Probably process is as follows: For every dot e, initial [e] to v = 0, dis [e] = inf Make starting point dis [s] = 0 Each find p, makes v [p] = 0, and dis [p] the smallest Make v [p] = 1 Adjacent to each and p (q), with dis [p]+ distance [p, q] to update the dis [q] Until find v [p] = 0

狄克斯特拉(Dijkstra)最短路径算法.cpp

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