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Description: 邮票问题:设一国家发行n种不同面值的邮票，并且每封信至多允许贴m张邮票，对于给定的m,n值，写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连续区域以及获得这个区域的各种可能面值的集合。如，当 n=4,m=5,若有面值为（1，4，12，21）的四种邮票，则邮资最大的连续区域为1到71。还有其他面值的四种邮票可组成同样大小的区域吗-stamp issue : Let a national issue n different denominations of the stamps and letters each allow up to m stamp affixed, to the m, n, write an algorithm derived from a postage in an increment of the circumstances, may obtain a postage value of the maximum continuous access to this region and regional various denominations could assemble. For example, when n = 4, m = 5, if the values of (1,4,12,21) of the four stamps, postage largest regional consecutive 1-71. There are four other denominations of the stamps can be the same size as the composition of the region? ?
Platform: |
Size: 808 |
Author: 彬 |
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Description: 邮票问题:设一国家发行n种不同面值的邮票，并且每封信至多允许贴m张邮票，对于给定的m,n值，写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连续区域以及获得这个区域的各种可能面值的集合。如，当 n=4,m=5,若有面值为（1，4，12，21）的四种邮票，则邮资最大的连续区域为1到71。还有其他面值的四种邮票可组成同样大小的区域吗-stamp issue : Let a national issue n different denominations of the stamps and letters each allow up to m stamp affixed, to the m, n, write an algorithm derived from a postage in an increment of the circumstances, may obtain a postage value of the maximum continuous access to this region and regional various denominations could assemble. For example, when n = 4, m = 5, if the values of (1,4,12,21) of the four stamps, postage largest regional consecutive 1-71. There are four other denominations of the stamps can be the same size as the composition of the region? ?
Platform: |
Size: 1024 |
Author: 彬 |
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Description: 邮票问题背景：设想一个国家发行n种不同面值的邮票，并假定每封信上至多只允许贴m张邮票，对于给定的m和n值，写一个算法求出从邮资1开始在增量为1的情况下可能获得的邮资值的最大连续区域以及获得此区域的各种可能面值的集合。-Background Stamp: n idea of a national issue of stamps of different denominations, and each letter on the assumption that only allows a maximum of stamps affixed to m, for a given value of m and n, write an algorithm derived from the one started in the incremental postage circumstances for one of the postage value may be the largest continuous region, as well as access to this region, a collection of all possible face value.
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Size: 265216 |
Author: 杨鹏 |
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Description: EDA程序： 将spice网表转化为用于计算电路各种参数所需要的相应稀疏矩阵。-EDA procedures: translate the spice netlist into the corresponding sparse matrix in order to calculate the various parameters of the circuit
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Size: 117760 |
Author: buhaixiang |
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Description: basic stamp program for sumo bot robot kit from paralax
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Size: 3072 |
Author: gligor |
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Description: 连续邮资问题的完整代码，修改了王晓东《计算机算法设计与分析》（第三版）中代码的错误，为使计算y[k]的过程更清楚，添加了一些中间调试代码。-Continuous postage question the integrity of the code, modify the Xiaodong " Computer Algorithm Design and Analysis" (third edition), the error code, for the calculation of y [k] of the process more clear and added some code in the middle of debugging.
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Size: 1024 |
Author: huang |
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Description: basic stamp code-basic stamp code..............
Platform: |
Size: 8192 |
Author: Niranjan |
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Description: Project Time Stamp REALTIME
Platform: |
Size: 1303552 |
Author: smart |
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Description: PDF file stamp maker
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Size: 136192 |
Author: deepak |
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Description: How to Testing ET-STM32 Stamp Board
Thai Version
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Size: 82944 |
Author: dekpri |
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Description: MCUApplications:
This application note presents a program in PBASIC that enables the BASIC Stamp to operate as a simple user-interface terminal.-MCUApplications
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Size: 162816 |
Author: 禾斗人 |
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Description: Delphi开发图章制作程序经典代码Development of the classic Delphi code stamp production process
-Development of the classic Delphi code stamp production process
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Size: 1583104 |
Author: o |
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Description: Board Stamp (PCB) of LPC1768
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Size: 505856 |
Author: Hieu Tran |
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Description: Get currect date/time data, create asm include file to enable date/time stamping of your work. Embed the stamp command ina batch file ahead of the assembler command line.
Platform: |
Size: 19456 |
Author: axlsoft |
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Description: stamp 算法，用于解超大规模电路方程-stamp algrithm, used for solving large ciucuit equation.
Platform: |
Size: 6144 |
Author: wangyancaho |
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Description: 淘宝上购买的小软件，用于水印图章的自动生成，很好用的一款软件-Taobao purchased software for watermark stamp automatically generated, easy to use piece of software
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Size: 2349056 |
Author: 华华 |
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Description: 设投币初始状态为ST0，如果投入一枚五毛硬币为ST1, 如果投入两枚五毛或者投入一枚一元硬币（累计一元）为ST2，如果投入三枚五毛或者一枚五毛和一枚一元（累计一元五角）为ST3，如果投入四枚五毛或者两枚五毛和一枚一元或者两枚一元（累计两元）为ST4，在ST4状态下，如果再次投入一枚五毛硬币，则输出邮票并返回初始状态，如果再次投入一枚一元硬币，则输出邮票并找回五毛同时返回初始状态。-Stamp vending machines
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Size: 4096 |
Author: zhangpei |
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Description: 自己制作一个图章，显示学校的名字，专业，年级等-They produced a stamp, display the name of the school, major, grade etc.
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Size: 1184768 |
Author: 王江 |
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Description: acm题，纪念邮票邮局最近推出了一套纪念邮票，这套邮票共有N张，邮票面值各不相同，按编号顺序为1分，2分，……，N分。小明是个集邮爱好者，他很喜欢这套邮票，可惜现在他身上只有M分，并不够把全套都买下。他希望尽量买，最好刚好花光所有的钱。作为一个集邮爱好者，小明也不想买的邮票编号断断续续，所以小明打算买面值a分至b分的b-a+1张连续的邮票，且总价值刚好为M分。 我们用不同的算法求出所有符合要求的方案，以[a，b]的形式输出。-acm questions, post office recently launched a commemorative set of commemorative stamps, stamps are a total of N sheets, stamps face value varies in numerical order of 1 minute, 2 minutes, ......, N points. Xiao Ming is a stamp collector, he was very fond of the stamps, but now his body is only M points, and not enough to have bought a full set. He hoped that try to buy the best just spend all the money. As a philatelists, Xiao Ming not want to buy stamps numbers off, so Xiao Ming intend to buy a par value b min b-a+1 continuous sheets of stamps, and the total value of M points exactly. We use different algorithms to obtain all eligible programs to [a, b] in the form of output.
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Size: 944128 |
Author: lai |
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Description: 介绍了在LabVIEW中如何将字符串的时间转换为时间变量的方法-Convert string to time stamp labview_
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Size: 39936 |
Author: silver |
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