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Description: 算术逻辑运算器单元ALU（74LS181）的工作原理。简单运算器的的数据传送通道。验算由74LS181等组合逻辑电路组成的运算功能发生器运算功能。
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Size: 27850 |
Author: 朱旭浩 |
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Description: 算术逻辑运算器单元ALU（74LS181）的工作原理。简单运算器的的数据传送通道。验算由74LS181等组合逻辑电路组成的运算功能发生器运算功能。
-Arithmetic logic operation unit ALU (74LS181) works. Simple arithmetic logic unit of the data transmission channel. 74LS181 checked by the combinational logic circuit, such as computing functions comprising computing function generator.
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Size: 27648 |
Author: 朱旭浩 |
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Description: 数据结构有关复数的实现几次的基地会计法警方开房间 发动机觉得ufnhv-Data structure of the plural base for the realization of a number of accounting method that the police opened the engine room ufnhv
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Size: 65536 |
Author: liguifang |
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Description: 某学校对教师每月工资的计算规定如下：固定工资＋课时补贴。教授的固定工资为5000元，每个课时补贴50元；副教授的固定工资为3000元，每个课时补贴30元；讲师的固定工资为2000元，每个课时补贴20元。定义教师抽象类，派生不同职称的教师类，编写程序求若干个教师的月工资。-Monthly wages of teachers in a school of calculation are as follows: a fixed wage+ hours subsidies. Professor fixed wage of 5000 yuan, 50 yuan subsidy for each class an associate professor of the fixed wage is 3,000 yuan, 30 yuan subsidy for each class lecturer at a fixed wage is 2,000 yuan, 20 yuan subsidy for each class. Define abstract class teachers, derived the title of teachers of different classes, write a program seeking a number of teacher' s monthly salary.
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Size: 1024 |
Author: 王朗 |
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Description: 设计一个有N个进程并发的进程调度程序。
进程调度算法：采用最高优先数优先的调度算法（即把处理机分配给优先数最高的进程）算法。
-Design of a concurrent process, N a process scheduler. The process of scheduling algorithm: The number of priority the highest priority scheduling algorithm (ie the number of processors allocated to the highest priority to the process) algorithm.
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Size: 1024 |
Author: 刘 |
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Description: 编写一个读入一个字符串，把它存入一个链表，并按相反的次序打印的程序-Write a read into a string, put it into a list, press the reverse order printing program
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Size: 10240 |
Author: 陆斌 |
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Description: 自选求根问题，分别用二分法、简单迭代法、埃特金加速收敛法和牛顿迭代法求解其根，然后完成编程作业（注意把同一求根问题的几种不同方法放在一个程序之内）。以下求根问题供参考和选择，也可自行选择其他求根问题：
1．用二分法求方程f(x)=x3-2x-5=0在区间[2 , 3]内的根。
2．方程f(x)=2x3-5x2-19x+42=0在x=3.0附近有根，试写出其三种不同的等价形式以构成三种不同的迭代格式，再用简单迭代法求根，观察这三种迭代是否收敛及收敛的快慢。
3．用牛顿迭代法求方程f(x)=x3+2x2+10x-20=0在区间[1 , 1.5]上的根。
4．Cosx=x在区间[0 ， /2]上的根。
-Numerical calculation method
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Size: 224256 |
Author: 肖潇 |
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Description: 这个有啥作用,我也不大清楚。。。。正在学习中-how to use
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Size: 100352 |
Author: linzifeng |
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Description: /编写一个完整的C语言程序，以单链表为存储结构，对一批学生的成绩进行管理，要求实//现如下功能：
//1.通过键盘输入若干学生的学号、成绩，将数据保存一个单链表中。
//2.查询并输出指定学号的学生成绩。
//3.统计并输出不及格人数。
//4.按从高到低的顺序输出所有学生成绩
-/ Write a complete C language program to a single list for the storage structure, the results of a group of students to manage, requiring real// are the following functions:// 1. Through the keyboard input student ID number of students, performance, data save a single linked list.// 2. Query and output the specified number of school pupils.// 3. Statistics and the number of output does not pass.// 4. According to the order of output from high to low scores for all students
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Size: 1024 |
Author: xiaojiezhanzhu |
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Description: 关于汇编的基础的运行内容，有运行步骤和结果截图。-Compiled to run on the basis of the contents of operation steps and the results have screenshots.
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Size: 125952 |
Author: 黄石 |
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Description: 编写求解几何图形周长、面积的应用程序，要求如下：
1） 几何图形要求至少包含直线、三角形，矩型，圆等类型，计算周长，面积等。
2） 要求能计算两个图形之间的距离
3） 要求能计算两个图形进行布尔运算（即交、并、差）后的面积（可选作）。
4） 必须用到继承、接口、多态和包 -It s good.
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Size: 12288 |
Author: 陈新光 |
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Description: 加上外围的电路连接可以实现数字频率计的功能，其中为4位显示的功能- digital frequency meter function
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Size: 2293760 |
Author: amy |
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Description: matlab上机实验：系统响应及系统稳定性-System response and system stability
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Size: 1024 |
Author: 正正 |
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Description: 、用 DEBUG的基本命令，单步执行P113例4-3的程序，检查每条指令执行后目的地址及有关寄存器的内容。
２、用DEBUG的A命令，键入如下程序段：
MOV BX，8275H
MOV AX，3412H ；双精度数34128275H——AX、BX
ADD BX，92A5H
ADC AX，2F65H ；加上双精度数2F6592A5H
ADD BX，0EAE6H
ADC AX，9C88H ；加上双精度数9C88EAE6H
然后用T命令单步执行，查看每条指令执行后有关寄存器的内容及标志位的变化。
注意：①用A命令时键入的数均为十六进制，故其后的“H”不要键入．
②用T命令不适合执行“INT”指令。
３、学会使用DEBUG中的命令：D、G、E、R、T、A、U，为后面调试运行汇编源程序打下基础。-The basic commands of the DEBUG, the single-step procedures of P113 cases 4-3, check the destination address and the contents of the register after each instruction execution. DEBUG A command, type the following program segment: MOV BX, 8275H MOV AX, 3412H double precision number 34128275H- AX, the BX the ADD the BX 92A5H the ADC AX, 2F65H coupled with double-precision number 2F6592A5H ADD the BX 0EAE6H ADC AX, 9C88H coupled with double-precision number 9C88EAE6H then use the T command steps to view the register content and the change of flag in each instruction is executed. Note: ① the A command, type the number are in hexadecimal, so the subsequent " H" Do not type. ② T command is not suitable for the implementation of the " INT" command. 3, learn how to use the DEBUG command: D, G, E, R, T, A, U,, for later debugging and lay the foundation for running the assembler source.
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Size: 2048 |
Author: 张娟 |
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Description: 8-3编码器代码和实验报告，希望对大家有所帮助，-8-3 encoder code and experimental reports, we want to help,
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Size: 51200 |
Author: 祝德美 |
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Description: 熟悉java平台开发环境；
理解常见古典加密算法：恺撒密码、多字母替代密码、多表替代密码；
理解古典加密技术中的替换技术、置换技术。
-Familiar with the Java platform development environment
Understand the common classical encryption algorithm: Caesar cipher, substitution cipher letters, multi-table substitution cipher
Understand the technology of the classical encryption technology replacement, replacement technology.
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Size: 31744 |
Author: mengmeng |
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Description: 建立一个命令M-文件：求所有的“水仙花数”，所谓“水仙花数”是指一个三位数，其各位数字的立方和等于该数本身。例如，153是一个水仙花数，因为153=13+53+33。-set a shuixian m_file
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Size: 3072 |
Author: 刘利 |
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Description: 读入学生数n和每个学生的课程数a[i],利用可变长参数计算每个学生的平均分-N and the number of students read each student' s course number a [i], calculate the average of each student using a variable-length argument
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Size: 1164288 |
Author: zhujianhui |
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Description: 编译原理实验报告，词法分析，自己看一下吧，开发环境未知，亲。-Report compiler principle experiment, lexical analysis, look at it yourself, the development environment is unknown, pro.
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Size: 22528 |
Author: fanyan |
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