : the structure definition : PLACE struct (int x, int y) expressed position on the chessboard. According to that intended, Ma every step dancing followed from 7 to choose a different direction next vault, of course, the premise is this step jump on the chessboard in front of it, within any step no jumping on the lattice (Bound), that could jump to success, or else vault unsuccessful. Vault if unsuccessful, to find a direction to vault, if the seven directions vault unsuccessful, then backtracking.
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Size: 47104 |
Author: 杨小娜 |
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Description: 第一格子网源码
演示地址：http://www.diyige.com.cn
■超大100 x 100像素广告格子,广告更加无拘束！
■完全免费,无论大小网站,谁都可以申请获得！
■加入条件:在你站加本站Logo；每被点击,你在本站格子就排第一！
■每页3000个格子，25个页面共75000个格子，里面肯定有你的一个！
后台管理：http://你的网址/admin/index.asp
管理员用户名：admin
管理员密码：admin
如果后台密码出错，请复制admin的MD5加密代码：21232f297a57a5a743894a0e4a801fc3到密码区
版权说明：任何单位或者个人未经过本人同意不得用于出售，其他版权请参考中国版权法！谢谢！-The first lattice network source presentation addresses: http://www.diyige.com.cn ■ Large 100 x 100 pixel ads lattice, advertising more freely! ■ completely free, regardless of the size of site, anyone can apply for! ■ adding conditions: in your site stops Logo each is clicked, you are in the lattice site on the first row! ■ per page Lattice 3000, 25 pages total of 75,000 grid, which you certainly have a! Admin: http:// to your URL/admin/index.asp administrator username: admin admin password: admin password if the background error, please copy the MD5 encrypted admin code: 21232f297a57a5a743894a0e4a801fc3 to password District Copyright Note: No unit or individual has not been I agree should not be used for sale, other copyright please refer to the Chinese copyright law! Thanks!
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Size: 1165312 |
Author: jeremy |
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Description: 用c＃实现动态点阵（x，y），数据来源不限。-with dynamic lattice (x, y), the open-source data.
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Size: 38912 |
Author: 苏大亮 |
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Description: 16乘16点阵设计\点阵源程序及编译,
采用电路最简洁,需要,可以邮件联系-16 x 16 lattice design Lattice source and compiled using the most simple circuit, needs, can e-mail contact
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Size: 2048 |
Author: 极光 |
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Description: lattice xp2 系列开发板带源码，有需要的可依进行设计参考！-lattice xp2 Series development board with source code, need-based reference design!
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Size: 210944 |
Author: lee |
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Description: 在一个n*n个方格的国际象棋棋盘上，马（骑士）从任意指定方格出发，按照横1 步竖2 步，或横2 步竖1步的跳马规则，走遍棋盘的每一个格子，且每个格子只走1次。这样的跳马步骤称为1 个成功的骑士征途。例如，当n=5 时的1 个成功的骑士征途如下图所示。
1 2 3 4 5
1 25 14 1 8 19
2 4 9 18 13 2
3 15 24 3 20 7
4 10 5 22 17 12
5 23 16 11 6 21
算法设计：
对于给定的n和n*n方格的起始位置x和y。用分支限界法找出从指定的方格(x,y)出发的一条成功的骑士征途。
数据输入：
第一行有1 个正整数n (1≤n≤10)；第二行有2 个正整
数x 和y，表示骑士的起始位置为(x,y)。
结果输出:
如果不存在从(x,y)出发的成功的骑士征途则输出’No Solution!’。
输入：
5
1 3
输出
25 14 1 8 19
4 9 18 13 2
15 24 3 20 7
10 5 22 17 12
23 16 11 6 21-In an n* n squares on the chess board, horse (knight) starting from any given square, erected in accordance with step 1 step 2 horizontal, vertical or horizontal-step 1 step 2 vault rules, traveled to every board lattice, and each grid only take 1. This step is called a successful vault knights journey. For example, when n = 5 when a successful knight journey as shown below.
12345
125,141,819
24,918,132
315,243,207
4105221712
5231611621
Algorithm Design:
For a given n and n* n grid starting position of the x and y. Using branch and bound method to find out from the specified grid (x, y) starting a successful journey Knight.
Data entry:
The first line has a positive integer n (1 ≤ n ≤ 10) the second line has two positive integers
Number of x and y, said Cleveland s starting position (x, y).
The resulting output:
If not from the (x, y) the success of the Knights start the journey is the output No Solution! .
Input:
5
13
Export
25,141,819
4918132
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Size: 881664 |
Author: wakaka |
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Description: LED点阵显示屏作为一种新兴的显示器件,是由多个独立的LED发光二极管封装而成. LED点阵显示屏可以显示数字或符号, 通常用来显示时间、速度、系统状态等。文章给出了一种基于MCS-51单片机的16×16 点阵LED显示屏的设计方案。包括系统具体的硬件设计方案,软件流程图和部分汇编语言程序等方面。在负载范围内, 只需通过简单的级联就可以对显示屏进行扩展,是一种成本低廉的图文显示方案。-Destem as a new kind of display devices, is composed of multiple independent LED light emitting diode encapsulation and into. Destem can display Numbers, or symbols, usually used to display the time, speed, the system state, etc. The paper gives a method based on MCS- 51 SCM 16 x 16 lattice LED display design. Including system design scheme of concrete hardware and software flow chart and part assembly language programs, etc. In load range, just through the simple cascade can expand on screen, is a low-cost graphic display solutions.
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Size: 173056 |
Author: 何刚 |
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Description: 晶格动力学计算工具ph.x，完整代码，包含makefile-Lattice dynamics calculation tools ph.x, complete code, including the makefile
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Size: 367616 |
Author: 陈辉 |
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Description: 晶格动力学计算工具D3，完整代码，包含makefile-Lattice dynamics calculation tools ph.x, complete code, including the makefile
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Size: 83968 |
Author: 陈辉 |
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Description: 方腔流的并行程序。非平衡态外推格式：附近一个格点，得边界三个方向上分布函数。边界也碰撞。角点处理。结果好。即是Cavityflow5中的程序改为并行程序。分区的线垂直于X轴。结果好，两核约快1.5倍-Cavity flow parallel program. Non-equilibrium extrapolation scheme: near a lattice point, the boundary of three direction distribution function. The boundary also collision. Corner point processing. Good results. Is the Cavityflow5 program to parallel program. The partition line perpendicular to the X axis. The result is good, two nuclei is about 1.5 times faster
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Size: 5120 |
Author: 媛媛 |
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Description: The ouput is the TE/TM band structure (first five bands) along pricipal
directions (G-X-M-G) of a square-lattice photonic crystal with unit cell
consisting of a substrate of "epb" relative permittivity with circular
rods(holes) of "epa" relative permittivity and radius "r".
Usage is
SharifPWE_BZplot(N,RES,r,epa,epb)
N: N in PWE algorithm (number at which the summations are truncated)
RES: number of the divisions on every side of BZ#1
r: normalized radius of the circle of holes/rods (0<r<0.5)
epa: relative permittivity of holes/rods
epb: relative permittivity of the substrate
Written by Amir Hosseini
for the Course Photonic Crystals
(C) Copyright 2005
School of Electrical Engineering
Sharif University of Technology
All Rights Reserved- The ouput is the TE/TM band structure (first five bands) along pricipal
directions (G-X-M-G) of a square-lattice photonic crystal with unit cell
consisting of a substrate of "epb" relative permittivity with circular
rods(holes) of "epa" relative permittivity and radius "r".
Usage is
SharifPWE_BZplot(N,RES,r,epa,epb)
N: N in PWE algorithm (number at which the summations are truncated)
RES: number of the divisions on every side of BZ#1
r: normalized radius of the circle of holes/rods (0<r<0.5)
epa: relative permittivity of holes/rods
epb: relative permittivity of the substrate
Written by Amir Hosseini
for the Course Photonic Crystals
(C) Copyright 2005
School of Electrical Engineering
Sharif University of Technology
All Rights Reserved
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Size: 2048 |
Author: iran |
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Description: This MATLAB M-file implements the finite-difference time-domain solution of Maxwell s curl equations over three-dimensional Cartesian space lattice comprised of uniform cubic grid cells.
To illustrate the algorithm, an air-filled rectangular cavity resonator is modeled. The length, width, and height of the cavity are 10.0 cm (x-direction), 4.8 cm (y-direction), and 2.0 cm (z-direction), respectively.-This MATLAB M-file implements the finite-difference time-domain solution of Maxwell' s curl equations over three-dimensional Cartesian space lattice comprised of uniform cubic grid cells. To illustrate the algorithm, an air-filled rectangular cavity resonator is modeled. The length, width, and height of the cavity are 10.0 cm (x-direction), 4.8 cm (y-direction), and 2.0 cm (z-direction), respectively.
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Size: 2048 |
Author: 双色 |
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Description: 今有 6 x 6 的棋盘格。其中某些格子已经预先放好了棋子。现在要再放上去一些，使得：每行每列都正好有3颗棋子。
我们希望推算出所有可能的放法。下面的代码就实现了这个功能。-This checkerboard of 6 x 6. Some lattice has been pre-put away a pawn. Recapture up, such that: each row and each column exactly three pieces. We want to figure out all the possible release method. The following code to achieve this functionality.
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Size: 1024 |
Author: 苏萨斯 |
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Description: Windows下通过GDI绘图和读取生成BDF格式的点阵汉字库文件，这种文件常用于Linux X Server. -Lattice Store generate BDF format under Windows GDI drawing and reading files, this file is commonly used in the Linux X Server.
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Size: 153600 |
Author: 耿程新 |
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Description: Here, for convenience, the vector in 2D is represented by a complex number: the real
part represents the x-component and the imaginary part represents the y-component. How to get the
Fourier transform is the key of this program. Here I used the analytical form for the circular cylinder
and used the shift property to get the Fourier transform for more complicated system consisting of
finite number of individual atoms.
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Size: 1024 |
Author: steven |
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Description: 格子手绢
问题描述
久城送给维多利加一块苏格兰格子手绢，可是手绢不小心被咖啡弄脏了，久城不得不负
起清洗的责任。
手绢的格子可以用二维坐标系来描述，手绢左下角坐标为(0,0)，右上角坐标为(N,M)，
也就是说，手绢上一共有N*M个格子。咖啡在手绢上形成了一个圆形的污点，圆心位于整点(
X,Y)处，半径为R。久城想知道，有多少个格子被完全污染了，多少个格子被部分污染了。
这里，某个格子被“完全污染”的意思为该格内被污点覆盖面积＝1，被“部分污染”的意
思为0＜该格内被污点覆盖面积＜1。
输入格式
一行5个整数N,M,X,Y,R。
输出格式
一行两个整数，由一个空格隔开，表示被完全污染的格子数量和被部分污染的格子数量
。
样例输入
2 2 0 0 2
样例输出
1 3
数据范围
对于20 的数据，N,M< 10；
对于60 的数据，N,M< 1000；
对于100 的数据，N,M< 1000000，0< X< N,0< Y< M，R< 1000000.-Plaid handkerchief
Problem description
For a long time the city to Victoria and a piece of Scotland Plaid handkerchief, but the handkerchief was accidentally dirty coffee, for a long time the city had negative
Responsibility for cleaning.
The handkerchief lattice can be used to describe the two-dimensional coordinates of the lower left corner of the handkerchief, coordinates (0,0), the upper right corner coordinates (N, M),
That is to say, a handkerchief and a total of N*M lattice. Coffee has formed a circular spot in a handkerchief, a center at the whole point (
X, Y), the radius is R. For a long time the city wanted to know, how many squares were completely polluted, and how many checks were partly polluted.
Here, a square was completely pollution means the box is spot coverage area 1, is pollution .
The box is for 0 < < 1 spot covered area.
Input format
One line of 5 integers N, M, X, Y, R.
Output format
A line of two integers, separated by a space, that is co
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Size: 1024 |
Author: zzz |
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