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Dijkstra

  • Category : AI-NN-PR
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  • Update : 2012-11-26
  • Size : 1kb
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  • Author :腾***
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void ShortestPath_DIJ( Node a ,Status i ,Status v0 ,Status*D ,Status*pre ) { int v,w,j,l=1 Status*final Status min final=(Status*)malloc( sizeof(Status)*i ) for(v=0 v<i v++) { final[v]=FALSE pre[v]=FALSE D[v]=a[v0][v] if(D[v]<10000) pre[v]=v0 }
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Dijkstra.c
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