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Description: DEbug 关于制作瑞星杀毒软件密钥盘的源码
MOV BX,200 ;内存基址(0面)
MOV DH,00 ;磁头号00
MOV DL,00 ;驱动器号00(A盘)
MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01)
MOV AH,05 ;格式化磁道
MOV AL,09 ;连续读取9个扇区
INT 13 ;调用13号中断
INT 3
MOV BX,300 ;内存基址(1面)
MOV DH,01 ;磁头号01
MOV DL,00 ;驱动器号00(A盘)
MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01)
MOV AH,05 ;格式化磁道
MOV AL,09 ;连续读取9个扇区
INT 13 ;调用13号中断
INT 20 ;返回dos
初学汇编，请各位多多指教！
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Size: 314 |
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Description: 这文档,是祥细说明了Int 13调用的技术文件.-This document is a note wound calling Int 13 technical papers.
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Size: 29924 |
Author: 李三零 |
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Description: as3.0 模拟爆炸
package
{
import flash.display.BitmapData
import flash.geom.ColorTransform
public class Explosion
{
/*
EXPLOSION PARAMETERS
*/
//-- START VALUES
private const EXPLOSION_RADIUS: int = 24
private const EXPLOSION_MAX_VELOCITY: Number = 2
private const EXPLOSION_MAX_HEAT: int = 2 // causes particles to move up
private const PARTICLE_CHAOTIC_MOVE: Number = .1825
private const PARTICLE_DAMP_MOVE: Number = .99
private const PARTICLE_DAMP_ENERGIE: Number = .99
//-- AMOUNT
private const P_COUNT: int = 3000
private const PCOUNT_EACH_FRAME: int = 100
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Size: 230026 |
Author: mabingru |
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Description: DOS游戏编程中处理Int 13的工具包
Platform: |
Size: 167017 |
Author: xdc |
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Description: DEbug 关于制作瑞星杀毒软件密钥盘的源码 MOV BX,200 ;内存基址(0面) MOV DH,00 ;磁头号00 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 3 MOV BX,300 ;内存基址(1面) MOV DH,01 ;磁头号01 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 20 ;返回dos 初学汇编，请各位多多指教！-Debug on the production of Rising antivirus software key source disk MOV BX, 200 memory base address (0 face) MOV DH, 00 head No. 00 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th interruption INT 3 MOV BX, 300 memory base address (1 side) MOV DH, 01 head No. 01 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th interrupt INT 20 return dos beginner compilation, please exhibitions!
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Description: 使用的是API编程,可格式化、校验和读写特殊扇区。可用作Windows下的磁盘加密。本函数还有以下两个缺点以待改进： 1.本函数还只能读能读 A: 和 B:,即只能对软盘操作 2.不能改变磁盘扇区大小，只能是标准的 512 个字节。 参数说明: command 操作: 0 重置磁盘 2 读扇区 3 写扇区 4 校验磁道 5 格式化磁道 8 得到设备参数 (int 1EH) drive 驱动器 A:=0 B:=1 head 磁头号,范围 0 - 1 track 磁道号,范围 0 - 84 ( 80 - 84 为特殊磁道，通常用来加密 ) sector 扇区号,范围 0 - 255 ( 19 - 255 为非标准扇区编号，通常用来加密) nsectors 每次读或写的扇区数,不能超出每磁道的最大扇区数 buffer 数据写入或读出的缓冲区，大小为 512 个字节 返回值 ( 同 Int 13H ): 0x0 成功 0x1 无效的命令 0x3 磁盘被写保护 0x4 扇区没有找到 0xa 发现坏扇区 0x80 磁盘没有准备好-using the API programming, formatting and testing literacy and special sectors. Windows can be used as a disk encryption. This function has the following two shortcomings to be improved : 1. This function can only be read, read A : and B : that only the right to operate two floppy disks. No change disk sector size, the standard is only 512 bytes. Parameter Description : command operations : 0 Reading 2 replacement disk write Sector Sector 3 4 5 checksum track to be formatted track eight equipment parameters (int 1EH) drive drive A : = 0 B : = 1 head head, range 0-1 track track, the range of 0-84 (80-84 for special track, normally used for encryption) sector sector, the scope of 0-255 (19-255 for a non-standard sector numbers, commonly used encryption) nsectors each read or write in the num
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Size: 38912 |
Author: 李小 |
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Description:
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Size: 10240 |
Author: 安辉 |
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Description: 龙已飞去的屠龙刀,系统关键数据/区MBR,DBR,CMOS-RAM 管理工具,适用Win9X/DOS
,开发工具BC3.1(+Turbo Vision),BIOS Int 13h-exiting the holding, the system key data/MBR District, DBR, CMOS-RAM management tools, application Win9X/DOS, development tools BC3.1 (Turbo Vision), the BIOS Int 13h
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Size: 111616 |
Author: szh |
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Description: 这文档,是祥细说明了Int 13调用的技术文件.-This document is a note wound calling Int 13 technical papers.
Platform: |
Size: 29696 |
Author: 李三零 |
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Description: as3.0 模拟爆炸
package
{
import flash.display.BitmapData
import flash.geom.ColorTransform
public class Explosion
{
/*
EXPLOSION PARAMETERS
*/
//-- START VALUES
private const EXPLOSION_RADIUS: int = 24
private const EXPLOSION_MAX_VELOCITY: Number = 2
private const EXPLOSION_MAX_HEAT: int = 2 // causes particles to move up
private const PARTICLE_CHAOTIC_MOVE: Number = .1825
private const PARTICLE_DAMP_MOVE: Number = .99
private const PARTICLE_DAMP_ENERGIE: Number = .99
//-- AMOUNT
private const P_COUNT: int = 3000
private const PCOUNT_EACH_FRAME: int = 100
-AS3.0 simulated explosive package (import flash.display.BitmapData import flash.geom.ColorTransform public class Explosion (/* EXPLOSION PARAMETERS*///START VALUES private const EXPLOSION_RADIUS: int = 24 private const EXPLOSION_MAX_VELOCITY: Number = 2 private const EXPLOSION_MAX_HEAT : int = 2// causes particles to move up private const PARTICLE_CHAOTIC_MOVE: Number = .1825 private const PARTICLE_DAMP_MOVE: Number = .99 private const PARTICLE_DAMP_ENERGIE: Number = .99// AMOUNT private const P_COUNT: int = 3000 private const PCOUNT_EACH_FRAME: int = 100
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Size: 230400 |
Author: mabingru |
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Description: DOS游戏编程中处理Int 13的工具包-DOS game programming Int 13 deal with the toolkit
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Size: 166912 |
Author: xdc |
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Description: BIOS int 13h功能描述，DOS下编程很值得收藏。-description of the interrupt 13H.
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Size: 8192 |
Author: 彬彬2009 |
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Description: BarcodeX ActiveX控件 能产生几乎所有类型的条形码。它可以和数据源绑定，用于数据库报告。条形码可以导出为位图，元文件，剪贴板等。支持的条形码格式有：EAN-13、 EAN-8、EAN-2、EAN-5、UPC-A、UPC-E、Code39、Code39 Ext、Code93、 Code 128、EAN-128、ISSN、ISBN、Plessey、Code11、Code25、Code25 Int.、Codebar 甚至PDF417 2维条形码-barcode activex
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Size: 1160192 |
Author: KennyYao |
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Description: 基本INT 13H读写磁盘扇区
一、读磁盘
MOV AX,0201H
MOV BX,7C00H
MOV CX,0001H
MOV DX,0080H
INT 13H
INT 3H
二、写磁盘
MOV AX,0301H
MOV BX,7C00H
MOV CX,0001H
MOV DX,0080H
INT 13H
INT 3H
-Partition structure
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Size: 22528 |
Author: 146 |
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Description: 检查闰年的方法
class MyDate
{
private static int[] Months=new int[13]{0,31,28,31,30,31,30,31,31,30,31,30,31}
private int year
private int month
private int day
//公有的方法,对外提供的服务
public MyDate()
{
year=1900
month=1
day=1
}
public MyDate(int year,int m,int d)
{
SetDate(year,m,d)
}
private void SetDate(int y,int m,int d)
{
this.year= CheckYear(y)
this.month = CheckMonth(m
this.day = CheckDay(d)
}-Check the leap year means class MyDate {private static int [] Months = new int [13] {0,31,28,31,30,31,30,31,31,30,31,30,31} private int year private int month private int day // public method to provide the service of external public MyDate () {year = 1900 month = 1 day = 1 } public MyDate (int year, int m, int d) { SetDate (year, m, d) } private void SetDate (int y, int m, int d) {this.year = CheckYear (y) this.month = CheckMonth (m this.day = CheckDay (d) }
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Size: 1024 |
Author: Maple |
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Description: 问题很简单。选择一个进制B，按照该进制将被乘数、乘数、乘积分别转换成十进制。
然后判断等式是否成立。使得等式成立的最小-int alfafl a jalaw jal
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Size: 731136 |
Author: 曹预建 |
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Description: 返回二维数组中的最大元素的位置
public static int[] locationLargest(double[][] a)-The Back the location of the largest element in the two-dimensional array public static int [] locationLargest (double [] [] a)
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Size: 3072 |
Author: kevin |
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Description: 基于JAVA编写一个整数的链表。程序包括对dat文档读取，链表的添加，删除，和完成指定要求。-Write a program, using an IntLinkedList to read in the following file and create a list according to the rules specified. The first number is n = the number of elements to generate. In the example, this is 20. First build a list containing the numbers from 1 to n. The second number is the count of numbers which are to be read in (in this case, 4). Read in those numbers and remove all numbers from the list that are a multiple of those numbers.
20 4
2 3 5 7
In the above case, the program should first generate a list of numbers from 1 to 20:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Then, it should remove all multiples of 2, 3, 5 and 7. Note that this is similar to prime number tests you may have learned but we are actually removing 2, 3, 5 and 7 as well
1 11 13 17 19
There is no guarantee that the numbers will all be prime. For example, the following would be just as legal:
20 3
4 11 99
In which case the output should be:
1 2 3 5 6 7 9 10 13 14 15 17 18 1
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Size: 13312 |
Author: han |
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Description: 一个有限状态机的编程范例
StateMachine包 状态机管理
IStateMachine.as 状态机接口
MyEvent_Control.as 消息管理,状态管理
MyEvent_Single.as 单个事件
Total.as 实现了状态机接口(IStateMachine)的基类,将其理解为抽象类比较好
A.as 继承基类(Total)的状态机,这个才是真正可用的
B.as 同A
Main.as 调用,以及启动
若要使用本状态机
前提:
1.你的基类名字叫basis.as
2.你继承基类的名字static.as
对应:
1.basis.as -- 相当于 Total.as
2.static.as -- 相当于 A.as
类功能:
参考"类说明.txt"
注:
1.管理类为静态类
使用“MyEvent_Control.istanceFun() ”来取到实例
消息部分-公开
-- //供外部调用的 发送消息 send()
状态机部分--公开
-- //绑定一个状态机 add_StateMachine(_idx)
-- //开启状态机 Start_StateMachine(_modo:int=0,_idx=null)
-- //状态更新 stateUpdate(_idx,str)
2.关于全局消息,和局部消息中
-- 使用 "e.sender" 来获取消息的发送者-A state machine programming paradigm StateMachine package management IStateMachine.as state machine interfaces MyEvent_Control.as message management finite state machine, state management MyEvent_Single.as single event Total.as implements a state machine interfaces (IStateMachine) base class, be understood as An abstract class is better A.as inherit the base class (Total) state machine, this is the real available B.as with A Main.as calls, and start to use the state machine premise: a name of your base class You inherit called basis.as 2 corresponds to the base class name static.as:. 1.basis.as- equivalent Total.as 2.static.as- functional equivalent A.as: Refer to " class description txt " Note: 1 static class management class to use." MyEvent_Control.istanceFun () " to get to the instance of the message part- publicly-// for external calls to send a message send () state machine part- publicly-// bind a state machine add_StateMachine (_idx)-// open state machine Star
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Size: 17408 |
Author: 可了 |
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Description: V4L2 internal ioctl interface for Linux v2.13.6.
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Size: 3072 |
Author: tadukin |
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